how to Pass MultiValues(QueryString) in ImageButton(TemplateField) in GridView?

Question

3.00/5 (1 vote)

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In a Gridview i want to pass 2 paremeters :
PostGroupID and PostGroup_cLanguageID
in Template field which contains ImageButton.
i dont know how pass this 2 values in PostBackUrl of ImageButton?

<asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False" DataSourceID="SqlDataSPostGroup"
BackColor="White" BorderColor="#DEDFDE" BorderStyle="None" BorderWidth="1px"
CellPadding="4" DataKeyNames="PostGroupID" ForeColor="Black" GridLines="Vertical"
Width="100%">
 
<Columns>
                            
    <asp:BoundField DataField="PostGroupCode" HeaderText="کد گروه"         SortExpression="PostGroupCode" />
     <asp:BoundField DataField="ex" HeaderText="مسیر گروه" ReadOnly="True" SortExpression="ex" />
     <asp:TemplateField HeaderText="ساخت زیر گروه">
          <ItemTemplate>
             <asp:ImageButton ID="ImageButton2" runat="server" ImageUrl="~/Post/Images/subItem.gif"
             ToolTip="ساخت زیر گروه" Width="16px" PostBackUrl='<%# Eval("PostGroupID", "~/Post/PostGroups.aspx?PostGroupID={0} , PostGroup_cLanguageID={1}") %>' />
          </ItemTemplate>
     </asp:TemplateField>
 </Columns>
                      
</asp:GridView>

Posted 10-Apr-12 22:57pm

maliheSadat

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3 solutions

Solution 1

You can pass these parameters as command argument..

In code file

C#

private void GridAddressCommandEvent(object sender, GridViewCommandEventArgs e)
     {
         
             switch (e.CommandName)
             {
                 case "ShowDetails":
                     {
                         _objSession["OrderID"] = e.CommandArgument.ToString();
                         System.Web.HttpContext.Current.Response.Redirect("OrderForm.aspx?orerid=_objSession["OrderID"]", true);
                         
                         
                     }
                     break;

             }
         }

IN design you can use this code

XML

<asp:TemplateField HeaderText="OrderId">
                                                              <ItemStyle HorizontalAlign="Center" />
                                                              <ItemTemplate>
                                                                  <asp:LinkButton ID="lnkbtnOrder" Text='<%# Eval("OrderId") %>'   CausesValidation="false" ToolTip="Delete"
                                                                      CommandName="ShowDetails"
                                                                      CommandArgument='<%# Eval("OrderId") %>' runat="server" />

                                                              </ItemTemplate>
                                                          </asp:TemplateField>

In this i am passing one parameter.But with using comma you can pass 2 parameters. and in code behind you can seprate the string.

Posted 10-Apr-12 23:17pm

Anuj Banka

Updated 10-Apr-12 23:19pm

v2

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Reza Ahmadi · Accepted Answer · 2012-04-10T23:17:00

You can use a method in your code behind to generate every URL based on your parameters. Here is a sample:

XML

<asp:TemplateField HeaderText="Image">
    <ItemTemplate>
        <asp:ImageButton ID="ImageButton1" runat="server" ImageUrl="~/RaidLogo.ico" PostBackUrl='<%# GetUrl( Eval("TableSeq"), Eval("StartMounth")) %>' />
    </ItemTemplate>
</asp:TemplateField>

Code behind:

C#

public string GetUrl(object TableSeq, object StartDate)
       {
           return string.Format("Test.aspx?TableSeq={0}&StartDate={1}", TableSeq.ToString(), StartDate.ToString());
       }

Cheers

binson143 · Accepted Answer · 2012-04-10T23:51:00

Solution 3

Use this code:

HTML

PostBackUrl='<%#string.Format("Post/PostGroups.aspx?PostGroupID={0}&PostGroup_cLanguageID={1}",Eval("PostGroupID"),Eval("PostGroup_cLanguageID")) %>'

Posted 10-Apr-12 23:51pm

binson143