C.j date KEY ENCRYPTION

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hi , i'm reading c.j date book part 17.5 > data encryption > page 520 > step 4 > i don't know how the result shows ... please forward me to learn this part ... i am in needed ... many thanks

simple text : AS+KI NGFIS HERS+ CATCH +FIRE
key Encryption: ELOIT
step 1) suppose that space=00,A=00, .... , Z=26
REsult of simple text: 0119001109 1407060919 0805181900 0301200308 0006091805
step 2) result of key encryption = 0512091520
step 3)
0119001109 1407060919 0805181900 0301200308 0006091805
0512091520 0512091520 0512091520 0512091520 0512091520
---------- ---------- ---------- ---------- ----------
0604092602 1919152412 1317000720 0813021801 0518180625

here is my problem that how the answer of for exmple 0006091805 and 0512091520 will be 0518180625?

step 4) FDIZB SSOXL MQ+GT HMBRA ERRFY

Posted 17-Oct-13 20:34pm

Lida Zareian

Updated 17-Oct-13 20:56pm

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[no name] 18-Oct-13 2:38am

and how you think we will come to know about the step 4..??

Lida Zareian 18-Oct-13 2:56am

i updated my question

Lida Zareian 18-Oct-13 2:42am

check the book

Lida Zareian 18-Oct-13 2:43am

i edit my writing now

Richard MacCutchan 18-Oct-13 4:01am

You need to contact the author of the book for this question.

Lida Zareian 18-Oct-13 4:41am

how?

Richard MacCutchan 18-Oct-13 6:32am

I have no idea, I don't have a copy of the book.

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