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thanks for replying.
I am thinking of taking the inputs for the entire packet. Which includes IP addresses, H/W addresses, port nos, flags etc.
should I use only text boxex for all the inputs?
apart from that, textboxes will give rise to strings. how do I convert string to Integer value, which are used to construct the packets?
mahesh
dfgdfgdfgdfg
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No, I would use multiple textboxes. Like another poster said, there are controls for IP address input available on codeproject.
To convert string to integer, use
string myIntString = "5";
int myInteger = int.Parse(myIntString);
Tech, life, family, faith: Give me a visit.
I'm currently blogging about: Hallelujah! It's Ken Jennings!
Judah Himango
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Search the articles here on Code Project for "ip address" and you'll get some useful examples.
www.troschuetz.de
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Hi all,
I developed one windows forms application in C#.But I want to develop licensing scheme for this application based on per machine.I have to generate a unique key based on MacAddress whenever SetUp is installed on Client machine(I know how to retrieve MacAddress).Can anybody have idea in this type of application please reply back with some sample code or approach document.I am very new to this license applications.
Thanks in advance
regards
Sastry.
Sas
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I used following code for one of my buttons for opening .txt files:
openFileDialog1.InitialDirectory = @"C:\Fragmentacija\Fortran\";
openFileDialog1.Title = "Izaberite dokument";
openFileDialog1.Filter = "Izlazni dokument|*.txt|Svi dokumenti (*.*)|*.*";
openFileDialog1.FilterIndex = 1;
openFileDialog1.FileName = "Data" ;
openFileDialog1.CheckFileExists = true;
openFileDialog1.CheckPathExists = true;
if ( openFileDialog1.ShowDialog() != DialogResult.OK )
return;
however, dialog box can see that particular file, but if I try to open it, it won't open (that data.txt file) How can cope with this.
anyone?
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alancatovic wrote:
it won't open (that data.txt file)
What do you mean with that? Are you getting an exception and if so, what does it say?
And please include the code that tries to open the file. It's difficult to help, if you present code that works and tell us that afterwards something goes wrong.
www.troschuetz.de
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The OpenFileDialog only capture the location of the selected file to open the file u have to select the file from the Open dialog box then include this code:
if ( openFileDialog1.ShowDialog() != DialogResult.OK )
System.Diagnostics.Process.Start(openFileDialog1.FileName);
Good Luck!
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private void menuItem9_Click(object sender, System.EventArgs e)
{
openFileDialog1.InitialDirectory = @"C:\Fragmentacija\Fortran\";
openFileDialog1.Title = "Izaberite izlazni dokument";
openFileDialog1.Filter = "Izlazni dokument|*.txt";
openFileDialog1.FilterIndex = 1;
openFileDialog1.FileName = "Data" ;
openFileDialog1.CheckFileExists = true;
openFileDialog1.CheckPathExists = true;
if ( openFileDialog1.ShowDialog() != DialogResult.OK )
System.Diagnostics.Process.Start(openFileDialog1.FileName);
}
this is my code, but again, I can't open data.txt file in notepad
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alancatovic wrote:
if ( openFileDialog1.ShowDialog() != DialogResult.OK )
System.Diagnostics.Process.Start(openFileDialog1.FileName);
If this is what you really have in your code, no wonder it doesn't work!
( next line of code will execute only when selecting file name fail ... now replace != with == )
best regards,
David 'DNH' Nohejl
Never forget: "Stay kul and happy" (I.A.)
Now back to algebra!
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ok, now it works thx
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Oops, i didnt see your "!=", i copy n paste your code n thought it is "==". Sorry ar...
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Hi
I have created a crystal report using c# from a xml file .
Now what I need is that
I would like you to create the same report that I have just finished as a screen program. The screen should look exactly the same as the report does, created from the same xml file. Then there should be a print button on the screen which when clicked should print out the screen.
please can anyone help me to do this.
I am new to c# , so I dont know how to do this. I have a rough idea that I have to do like this
"Use xPath queries to fetch the same data from the XML and display
in the form "
But I need a rough idea of the coding.
Please can u wirte me just how to frame a xpath to fetch data's from a xml with a small example.
so that I can use it to do my program.
santhosh
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Hi All,
I am developing a windows based application using C#. My data is present in the database. One of the fields of database has data in html format (I mean complete source code of html is being stored in that database).
How can I show the same on Windows Form (I want to show proper HTML formated output).
Thanks
Ajay
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You can use the Microsoft Webbrowser ActiveX control on your form.
Just add it to your toolbox (it's a COM control) and drag it onto your form.
Then you can use its Navigate() method to display an HTML page.
mav
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I added form2 (for help topics) to my existing form1. What code should I put under the button which is expected to open that form2. Button is on form1.
please help
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Hi,
You can just create an instance of From2 and call show or ShowDialog method on it.
Form2 frm2 = new Form2();
frm2.Show();
Regards
SGS
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it worked just fine, thank you.
Can i ask you one more thing? How can I make forms unchangeable (that user can't resize form)?
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Simply set the FormBorderStyle property of your Form to a value of your liking.
Regards,
mav
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Hi,
Thank you. Set the FormBorderStyle property to FixedSingle or Fixed3D and set MaximizeBox property to False.
Hope this will help you.
Regards
SGS
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How to not allow user to resize my user control at design-time ? or allow only a particular dimension ? For example, the Textbox control. It allows only resize the control's width if and only if multiline is false; but both dimension if and only if multiline is true.
Thank you
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put this attribute on the property which is used for size:
[Browsable(false)]
-spif2001
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Also check this article out - it will help u out .
http://www.devhood.com/tutorials/tutorial_details.aspx?tutorial_id=319
-spif2001
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Dear spif2001
I mean the user resize my user control at form designer, not from the propertygrid.
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