help to convert Int to binary Python 3 without using("bin()")

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Hi,

I'm pretty new to programation so I came here for you "pros" to help me fidding out, how to make a program that convert integer(from the user input) to a binary code, without using the bin() function.

Here is what I started to do by myself:

Python

nDecimal = eval(input("entrer un décimal positif :"))
print("Le nombre décimal entrer est:", nDecimal)

#transformation into binairy:


while nDecimal != 1 or 0:
    for i in nDecimal:
        i = nDecimal % len(nDecimal)
        if i > 1 or 0:
            i += 1
        else:
            print("votre nombre", nDecimal, "en binaire est:", i)
            break

Of course that code doesn't work :(. I tried to use the modulo of the user input and add to it 1 until the "nDecimal" is not divisible anymore.

Ps: Sorry for my sh*tty english.

Posted 26-Jan-15 11:37am

Brisken

Updated 26-Jan-15 22:12pm

Richard MacCutchan

v3

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Richard MacCutchan · Accepted Answer · 2015-01-26T22:53:00

To convert a decimal number to its binary equivalent you need to take the remainder of successively dividing by 2, and print in reverse. For example the number 13 is

13 / 2 = 6 rem 1
 6 / 2 = 3 rem 0
 3 / 2 = 1 rem 1
 1 / 2 = 0 rem 1
      binary = 1101

Try

Python

nDecimal = eval(input("entrer un décimal positif :"))
print("Le nombre décimal entrer est:", nDecimal)
nbin=[]
while nDecimal > 0:
    value = int(nDecimal % 2)
    # print (value)
    nDecimal = int(nDecimal / 2)
    nbin.append(value)
nbin.reverse()
print("Le nombre binaire est", end=": ")
for x in nbin:
    print(x, end='')