Parse error: syntax error, unexpected 'else' (T_ELSE) in C:\xampp\htdocs\mlmsoftware\admin\pingeneratesuccess.php on line 48

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if(isset($_POST['pinSend'])){
	
	$userid=$_POST['userid'];
	$pinNo=$_POST['pinNo'];
	
	
	$x=1;
	
	while($x<=$pinNo) {
		
		$pint=pin_generate();
		$pinsql="INSERT INTO `pin_list`(`userid`, `pin`, `pinAmt`, `pinNo`, `status`) VALUES ('$userid', '$pint', '100', '$pinNo', '1')";
		$run=mysqli_query($db,$pinsql);
		
		  $x++;
          ?>

          <script>
		
          alert('E-pin Generated successfully');
          </script>
        <?php

			
	}
	
    }
	
	//Function for pin Generate
	function pin_generate() {
		
		global $db;
		$pint=mt_rand(10000, 9999999);
		$sql="SELECT * FROM pin_list where pin='$pint'";
		$run=mysqli_query($db,$sql);
		if(mysqli_num_rows($run)>0); {
			
			pin_generate();
			
	    }
		else {
			
			return $pint;
		}
		
		    
	}
	
	?>

What I have tried:

i tried but same error occurs i can't understand the error any one help me to solve this issue.

Posted 30-Aug-20 8:33am

adhars

Updated 30-Aug-20 8:52am

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[no name] 5-Jun-22 3:42am

Parse error: syntax error, unexpected 'else' (T_ELSE) in C:\xampp\htdocs\project\admin\select_project.php on line 170

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{

foreach($sql_run as $sql)

{
?>

Student 1*

Roll No*

Email*

Student 2*

Roll No*

Email*

Program

--please Select--

Semester

--please Select--

Session

--please Select--

Project Details

Project Title

About_project

Area

Tools

Other

Supervisor

--please Select--

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Greg Utas · Answer 1 · 2020-08-30T08:47:00

Solution 1

It looks like there is a spurious semicolon in this line:

if(mysqli_num_rows($run)>0); {

Posted 30-Aug-20 8:47am

Greg Utas

Updated 30-Aug-20 8:48am

v2

Patrice T · Answer 2 · 2020-08-30T08:52:00

Solution 2

PHP

if(mysqli_num_rows($run)>0); {
                           ^ remove semicolon here

Posted 30-Aug-20 8:52am

Patrice T