how to find rootname and root of root name from treeview

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actually i have one treeview.which have 3 levels of node.as like follwing tree structure

Dept
|
--- SubDept
|
------KPI

there are 3 textbox
1.txtDept
2.txtsubdept
3.txtkpi

there are 3 condition:
1.if user click on mainroot node(Dept)
when user click on 1st node i.e dept(Root node),dept name shown into txtdept,and 1st corresponding subdeptname display into txtsubdept and corresponding 1st KPI display into txtkpi

2.if user click on root node(SubDept)
when user click on next Root node i.e subdept,subdept name display into txtsubdept and corresponding 1st KPI display into txtkpi and parent node(Dept name) shown into txtdept.

3.if user click on child node of subdept(KPI)
when user click child node of subdept(KPI),that kpinode name display into txtkpi,and its corresponding parent i.e(SubDept)display into txtsubdept,and parent of parent node name (Dept) display into txtdept

how to handled this three condition?and which event fire for this?

mycode:

private void treeViewKPI_AfterSelect(object sender, TreeViewEventArgs e)
{
TreeNode node;
node = treeViewKPI.SelectedNode;
if (node.TreeView.Nodes.Contains(node))
{
string nodeName;
panelDisplayKPI.Visible = true;
txtDept.Text = node.Text.ToString();
nodeName = node.FirstNode.Text.ToString();
textSubDept.Text = node.FirstNode.Text.ToString();
if (node.FirstNode.Nodes.Count > 0)
{
txtDisplayKPI.Text = node.FirstNode.Nodes[0].Text;
}
else
{
txtDisplayKPI.Text = "";
}
}
else
{

txtDept.Text = node.Parent.Text.ToString();
textSubDept.Text = node.Text.ToString();
if (node.FirstNode.Nodes.Count > 0 || node.FirstNode!=null)
{
txtDisplayKPI.Text = node.FirstNode.Nodes[0].Text;
}
else
{
}
}
btnSave.Enabled = true;
btnDelete.Enabled = true;
}

Posted 31-Dec-13 20:22pm

Gauri Bharde

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BillWoodruff · Answer 1 · 2013-12-31T21:08:00

You can use the 'Level Property of the TreeNode object in the Microsoft TreeView Control to simplify this:

C#

private void treeView1_AfterSelect(object sender, TreeViewEventArgs e)
{
    TreeNode currentNode = e.Node;

    switch (currentNode.Level)
    {
        case 0:
            textBox1.Text = currentNode.Text; // dept
            textBox2.Text = currentNode.Nodes[0].Text; // sub dept
            textBox3.Text = currentNode.Nodes[0].Nodes[0].Text;  // KPI
            break;
        case 1:
            textBox1.Text = currentNode.Parent.Text;
            textBox2.Text = currentNode.Text;
            textBox3.Text = currentNode.Nodes[0].Text;
            break;
        case 2:
            textBox1.Text = currentNode.Parent.Parent.Text;
            textBox2.Text = currentNode.Parent.Text;
            textBox3.Text = currentNode.Text;
            break;
    }
}