how to split a text file basis on its size

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i have to divide a text file in user define strings ..... and if the user ask to divide the text file in 10 parts then every divided string should be of same size (bytes) ......i have

used the substring method in c# but it doesn't fulfill my needs and i am using c#

give me any suggestion or any possible solution .........................................

and i have to do this using c# only

................................................................thanks

Posted 28-Jan-14 20:43pm

Adi5555

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BillWoodruff 29-Jan-14 3:10am

And, it doesn't matter if you chop words into two parts ?

What happens if the length of your data string is not evenly divisible by the chunk size: in that case unless you create a string to hold the "remainder" padded with some character so its size is equal to the chunk size: you will not preserve all the characters in the data string.

Adi5555 29-Jan-14 4:02am

the difference of 1 byte or 2 byte in the size is acceptable but not more than that

BillWoodruff 29-Jan-14 4:05am

Logically, the maximum "remainder" you could have would be chunkSize - 1 in length.

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Sunny_Kumar_ · Answer 1 · 2014-01-28T21:01:00

Solution 1

use this method:

C#

static IEnumerable<string> SplitText(string str, int chunkSize)
{
  if (str.Length < chunkSize)
   {
     return new string[]{str};
   }
   return Enumerable.Range(0, str.Length / chunkSize)
         .Select(i =>
                   ((i * chunkSize) + chunkSize) <= str.Length ?
                   str.Substring(i * chunkSize, chunkSize):
                   str.Substring((i*chunkSize), str.Length-(i*chunkSize))
               );
}

use it like:

C#

string mytext = "Quick brown fox jumps over the lazy dog!123456789";
string[] chunks = SplitText(mytext, 4).ToArray();

HTH !

Posted 28-Jan-14 21:01pm

Sunny_Kumar_

Updated 28-Jan-14 22:24pm

v3

Comments

BillWoodruff 29-Jan-14 3:39am

+4
Nice use of Linq ! The problem with this code is that if the string being "chunked"'s length is not evenly divisible by the chunkSize, characters will be left out.

However, the OP doesn't say what to do in this case.

If you can modify your code to handle (string length) % chunkSize != 0 ... you get a 5.

Sunny_Kumar_ 29-Jan-14 4:25am

thanks for pointing out... modified my answer to handle last chunk of text. Thanks!

BillWoodruff 29-Jan-14 5:21am

+5 :)

Sunny_Kumar_ 29-Jan-14 5:23am

thanks :)

BillWoodruff · Answer 2 · 2014-01-28T22:12:00

Here's an outline of a very plain one step-at-a-time solution:

C#

List<string> chunks = new List<string>();

string mytext = "Quick brown fox jumps over the lazy dog yet we!";

int sLen = mytext.Length;

int chunkSize = 4;

int remainder = sLen % chunkSize;

string pad = "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~";

for (int i = 0; i < sLen; i += chunkSize)
{
    if(i + chunkSize <= sLen)
    {
        chunks.Add(mytext.Substring(i, chunkSize));
    }
    else
    {
        chunks.Add(mytext.Substring(i, remainder) + pad.Substring(0, chunkSize - remainder));
    }
}

In this solution the case that the length of the data string is not evenly divisible by the chunk size is handled by padding the "remainder" characters in the last element in the List with tilde characters (~).

Karthik_Mahalingam · Answer 3 · 2014-01-28T21:45:00

Solution 2

Try this..

C#

int size = 5;

double each = (double) mytext.Length / (double)size;
List<string> lstOut = new List<string> ();
for (int i = 0; i < size; i++)
    lstOut.Add(mytext.Substring(i * (int)each ,(int)each));

Posted 28-Jan-14 21:45pm

Karthik_Mahalingam

Comments

Adi5555 29-Jan-14 3:57am

but u have hard coded the size ...... in my case the size dependce upon the user upload

Karthik_Mahalingam 29-Jan-14 4:11am

yes you can pass any size values,
for testing and demo i have used 5..

BillWoodruff 29-Jan-14 4:04am

All the conversions to double and int are not necessary for a solution here.

how to split a text file basis on its size

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