linked In sharing code

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HI my prob is this that i have mad e a custom sharing button for linked in but on clicking upon the button it is not posting any url on my linkd in profile...here is my code .. m i missing smethng ?

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<script type="text/javascript">function LinkdIN_click() {u=location.href;t=document.title;window.open('http://www.linkedin.com/shareArticle?mini=true&url=<?php'+encodeURIComponent(u)+'&t='+encodeURIComponent(t),'sharer','toolbar=0,status=0,width=626,height=436,Scrolbar = 1');return false;}</script><a href="http://www.linkedin.com/shareArticle?mini=true&url=<?phpthe_permalink();?>" title="Click to share this post on LinkedIn" target="_blank" onclick = "return LinkdIN_click()">
<img src="<% =ResolveClientUrl("../images/Lin.jpeg")%>" alt="Share on LinkedIn" width="20" height="20" border="0" style="margin-right:2px; vertical-align:middle" /></a>

Posted 17-Apr-12 20:57pm

Taresh Uppal

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Dhanamanikandan 20-Apr-12 4:02am

your code is not clear to identify the issue. align your using improve question.

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Eugene Sadovoi · Answer 1 · 2012-04-20T10:49:00

You could use some spy software to intersept what you are sending to the server. The code looks fine but content of your variables might be incorrect. See what is being sent and compare with what it should be.
Try to hardcode all of the fields of the form to make sure you are sending what server expects and once you are good roll it into dinamically built url.