How can I create an IntPtr with an Int64?

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4.33/5 (2 votes)

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I am trying to create an IntPtr like this:

VB

Dim pid As New IntPtr(Int64.MaxValue)

The C# equivalent would be something like:

C#

IntPtr pid = new IntPtr(Int64.MaxValue);

I keep getting the error "OverflowException".
How can I make this work?

edit:
This is being compiled with "AnyCPU". It's a device application using .NET CF 2.0; The target device is running Windows Mobile 6.5

Posted 1-Jan-14 23:14pm

seph0r

Updated 1-Jan-14 23:18pm

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Karthik_Mahalingam · Accepted Answer · 2014-01-01T23:34:00

Hi try this..

C#

IntPtr pid = new IntPtr(int.MaxValue);

The IntPtr type is designed to be an integer whose size is platform-specific. That is, an instance of this type is expected to be 32-bits on 32-bit hardware and operating systems, and 64-bits on 64-bit hardware and operating systems.

hope your machine is 32 bit operating system.

reference: intptr[^]

Thomas Daniels · Accepted Answer · 2014-01-01T23:27:00

Solution 1

In the Object Browser of Visual Studio, when you go to IntPtr(long), then you see the following under Exceptions

Object Browser
System.OverflowException: On a 32-bit platform, value is too large or too small to represent as an System.IntPtr.

I guess you are running your application on a 32-bit platform, so you get this error.

Posted 1-Jan-14 23:27pm

Thomas Daniels

Comments

seph0r 2-Jan-14 5:54am

Indeed, its an 32bit device, that caused the error.