How to compare string in substring with java?

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Hi everybody.
I have simple problem I can't resolve.

Java

String body="example....string...here.."; 
for(int loop=0;loop<body.length()-1;loop++)
{
    String cek1=body.substring(loop, loop+1);
    String cek2=body.substring(loop+1, loop+2);
    if(cek1=="." && cek2==".")
    {
       body=body.substring(0, loop)+body.substring(loop+2, body.length());
       loop=loop-1;			  
    }
}

Very simple but why i can't go to :

Java

if(cek1=="." && cek2==".")
{
   // HERE
    // bla bla bla bla
}

Please help me, I new in android.

Posted 23-Dec-13 0:42am

bagus bujangga

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Comments

Shubhashish_Mandal 23-Dec-13 6:56am

not so clear..

bagus bujangga 23-Dec-13 7:06am

I Never meet cek1="." and cek2="."

Shubhashish_Mandal 24-Dec-13 1:47am

Issue is with the comparison. You have checked whether two objects reference (using == operator) is same instead the value of the object. So to check the value you should use
".".equals(cek1) && ".".equals(cek2)

3 solutions

Solution 1

Hi friend,

I Solved it :) Please mark it as solved and rate it too if you wish :)

Here's the code :

Java

String body = "example....string...here..";

for (int loop = 0; loop < body.length() - 1; loop++)
{
    char cek1 = body.substring(loop, loop+1).charAt(0);
    char cek2 = body.substring(loop+1, loop+2).charAt(0);

    if (cek1 == '.' && cek2 == '.')
    {
        body = body.substring(0, loop) + body.substring(loop+2, body.length());
        loop = loop-1;
    }
}

What I did was converted the single charater String type to a character type and then compare it :)

With Regards
Tushar Srivastava

Posted 23-Dec-13 1:18am

Er. Tushar Srivastava

Solution 2

If I understand your code correctly, you are trying to remove the '.' in a word. But your code is hard to comprehend. You should use regex pattern and matcher to achieve it. See my sample code below. You can find many regex tutorials on the web. I have one article on this here Code Experiment on Integer Validation[^]

package com.peterleow;

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Test01 {
	
	public static void main(String[] args) {
		   
	    String body = "example....string...here..";
	    
	    System.out.println("Before : " + body);
	    
            // regex syntax for one or more '.' 
	    Pattern pattern2Remove = Pattern.compile("\\.+"); 
	    
	    Matcher matcher = pattern2Remove.matcher(body);
	    
	    while(matcher.find())
            {
                 String string2Remove = matcher.group();

                 body = body.replace(string2Remove, "");

                 System.out.println("After : " + body);
            } 
	}
}

Posted 23-Dec-13 4:40am

Peter Leow

Updated 23-Dec-13 4:43am

v2

Comments

Maciej Los 23-Dec-13 11:26am

+5

Peter Leow 23-Dec-13 11:28am

Thank you.

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Xiao Ling · Accepted Answer · 2013-12-23T16:01:00

Solution 3

If you want to compare string, you cannot use

if (cek1 == '.' && cek2 == '.')

you have to use

if (cek1.equals"." && cek2.quals".")

because string is an object. of course, it's fine to use "==" to compare char :)