How to find distinct record in join query?

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SQL-Server-2008R2

I am trying to find distinct record by using join query in sql server 2008 r2 but getting an error "Column 'tbl_SalaryInformation.SalaryId' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.
"

And below its my query so please help me and give me better solution for that

SQL

select distinct si.Date, si.SalaryId,er.EmpCode, er.FName from tbl_EmpRegistration er,tbl_SalaryInformation si where er.EmpCode=si.EmpCode and si.PartnerName='Pio' and er.PartnerName='Pio' group by si.Date

Posted 21-Sep-14 23:22pm

Dhananjay32

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Dinesh.V.Kumar 22-Sep-14 5:31am

In order to group by you need to have a aggregate function in the select part of the query.
for eg:
Select si.Date, si.SalaryId,er.EmpCode, er.FName, sum(si.salary) from bl_EmpRegistration er,tbl_SalaryInformation si where er.EmpCode=si.EmpCode and si.PartnerName='Pio' and er.PartnerName='Pio' group by si.Date, si.SalaryId,er.EmpCode, er.FName

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_Asif_ · Answer 1 · 2014-09-21T23:32:00

It seems that you need to improve your SQL skill, Please read google SQL and group by clauses.

Apart from that you can have two solutions.

1. Remove your Group by Clause at all Like this

SQL

select distinct si.Date, si.SalaryId,er.EmpCode, er.FName from tbl_EmpRegistration er,tbl_SalaryInformation si where er.EmpCode=si.EmpCode and si.PartnerName='Pio' and er.PartnerName='Pio';

2. USe Group by with modifications in select clause

SQL

SELECT T.Date, T.MaxSalaryID SalaryId, er.EmpCode, er.FName
FROM
(
SELECT si.Date, si.EmpCode, MAX(si.SalaryId) MAXSalaryID
FROM tbl_SalaryInformation si
Group by si.Date, si.EmpCode
) T INNER JOIN tbl_EmpRegistration er on T.EmpCode = er.EmpCode