Open Form By Click Any Key By KeyBoard At Run Time

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Hello Friends,
I have a mdi main form in which there are some menus. i made a form which i was not show in that menus. i just want to open that form by click and key from keyboard like alt+F6, Ctrl+F6 like something...
so i want to know the code for open that form by click any key. i have already written a 2 line code in keypress event of my main form.
that is....

C#

if (e.KeyChar == 63) // Ctrl + F6
{
  Cotation ct = new Cotation();
  ct.MdiParent = this;
  ct.Show();
}

but it was not working...
what was i doing wrong? Help me for this...
Thanks in advance...

Posted 6-Feb-13 21:05pm

tanisha pandey

Updated 6-Feb-13 21:10pm

Orcun Iyigun

v2

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Ritwesh · Answer 1 · 2013-02-06T21:38:00

Solution 1

Instead of using KeyDown, use KeyUp. It shall work. I have tried it out. The following code snippet should do it.

C#

private void Form1_KeyUp(object sender, KeyEventArgs e)
        {
            if (e.KeyData.ToString().Equals("F6, Control"))
            {
                Cotation ct = new Cotation();
                ct.MdiParent = this;
                ct.Show();
            }
        }

Hope this helps.

Posted 6-Feb-13 21:38pm

Ritwesh

v2

Comments

tanisha pandey 7-Feb-13 3:50am

I tried this but it was stop at the last line of below code.

Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new Login());

this is i wrote in Program.cs to open my log in page.
i can't understand the problem.