Array in r.id.i[I] android

Question

1.00/5 (1 vote)

See more:

TextView[] t = new TextView[8];
t[0] = (EditText)findViewById(R.id.seller1);
t[1] = (EditText)findViewById(R.id.seller2);
t[2] = (EditText)findViewById(R.id.seller3);
t[3] = (EditText)findViewById(R.id.seller4);
t[4] = (EditText)findViewById(R.id.seller5);
t[5] = (EditText)findViewById(R.id.seller6);
t[6] = (EditText)findViewById(R.id.seller7);
t[7] = (EditText)findViewById(R.id.seller8);

And Go On

What I have tried:

t[i] = (EditText)findViewById(R.id.selleri);

repeating many times in my code so i am trying to replace seller1,seller2.... by some sort of array of selleri. So i have try

Java

String[] Seller = {"seller1","seller2","seller3","seller4"};

and replace it in

Java

t[i] = (EditText)findViewById(R.id.seller[i]);

but gives error on seller[i].

Posted 24-Sep-20 5:25am

Vivek Kansal

Updated 5-May-23 22:23pm

Sandeep Mewara

v2

Add a Solution

2 solutions

Add a Solution

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Richard MacCutchan · Answer 1 · 2020-09-24T05:46:00

Solution 1

As you can see from your calls to findViewById, you cannot use strings to reference resources, you must use the actual resource identifiers. So you could try something like:

Java

int[] Sellers = {r.id.seller1, r.id.seller2, r.id.seller3, r.id.seller4, ...};
// and replace it in 
t[i] = (EditText) findViewById(Sellers[i]);

But all of this begs the question: do you really need EditText types for this, or could a List<T> work better?

Posted 24-Sep-20 5:46am

Richard MacCutchan

Updated 24-Sep-20 9:29am

v2

Comments

Vivek Kansal 24-Sep-20 12:47pm

Not working sir. How List<t> can replace EditText? Is there any example?

[no name] 24-Sep-20 16:50pm

I have no idea, you need to think about what you are trying to do and whether your design is the best way of doing it. Go to the Android developer website and look at the documentation, it contains all the information you need.

Sandeep Mewara 24-Sep-20 17:14pm

5! Above suggested code snippet makes sense and should work (array with actual IDs)

Sandeep Mewara · Answer 2 · 2020-09-24T10:31:00

If you have fixed naming convention then code like below would be easier instead of defining an array with all IDs.

Try:

Java

ArrayList<EditText> myList = new ArrayList<EditText>();

// Removed array
String sellerID;
int resourceViewID; 

for (int i = 0; i < 4; i++)
{
   sellerID = "seller" + i;
   resourceViewID = getResources().getIdentifier(sellerID, "id", getPackageName());
   myList.add((EditText)findViewById(resourceViewID);
}

Reference: Java ArrayList[^]

Quote:
The difference between a built-in array and an ArrayList in Java, is that the size of an array cannot be modified (if you want to add or remove elements to/from an array, you have to create a new one).

Array in r.id.i[I] android

2 solutions

Solution 1

Solution 2

Add your solution here

Preview 0

Array in r.id.i[I] android

2 solutions

Solution 1

Solution 2

Add your solution here

Preview 0

Existing Members

...or Join us