How to zip multiple files to a single zip file in ASP.NET C#

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Hi All,

I need your advice on how to create a single zip file which compress multiple files and then send an email with the created file as attached.

I am using DotNetZip library for creating zip files.

I can able send multiple zipped files through email, but I need one zip file for the entire files. Please see the code below,

Thanks in advance!!

What I have tried:

foreach (KeyValuePair<string, byte[]=""> doc in attachmentColl)
{
Attachment attachment;
MemoryStream memoryStream = new MemoryStream();
using (ZipFile zip = new ZipFile())
{
zip.AddEntry(doc.Key + ".xls", doc.Value);
zip.Save(memoryStream);
memoryStream.Position = 0;
attachment = new Attachment(memoryStream, new ContentType("application/zip")) { Name = doc.Key + ".zip" };
}
message.Attachments.Add(attachment);
}
message.To.Add(toAddress);
message.Body = mailbody;
message.IsBodyHtml = true;
SmtpClient smtpClient = new SmtpClient("smtp.XXXXXXXX.net");
smtpClient.Send(message);

Posted 1-Dec-16 23:50pm

DPM20

Updated 2-Dec-16 0:37am

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OriginalGriff 2-Dec-16 6:08am

And? What happens that you didn't expect, or doesn't happen that you did?
Where are you stuck?
What help do you need?

DPM20 2-Dec-16 6:13am

Thanks for your reply.

Posted code will generate an email with multiple zip files as attached but, I need single zip file which compress all the files.

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OriginalGriff · Answer 1 · 2016-12-02T00:37:00

Quote:
Posted code will generate an email with multiple zip files as attached but, I need single zip file which compress all the files.

So...you need us to tell you how to move the zip file creation outside a loop, and fill it inside?

That's the kind of thing a third week student on his first computer course should be able to work out on his own in a couple of minutes...

C#

using (ZipFile zip = new ZipFile())
    {
    foreach (KeyValuePair<string, byte[]> doc in attachmentColl)
        {
        zip.AddEntry(doc.Key + ".xls", doc.Value);
        }
    zip.Save(memoryStream);
    MemoryStream memoryStream = new MemoryStream();
    memoryStream.Position = 0;
    Attachment attachment = new Attachment(memoryStream, new ContentType("application/zip")) { Name = doc.Key + ".zip" };
    message.Attachments.Add(attachment);
    message.To.Add(toAddress);
    message.Body = mailbody;
    message.IsBodyHtml = true;
    SmtpClient smtpClient = new SmtpClient("smtp.XXXXXXXX.net");
    smtpClient.Send(message);
    }