Multiply two decimal list values

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1.00/5 (2 votes)

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i have listA,listB Contains same count

C#

List<decimal> listA =new List<decimal>(){1.5M,2.63M,1.25M};

List<decimal> listB =new List<decimal>(){2.5M,0M,1M};

i need multiply listA*listB means

C#

1.5M*2.5M=3.75M
2.63M*0M=OM
1.25M*1M=1.25M

like above i need another List listC
how to do it please help.

i tried with listA[0]*listB[0];
is this correct but i have changed count at runtime

Posted 4-Oct-14 20:10pm

Abhi KA

Updated 4-Oct-14 22:40pm

Afzaal Ahmad Zeeshan

v3

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Zoltán Zörgő 5-Oct-14 2:21am

Quite simple task. What have you tried?

Abhi KA 5-Oct-14 2:38am

just give me suggestion

Sergey Alexandrovich Kryukov 5-Oct-14 2:22am

First of all, where is the definition of List?
It sounds way too trivial, so: what have you tried so far?
—SA

Abhi KA 5-Oct-14 2:26am

sorry i defines list of decimal List<decimal> listA=new List<decimal>(){1.5M,2.63M,1.25M}; but in code not show why ?

Sergey Alexandrovich Kryukov 5-Oct-14 2:41am

I did not ask you how you defined listA. I asked how did you define List (type); and you did not answer me. Not understanding the concept of definition would be a big problem.
—SA

Richard MacCutchan 5-Oct-14 3:30am

Are you saying that you do not know how to iterate through a list?

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BillWoodruff · Answer 1 · 2014-10-04T21:56:00

C#

// uses Linq
using Linq

List<decimal> listA = new List<decimal>() { 1.5M, 2.63M, 1.25M };

List<decimal> listB = new List<decimal>() { 2.5M, 0M, 1M };

List<decimal> listC = listA.Select((dValue, index) => dValue * listB[index]).ToList();

This uses the form of Linq 'Select which automatically creates an index for you [^].

Note that this would fail if ListA had more elements than ListB, but work if ListA had fewer elements than ListB. You may want to put a test in your code to ensure both lists have the same number of elements ?

Andreas Gieriet · Answer 2 · 2014-10-05T00:00:00

Solution 5

How about this:

C#

var listC = new List<decimal>(listA.Zip(listB,(a,b)=>a*b));

Cheers
Andi

Posted 5-Oct-14 0:00am

Andreas Gieriet

Updated 5-Oct-14 0:01am

v2

George Jonsson · Answer 3 · 2014-10-04T21:35:00

One straightforward way to do this implementation is via a loop.
You have to do some validation first to check that both your input lists are of the same length, or if not decide rules for what to do in these cases.
For example:

C#

// Choose the shortest list of the two
// I am assuming here that your list has a Count property. 
// (As Sergey pointed out, the type of list is undefined)
int length = (listA.Count > listB.Count) ? listB.Count : listA.Count;

After this it is a simple matter to create listC and loop through the list items, multiply them and put them in listC.

Jems_007 · Answer 4 · 2014-10-04T21:33:00

Solution 2

Try this :

XML

List<decimal> listA = new List<decimal>() { 1.5M, 2.63M, 1.25M };
List<decimal> listB = new List<decimal>() { 1.5M, 2.63M, 1.25M };
List<decimal> listC = new List<decimal>(); ;
for (Int32 i = 0; i <= listA.Count; i++ )
{
    listC.Add( listA[i] * listB[i]);
}

Posted 4-Oct-14 21:33pm

Jems_007

Multiply two decimal list values

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