XML file split using c#

Question

0.00/5 (No votes)

See more:

XML

XmlDocument xmlDoc = new XmlDocument();
       xmlDoc.Load(@"D:\Prod.xml");

      XmlNode node = xmlDoc.DocumentElement.FirstChild;
      XmlNodeList lstVideos = node.ChildNodes;
      for (int i = 0; i < lstVideos.Count; i++)
       {

           for (int j = 0; j < 3; j++)
           {
               Response.Write("  " + lstVideos[j].InnerText + " ");
           }
           Response.Write("<br>");
       }





xml file is:
 Collapse | Copy Code
<?xml version="1.0"?>
-<DocumentElement>
-<test>
<c0>manas</c0>
<c1>100</c1>
<c2>20</c2>
<c3>33</c3>
<c4>54</c4>
 <c5>65</c5>
<c6>78</c6>
</test>


So i want
like
manas 100 20
manas 33 54
manas 65 78

but coming like
manas 100 20
manas 100 20
manas 100 20
manas 100 20
manas 100 20

Note:
Column numbers are not fixed like 7.
it may be 200, or 100.


plz help me.

Posted 2-Jul-13 21:22pm

connect2manas

Add a Solution

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

thanh_bkhn · Answer 1 · 2013-07-02T22:24:00

Solution 1

I think the loop could be:

C#

String firstItem = lstVideos[0].InnerText;
for (int i = 1; i < lstVideos.Count; i+=2)
       {
           Response.Write(firstItem + " " + lstVideos[i].InnerText + " " + lstVideos[i+1] + " ");
           Response.Write("<br>");
       }

Posted 2-Jul-13 22:24pm

thanh_bkhn

connect2manas · Answer 2 · 2013-07-03T03:28:00

static void GetXMLDocument(int NoOfColumn)
{
string pathToXmlFile = @"D:\Manas\Prod.xml";
DataTable dt = new DataTable();
DataSet ds = new DataSet();
ds.ReadXml(pathToXmlFile);
if (ds.Tables.Count > 0)
{
dt = ds.Tables[0];
if (dt.Rows.Count > 0)
{
for (int i = 0; i < dt.Rows.Count; i++)
{
string names = dt.Rows[i][0].ToString();
if (i > 0) Console.WriteLine(" ");
string lines = names + " ";
for (int j = 1; j < dt.Columns.Count; j++) //Check with no of columns
{
lines += dt.Rows[i][j].ToString() + " ";
if (j % NoOfColumn == 0)//When it is equla with your no of columns upto last stage
{
Console.WriteLine(lines);
lines = names + " ";
}
if (j == dt.Columns.Count - 1 && j % NoOfColumn != 0) //Check at last column
{
Console.WriteLine(lines);
}
}
}
}
} Console.Read();
}

public static void GetXMLValue(int NoOfColumn)
{
XmlDocument xmldoc = new XmlDocument();
xmldoc.Load(@"D:\Manas\ProdNew.xml");

XmlNode nodeCol = xmldoc.DocumentElement.FirstChild;
XmlNode nodeRow = xmldoc.DocumentElement;
XmlNodeList lstRows = nodeRow.ChildNodes;
XmlNodeList lstColumns = nodeCol.ChildNodes;

for ( int i = 0; i < lstRows.Count; i++)
{
string names = lstRows[i].InnerText.ToString();
if (i > 0) Console.WriteLine("");
string lines = names + " ";
for (int j = 1; j {
lines += lstRows[i].InnerText.ToString() + " ";
if (j % NoOfColumn == 0)//When it is equla with your no of columns upto last stage
{
Console.WriteLine(lines);
lines = names + " ";
}
if (j == lstColumns.Count - 1 && j % NoOfColumn != 0) //Check at last column
{
Console.WriteLine(lines);
}
}

}
Console.Read();
}