How do I display last two digit only

Question

2.33/5 (2 votes)

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i need to display only last two digit of the value ab12345678, what code will be used to get this out put. i just put if function to make it run, infact i want system read value of X and take it last two digit and display it.

C#

// struct.cs
using System;
struct vu
{
    private int id;
    public int X


      {
        get
        {
            return id;
        }
        set
        {
            if (id < 100)
            id = value;
        }
    }
    public void DisplayX()
    {
        Console.WriteLine("Last Two Digit Of the ID is: {0}", id);
    }
}

class Abc
{
    public static void Main()
    {
        vu ss = new vu ();
        ss.X = ab12345678;
        ss.DisplayX();
    }
}

Posted 27-May-15 4:53am

Mr.IHB

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Comments

F-ES Sitecore 27-May-15 11:01am

Use a combination of id.ToString().Length and id.ToString().Substring, or do it using maths via the % operator.

Maciej Los 27-May-15 11:18am

Do not repost!
http://www.codeproject.com/Questions/995565/How-do-I-get-last-digit-of-the-id?arn=10

2 solutions

Solution 1

Try this:

C#

public void DisplayX()
{
    //Console.WriteLine("Last Two Digit Of the ID is: {0}", id);
    Console.WriteLine("Last Two Digit Of the ID is: {0:D2}", id % 100);
}

Posted 27-May-15 5:01am

Leo Chapiro

Updated 27-May-15 5:16am

v3

Comments

Andy Lanng 27-May-15 11:03am

love it! 5*

Leo Chapiro 27-May-15 12:58pm

Thx Andy :)

Sascha Lefèvre 27-May-15 11:07am

It's clever - but not 100% correct because it will only show one digit for multiples of 100.

Andy Lanng 27-May-15 11:16am

and now it's perfect :Þ

Sergey Alexandrovich Kryukov 27-May-15 12:19pm

"Perfect" would look like a kind of exaggeration. The solution is rather hard-coded...
Please see Solution 2, also not perfect... :-)
—SA

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Sergey Alexandrovich Kryukov · Accepted Answer · 2015-05-27T06:17:00

This is the improved solution, instead of the one which was auto-removed with your next question, due to some abuse reports:

First of all, the notion of decimal or hexadecimal digits is inapplicable to numeric objects, which are always "binary". Therefore, you can represent the numeric value to string and modify it. This is not the best solution in terms of performance, but it is most practical and easy to maintain. It can be something like

C#

static class Something {

    internal static string LastDigitsOfHexNumber(int value, byte numberOfDigits) {
        string result = string.Format(hexFormat, value);
        return result.Remove(0, maxNumberOfDigitsInHexInt - numberOfDigits);
    }

    const int maxNumberOfDigitsInHexInt = sizeof(int) * 2;
    static readonly string hexFormat =
       string.Format("{{0:X{0}}}", maxNumberOfDigitsInHexInt);

}

Note the constant and static readonly members. This is the way to avoid hard-coding of immediate constants 8 and "{0:X8}" and, at the same time, avoiding recalculation of these values on each call. Such techniques look more sophisticated, but they greatly improve maintenance.

Now, I would advise you to avoid both re-posting and self-answering, to avoid abuse reports. Your removed "answer" wasn't correct and wasn't even worse. More essentially, people generally are not really interested to see how you failed to solve some trivial problem and later solved it. It only adds garbage to the site.

Thank you for your understanding.

—SA