converting number in C++

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is there any function in C++ to convert a m digit number to n ?
for example :
m = 4, n = 8
input : 1234
output: 00001234

Posted 6-Feb-14 3:38am

Member 10290317

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4 solutions

Solution 1

Use printf to do the job.

If you are looking at m and n being variables in your program, then you will have to send printf a string containing the format you want.

printf("%08d", 1234);

will output 00001234 as you want.

http://www.cplusplus.com/reference/cstdio/printf/[^]

Posted 6-Feb-14 3:52am

David Knechtges

Solution 3

The other 2 answers are fully adequate. I like the streams approach. If you want a general approach using printf() then:

C++

int value=1234;
int width = 8;
printf ("%0*d \n", width, value);

Posted 6-Feb-14 22:10pm

User 59241

Comments

CHill60 7-Feb-14 11:04am

No idea why your solution has been voted down. Possibly because the reader didn't realise that you bave demonstrated the use of a variable width in the printf (as per the OPs post!). Upvoted to balance it out.

[no name] 7-Feb-14 18:04pm

Thanks. As I have sometimes observed there is no point in adding a solution if it does not contribute anything new. I thought my answer did that. I also upvoted both others.

Solution 4

C++

#include <iostream>
#include <iomanip>
#include <conio.h>
using namespace std;
void main()
{
 int m=4, n=8,input;
 cout<<"input a number by "<<m<<" digit:"<<endl;
 cin>>input;
  cout << setfill('0') << setw(n) << 1234 << endl;getch();
}

</conio.h></iomanip></iostream>

Posted 7-Feb-14 5:00am

Karim Pazoki

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CPallini · Accepted Answer · 2014-02-06T21:51:00

Solution 2

You may also use C++ I/O streams for the purpose:

C++

#include <iostream>
#include <iomanip>
using namespace std;
int main()
{
  cout << setfill('0') << setw(8) << 1234 << endl;
}

Posted 6-Feb-14 21:51pm

CPallini