How to Store the message of midi::CShortMsg?

Question

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C#

void CDemoDlg::OnNoteOn(CPianoCtrl &PianoCtrl, unsigned char NoteId)
{
    midi::CShortMsg ShortMsg(midi::NOTE_ON, 0, NoteId, 127, 0);
    ShortMsg.SendMsg(m_OutDevice);/* How to store this ShortMsg in another variable what should be the type of variable*/

   

}

VB

namespace midi{
.........
class CShortMsg : public CMIDIMsg
{......
 void SendMsg(midi::CMIDIOutDevice &OutDevice);
.......
}

How to store this ShortMsg in another variable what should be the type of variable?
Is it possible to store the message that we are sending to m_OutDevice?

Posted 20-Jan-12 22:15pm

chaiein

Updated 21-Jan-12 0:10am

v5

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Richard MacCutchan · Answer 1 · 2012-01-20T22:40:00

Solution 1

You already have it in a variable: ShortMsg, which is a variable of the class midi::CShortMsg. Perhaps you could try rephrasing your question.

Posted 20-Jan-12 22:40pm

Richard MacCutchan

Comments

chaiein 21-Jan-12 4:53am

struct Records
{

midi::CShortMsg Message;/* this is causing error */
.......

};

when ever
the below code is executed
midi::CShortMsg ShortMsg(midi::NOTE_ON, 0, NoteId, 127, 0);
ShortMsg.SendMsg(m_OutDevice);
i need to store the message in another variable that is in the structure Record.

Richard MacCutchan 21-Jan-12 5:31am

I don't understand; how can this code ever work if CShortMsg is not a class member? Where have you copied this code from, or is midi some class that you have developed yourself?

chaiein 21-Jan-12 5:24am

I can store that message so that i can get the same sound again.
If i am wrong please correct me.

Richard MacCutchan 21-Jan-12 5:33am

Now you have changed the information I just responded to. I still don't understand your problem. Please edit the original question and show the exact code that you have a problem with and explain what the problem is.

chaiein 21-Jan-12 5:39am

what type of variable should i declare for storing the message that is in below code.

midi::CShortMsg ShortMsg(midi::NOTE_ON, 0, NoteId, 127, 0);
ShortMsg.SendMsg(m_OutDevice);

I am getting errors if i create a variable of type midi::CShortMsg;

chaiein 21-Jan-12 5:41am

void CDemoDlg::OnNoteOn(CPianoCtrl &PianoCtrl, unsigned char NoteId)
{
midi::CShortMsg ShortMsg(midi::NOTE_ON, 0, NoteId, 127, 0);
ShortMsg.SendMsg(m_OutDevice);

}

Richard MacCutchan 21-Jan-12 5:59am

What errors are you getting; I cannot guess, nor can I see what is on your screen. Please do as I suggested and edit your original question and put in the exact details of the code and any errors you see.

chaiein 21-Jan-12 6:16am

Richard i have improved the question Please check out

Richard MacCutchan 21-Jan-12 6:21am

And I think my original answer still holds true. The type of variable to hold the information is a midi::CShortMsg object. I do not understand what problem you are having implementing this.

JackDingler · Answer 2 · 2012-01-21T11:16:00

midi::CShortMsg doesn't have a default constructor. So in your struct you'll need to initialize it.

C++

struct Records 
{ 
    midi::CShortMsg Message;

public:
   Records(void);
   Records(unsigned char Command, unsigned char Channel,
            unsigned char Data1, unsigned char Data2, DWORD TimeStamp);
}; 

inline Records::Records(void)
: Message(midi::NOTE_ON, 0, NoteId, 127, 0)
{
}

inline Records::Records(unsigned char Command, unsigned char Channel,
            unsigned char Data1, unsigned char Data2, 
            DWORD TimeStamp)
: Message(Command, Channel, Data1, Data2, TimeStamp)
{
}