How to show the random number from database without repetition .

Make an array of the IDs and then shuffle the array.
Look at my solution in: playing cards game (make Random 4 groups of Numbers in Main Group)[^] for shuffling.
Present the records in the shuffled order.
Don't re-use a record, once presented.
Shuffle again for the next sequence of records.

[Edit: MTH]
First get an array of the record objects (or just the IDs). Call it orderedData.
Call var shuffledData = Shuffle(orderedData); (see below)
Use the values of shuffledData[0 thru end] in sequence and it will be the record objects (or IDs, as above) in a random order with no repeats.

Code for Shuffle() converted to generic:

private Random rand = new Random();
public static T[] Shuffle<T>(T[] data)
{
  T[] shuffled = new T[data.Length];
  shuffled[0] = data[0];
  for (int i = 1; i < data.Length; i++)
  {
    int j = rand.Next(i + 1);
    if (j != i)
      shuffled[i] = shuffled[j];
    shuffled[j] = data[i];
  }
  return shuffled;
}

[Edit #2: MTH]: I renamed the variable outside of the Shuffle method so there's no confusion about names.