How to remove zero values from a list in Python

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I want to remove zero values from a list in python. I've tried some codes but it still shows the zero values. Here is my list.

In [128]: allData
Out[128]: 
[['Brand', 'Type', 'Release'],
 ['Nissan', 'seDan', '2010'],
 ['Hyundae', 'suv', '2011'],
 ['BMW', 'seDan', '2012'],
 ['Hyun dae', 'seDan', '2012'],
 ['BMW', 'suv', '2012'],
 ['BMW', 'suv', '0']]

The below code what I've tried is a part of the full script.
Please help me to solve the issue.
Thank you.

What I have tried:

import csv
import os

fileToRead = "est1.csv"

f = open(fileToRead, 'r')
reader = csv.reader(f)
allData = list(reader)
totalCols = len(attributes)
totalRows = len(allData)
f.close()

# Add a '0' for each empty cell
for j in range(0,totalCols):
	for i in range(0,totalRows):
		if 0 == len(allData[i][j]):
			allData[i][j] = "0"
# Remove zero value
for j in range(0,totalCols):
	for i in range(0,totalRows):
		list(filter(lambda a: a !="0", allData[i]))

Posted 7-Feb-20 19:19pm

Member 14738587

Updated 19-Aug-20 0:43am

Add a Solution

4 solutions

Solution 3

Hello,
I just saw the solutions posted.

Python is known for the ability to compress number of lines of code and it is certainly the way you write code in C/C++ or java.

You can use the concept of list comprehension - a unique feature of python and very popular among modern age python programmers.

Let's take an example:

say I define a list

>>> a = [1,2,0,3,0,5,6,7,0,10]

Now to remove all '0' in the list, just use "list comprehension" i.e.

>>> [x for x in a if x !=0]
[1, 2, 3, 5, 6, 7, 10]
>>>

Cool right !!

Cheers,
Joydeep

Posted 19-Aug-20 0:43am

Member 14917910

Updated 19-Aug-20 6:11am

v2

Solution 4

Hi, my solution remove everything you don't like in a list as follows, enjoy:

s1 = [2, 5.6, 0,"u", 78, 0, -3.6, 96, "t"]

s2 = [i for i in s1 if type(i) != str]
s1 = [i for i in s2 if type(i) != float]
s2 = [[i for i in s1 if i != 0]]

print(s2, end= " ")
print()

Posted 21-Nov-20 12:38pm

Member 14999330

Updated 21-Nov-20 16:38pm

Solution 2

a=[0,1,2,3,0,0,0,0,5,6,7,8,0,0]
ll=len(a)
i=0
while i<ll:
if="" a[i]="=0:
" del="" a[i]
="" print(a)
="" ll="ll-1
" i="0
" else:
="" print(a)<="" code="">

Posted 21-May-20 4:56am

Member 14839628

Updated 21-May-20 5:06am

v3

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Richard MacCutchan · Accepted Answer · 2020-02-07T22:29:00

Solution 1

You start by replacing 0 by "0" - which is not necessary. Secondly your filter call does not save the resulting list; try:

Python

allData[i] = list(filter(lambda a: a !=0, allData[i]))

Posted 7-Feb-20 22:29pm

Richard MacCutchan

Comments

Member 14738587 9-Feb-20 22:17pm

Thank you so much for your help. It works! Thank you.