How to ignore the row from array if elements are not in an order

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Hi Ppl,

I have an array as shown below, i would need to ignore the first row as the elements are not in order as 2 and 3... wouldn't want to sort instead ignore the row if its not in order

var cars = [
{year:2016,type:"Volvo"},
{type:"Saab", year:2001},
{type:"BMW", year:2010}]

any suggestions pls?

What I have tried:

i have no idea on how to acheive this,. if one of the element is missing i would tried with ownproperty ... but this has all elements... but it not in an order. experts thoughts pls

Posted 9-Mar-17 15:41pm

Member 12974741

Updated 9-Mar-17 16:27pm

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Peter Leow · Answer 1 · 2017-03-09T16:27:00

Solution 1

There is no need to do that. Each array element is an object with the properties of year and type, their order is of no issue here, you get each object by their array index, e.g.

cars[0]

for the first object. To get the respective properties of the an element, say the 2nd elements,

cars[1].type

and

cars[1].year

Learn JavaScript Objects[^]

Posted 9-Mar-17 16:27pm

Peter Leow

Updated 9-Mar-17 16:28pm

v3

Comments

Karthik_Mahalingam 9-Mar-17 23:14pm

5

Peter Leow 10-Mar-17 0:46am

Thank you, Karthik.