I cant understand the logic how the output came

Question

1.00/5 (1 vote)

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C++

#include<stdio.h>  
int main(){  
  int i=1,j=1;//initializing a local variable    

  for(i=1;i<=3;i++){      
    for(j=1;j<=3;j++){    
      printf("%d &d\n",i,j);    
      if(i==2 && j==2){    
        break;//will break loop of j only    
      }    
    }//end of for loop    

  return 0;  
}

What I have tried:

1 1
1 2
1 3
2 1
2 2
3 1
3 2
3 3

Posted 29-Dec-17 1:47am

yaminipra

Updated 30-Dec-17 1:50am

PIEBALDconsult

v2

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3 solutions

Solution 3

You are "break"ing after printing your values. That's the reason it is being printed even when I=2 & j=2.

Posted 30-Dec-17 1:50am

PrafullaVedante

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OriginalGriff · Accepted Answer · 2017-12-29T01:56:00

For starters, lets indent your code so it's more readable:

#include<stdio.h>  
int main()
    {  
    int i=1,j=1;//initializing a local variable    
    for(i=1;i<=3;i++)
        {      
        for(j=1;j<=3;j++)
            {    
            printf("%d &d\n",i,j);    
            if(i==2 && j==2)
                {    
                break;//will break loop of j only    
                }    
            }//end of for loop    
        return 0;  
        }
    }

(I added the last close curly bracket for completeness)
Now you can see what happens: When you break out of the inner loop, the next code the processor sees is

C++

return 0;

so it exits the main function and terminates the application.
Probably, you want the return at the end of the function, outside both loops.

You also need to change this:

printf("%d &d\n",i,j);

To this:

printf("%d %d\n",i,j);

Patrice T · Accepted Answer · 2017-12-29T02:32:00

Use the debugger and see your code execute step by step.

There is a tool that allow you to see what your code is doing, its name is debugger. It is also a great learning tool because it show you reality and you can see which expectation match reality.
When you don't understand what your code is doing or why it does what it does, the answer is debugger.
Use the debugger to see what your code is doing. Just set a breakpoint and see your code performing, the debugger allow you to execute lines 1 by 1 and to inspect variables as it execute.

Debugger - Wikipedia, the free encyclopedia[^]

Mastering Debugging in Visual Studio 2010 - A Beginner's Guide[^]
Basic Debugging with Visual Studio 2010 - YouTube[^]
The debugger is here to show you what your code is doing and your task is to compare with what it should do.
There is no magic in the debugger, it don't find bugs, it just help you to. When the code don't do what is expected, you are close to a bug.

I cant understand the logic how the output came

3 solutions

Solution 1

Solution 3

Solution 2

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