Download any File in Asp.net with c#

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Hi
I am using asp.net 2010. i have upload image, doc.,any type on cdn server .
now i want to download from cdn in such way as when i click on download button then any popup should be open for selectiong location ( where you want to save it.) then this file should be downloaded on that choosen location. any can help me
Thanks & regards

Posted 9-Sep-11 1:12am

gauravrawat

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4 solutions

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Mohd Wasif · Answer 1 · 2011-09-09T01:34:00

Solution 1

C#

string result = Path.GetFileName(path);
       //Response.ContentType = "Document/Docx";
       Response.ContentType = "application/vnd.ms-word";

       Response.AppendHeader("Content-Disposition", "inline; filename=" + result);
       Response.TransmitFile(Server.MapPath(path));
       Response.End();

Posted 9-Sep-11 1:34am

Mohd Wasif

Comments

gauravrawat 9-Sep-11 8:47am

this code not working .
i an downloading from this path:
http://cdn.stukcdn.net/z5b6p5y7/cds/LIPC/Docs/20110907015031-ff81f04c-b576-4e15-b899-9396eea45571.jpg
this give erron on Response.TransmitFile(Server.MapPath(path));
(Exception is"this is not valid virtual path ")

Tejas Vaishnav · Answer 2 · 2011-09-09T01:52:00

Solution 2

This will help you...

http://aspalliance.com/259[^]

http://support.microsoft.com/default.aspx?scid=KB;EN-US;q306654&ID=KB;EN-US;q306654&lex[^]

http://forums.asp.net/t/1265651.aspx/1[^]

Posted 9-Sep-11 1:52am

Tejas Vaishnav

tareqmarji · Answer 3 · 2014-03-16T22:47:00

Preferences oRefrence = new Preferences("UPLOADFOLDERTEMP"); //Class
string filename = oRefrence.VALUE + e.CommandName;
string fileName = string.Empty;
fileName = e.CommandName.Substring(e.CommandName.IndexOf("-_-") + 3);
FileInfo fileinfo = new FileInfo(filename);

if (fileinfo.Exists)
{
Response.Clear();
Response.Charset = "";
Response.AddHeader("Content-Disposition", "attachment; filename=" + fileName);
Response.AddHeader("Content-Length", fileinfo.Length.ToString());
Response.ContentType = "application/octet-stream";
Response.TransmitFile(fileinfo.FullName);
System.Web.HttpContext.Current.ApplicationInstance.CompleteRequest();

}

Member 10437096 · Answer 4 · 2014-04-03T07:47:00

Solution 4

download(file name);
you can download any file.

Posted 3-Apr-14 7:47am

Member 10437096