Sorting value closer to zero and print their locations

Question

1.00/5 (1 vote)

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i have an array of float datatype. arr=[-0.05,0.03,0.09,0.1]; now i have written code such that it will display the closest value to zero and their location.
but now i need to do in such a way that all the array values should be in an order closer to zero.
if array index starting from zero.
the output should be like
1. 0.03 location=1
2. -0.05 location=0
3. 0.09 location=2
4. 0.1 location=3

What I have tried:

#include<stdio.h>
int main() 
{
    float array[100], minimum;
    int size, c, location = 1;
 
    printf("Enter the number of elements in array\n");
    scanf("%d",&size);
 
    printf("Enter %d integers\n", size);
 
    for ( c = 0 ; c < size ; c++ )
        scanf("%f", &array[c]);
 
    minimum = array[0];
 
    for ( c = 0 ; c < size ; c++ ) 
    {
	   if(array[c]<0 && minimum<0)
		{
	if ( (-array[c]) < (-minimum ) )
        {
           minimum = array[c];
           location = c+1;
        }	
		}
else if(array[c]<0 && minimum>0)
{
if ( (-array[c]) < (minimum ) )
        {
           minimum = array[c];
           location = c+1;
        }	
}
else if(array[c]>0 && minimum<0)
{
if ( (array[c]) < (-minimum ) )
        {
           minimum = array[c];
           location = c+1;
        }	
}
else{
        if ( array[c] < minimum ) 
        {
           minimum = array[c];
           location = c+1;
        }}
    } 
 
    printf("Minimum element is present at location %d and it's value is %f.\n", location, minimum);
    return 0;
}

Posted 10-Apr-17 1:43am

R!sh!

Updated 10-Apr-17 1:56am

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CPallini · Answer 1 · 2017-04-10T01:47:00

Solution 1

Use the qsort[^] function for the purpose.

Posted 10-Apr-17 1:47am

CPallini

Jochen Arndt · Answer 2 · 2017-04-10T01:56:00

You have to sort the array. Because you need to print out the initial position after sorting you have to store that too. The solution is to use a structure:

C++

typedef struct
{
    int position;
    float value;
} val_struct;

int main()
{
    val_struct array[100];
    /* ... */
    for ( c = 0 ; c < size ; c++ )
    {
        array[c].position = c;
        scanf("%f", &array[c].value);
    }
    /* ... */
}

Now sort the array and print all items as required. Because it seems this is some kind of homework, it will not post a final solution. You can search online for sorting algorithms or use qsort - C++ Reference[^].