creating an array in c language

You can use a plain english to C gibberish translator[^] like this: http://cdecl.ridiculousfish.com/?q=declare+bar+as+array+10+of+pointer+to+int[^]

Yes of course. Google will help. Here's a start:

http://www.roseindia.net/c-tutorials/c-array-pointers.shtml[^]

http://www.tutorialspoint.com/cprogramming/c_array_of_pointers.htm[^]

yes it is possible to create an array whose each element is a pointer.

if you have used linked list and character pointers than you might be familiar with the fact
that they makes use of the pointer variables to append the elements

char *ch = "ASDFGH";

here ch will hold the initial position of the string but when you print the whole string
using printf("%s",ch); you will get the complete string.

and suppose you have taken an char *Array[20] it will take 20 elements and each of the element would a pointer .

int main()
{
 char *arr[20];
 char ch = 0;

   while(ch<20)
   {
    arr[ch] = &ch; 
    ch++; 
    printf("%d\n",*arr[ch]);
   }
  getch();
}

[edit]Code block added[/edit]

best option you can search on google get immediately solutions .