How to find minimum date from different xml date nodes using xslt

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XML

XSLT

Hi Team,
I created the html file using xml and xslt.
I need minimum date using xslt. here my task is i have one xml file with different nodes like flightList,HotelList,CarList,.... I need to get the lowest date from all nodes(flightList,HotelList,CarList).
I have created application as mentioned below.
My XML File written like this:
----------------------------

<TRSummary>
    <FlightList>
        <TravelDate>28/04/2014</TravelDate>
    </FlightList>
    <FlightList>
        <TravelDate>24/04/2012</TravelDate>
    </FlightList>
    <FlightList>
        <TravelDate>30/04/2013</TravelDate>
    </FlightList>
    <HotelsList>
        <CheckInDate>29/04/2015</CheckInDate>
    </HotelsList>
    <HotelsList>
        <CheckInDate>22/04/2015</CheckInDate>
    </HotelsList>
    <HotelsList>
        <CheckInDate>31/05/2016</CheckInDate>
    </HotelsList>
    <CarList>
        <CarFromDate>29/04/2015</CarFromDate>
    </CarList>
    <CarList>
        <CarFromDate>29/04/2011</CarFromDate>
    </CarList>
    <CarList>
        <CarFromDate>23/04/2015</CarFromDate>
    </CarList>
</TRSummary>

My xml document written like this:
-----------------------------

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt">
    <xsl:output method="xml" indent="yes"/>
    <!--<xsl:template match="TRSummary">-->

        <!--Flight TravelDate Minimum date-->

        <xsl:variable name="Flight">
            <xsl:for-each select="TRSummary/FlightList">
                <xsl:sort select="number(substring(TravelDate, 7, 4))" order="ascending"/>
                <xsl:sort select="number(substring(TravelDate, 3, 2))" order="ascending"/>
                <xsl:sort select="number(substring(TravelDate, 1, 2))" order="ascending"/>
                <xsl:if test="position() = 1">
                    <xsl:value-of select="TravelDate"/>
                </xsl:if>
            </xsl:for-each>
        </xsl:variable>

        <!--Hotel CheckInDate Minimum date-->

        <xsl:variable name="Hotel">
            <xsl:for-each select="TRSummary/HotelsList">
                <xsl:sort select="number(substring(CheckInDate, 7, 4))" order="ascending"/>
                <xsl:sort select="number(substring(CheckInDate, 3, 2))" order="ascending"/>
                <xsl:sort select="number(substring(CheckInDate, 1, 2))" order="ascending"/>

                <xsl:if test="position() = 1">
                    <xsl:value-of select="CheckInDate"/>
                </xsl:if>
            </xsl:for-each>
        </xsl:variable>

        <!--Car CarFromDate Minimum date-->

        <xsl:variable name="Car">
            <xsl:for-each select="TRSummary/CarList">
                <xsl:sort select="number(substring(CarFromDate, 7, 4))" order="ascending"/>
                <xsl:sort select="number(substring(CarFromDate, 3, 2))" order="ascending"/>
                <xsl:sort select="number(substring(CarFromDate, 1, 2))" order="ascending"/>

                <xsl:if test="position() = 1">
                    <xsl:value-of select="CarFromDate"/>
                </xsl:if>
            </xsl:for-each>
        </xsl:variable>

        <xsl:variable name="arrays"  >
            <Item>
                <xsl:value-of select="$Car"/>
            </Item>
            <Item>
                <xsl:value-of select="$Hotel"/>
            </Item>
            <Item>
                <xsl:value-of select="$Flight"/>
            </Item>
        </xsl:variable>
    <xsl:param name="array" select="msxsl:node-set($arrays)"/>
    <xsl:template match="/">
        <xsl:for-each select="TRSummary">
            <xsl:value-of select="$array/Item"/>
        </xsl:for-each>
    </xsl:template>
</xsl:stylesheet>

The above code am getting output :
-----------------------------------

24/04/2012 22/04/2015 29/04/2011


I need output like this:
---------------
29/04/2011

How to get minimum date.
plz guide me ASAP.

Thanks&Regards,
Ramu.