InvailidOperationException

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Hello, I have 2 forms in my project: in one the user selects a value from a combobox (form2) and the other one gets the combobox value and uses it(form1).
I start debugging, the form2 (which is called from form1) appears, I select my value and then form1 appears.
Then I get the error"InvailidOperationException was unhandled Object is currently in use elsewhere" from "Program.cs" at

Application.Run(new Form1());

How can I get this error when the form is already open?
How can I resolve it?
This is the strange thing in my code I open form1 only 1 time there's no second one (and I checked my code)
Even stranger: if I delete a part of my code pictureBox1.Image = img; I don't get the error.

Posted 22-Jun-10 1:21am

mostwanted4

Updated 22-Jun-10 3:17am

v3

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Richard MacCutchan · Answer 1 · 2010-06-22T02:16:00

Solution 1

It sounds like you are trying to open Form1 a second time when it is already open. Check your code.

Posted 22-Jun-10 2:16am

Richard MacCutchan

#realJSOP · Answer 2 · 2010-06-22T02:26:00

Solution 2

Instead of using Application.Run to re-run the form, simply call form1.Hide() when Form2 is displayed, and when Form2 closes, call form1.Show() again.

There are a couple of other (similar) ways to manage it, but I'll leave you to find those alternatives on your own.

Posted 22-Jun-10 2:26am

#realJSOP

Jimmanuel · Answer 3 · 2010-06-22T03:31:00

mostwanted4 wrote:
if I delete a part of my code pictureBox1.Image = img;

Is that happening in a background thread or on the UI thread? I've sometimes seen cross thread exceptions like that thrown up to the call to Application.Run(...) in the Main method.

Does the inner exception shed any light on the problem?

If you attach to the unhandled exception handler:

C#

static void Main(string[] args)
{
    AppDomain.CurrentDomain.UnhandledException += new UnhandledExceptionEventHandler(CurrentDomain_UnhandledException);
    //...
}
static void CurrentDomain_UnhandledException(object sender, UnhandledExceptionEventArgs e)
{
    // ...
}

do you get any more useful information?

mostwanted4 · Answer 4 · 2010-06-22T04:22:00

Solution 4

I modified my code a little bit and the I got the error "
Bitmap region is already locked" and I found this which solved all my problems. Anyway thank you for your answers.

Posted 22-Jun-10 4:22am