C / C++ / MFC

toxcct30-Aug-05 23:16

30-Aug-05 23:16

this is done automatically...

int i = 0x57;
ASSERT(i == 87);

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Cedric Moonen30-Aug-05 23:16

Cedric Moonen

30-Aug-05 23:16

An integer is neither an hex or a decimal. It's an integer and that's it ! Now, it's representation (so you will print it on the screen, in a file, ...) can change from hew to decimal. But then, it's not converting an integer but converting a string.

Marc Soleda30-Aug-05 23:23

Marc Soleda

30-Aug-05 23:23

hex, dec, oct are just ways to represent the same integer...

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xiaohe52130-Aug-05 23:41

xiaohe521

30-Aug-05 23:41

yes, the diffrent is the string's represent format, i know how to represent a integer to diffrent format string as

<br />
char *_itoa(<br />
   int value,<br />
   char *string,<br />
   int radix <br />
);

but

int atoi( const char *string );

the function has only one param, no format param

must i write a function to do this?

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toxcct30-Aug-05 23:45

30-Aug-05 23:45

an integer is an integer !!!!

it is stored as a serie of bits in memory, wether you stored an hexa value, an octal one, or a decimal one...

int i = 0x05;
//i contains <code>00000000 00000000 00000000 00000101</code>
 
<hr>
 
int i = \005;
//i contains <code>00000000 00000000 00000000 00000101</code>
 
<hr>
 
int i = 5;
//i contains <code>00000000 00000000 00000000 00000101</code>

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Cedric Moonen30-Aug-05 23:46

Cedric Moonen

30-Aug-05 23:46

Take a look at the sprintf function instead. It will do what you are looking for (and even much more Wink | ;)

).

Hexa:
sprintf(Buffer,"%x",Number);

Decimal:
sprintf(Buffer,"%d",Number);

Marc Soleda31-Aug-05 0:07

Marc Soleda

31-Aug-05 0:07

An integer is an integer and it doesn't matter how you represent it. If you are trying to print it in different representations you may take a look to print flags[^].

Marc Soleda.

... she said you are the perfect stranger she said baby let's keep it like this... Tunnel of Love, Dire Straits.

Nishad S31-Aug-05 0:36

Nishad S

31-Aug-05 0:36

xiaohe521 wrote:
int atoi( const char *string );
the function has only one param, no format param
must i write a function to do this?

I think you are trying to convert a hexadecimal number (which is a string) to an integer. Am I right?

markkuk31-Aug-05 2:04

markkuk

31-Aug-05 2:04

Use the strtol() function to convert numeric strings in various bases into integers.

just like this..

Eytukan31-Aug-05 0:35

Eytukan

31-Aug-05 0:35

How do u convert a Number to an Integer..? Big Grin | :-D

Re: just like this..

toxcct31-Aug-05 1:58

how can i get all the arguments in the va_list

31-Aug-05 1:58

ah... there's now azt least one interresting post on that thread... Big Grin | :-D

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bbluey30-Aug-05 22:53

bbluey

30-Aug-05 22:53

If i have a function myfunc(arg1,arg2,arg3), how can i include them, all, in a va_list variable?
if i use va_start(list, arg1), i won't have arg1 in the list and I cannot change the singnature of the function myfunc.

If I do something like:
list = (va_list)&arg1 it works for types like int, unsigned int, even char*, but not float or double. If one of the args is float, it will store in list a 0 instead of the real value.

please help Unsure | :~

Bob Ciora31-Aug-05 1:22

Bob Ciora

31-Aug-05 1:22

You'd have to include a sizeof(arg1) to account for the stack space used by arg1 and include it. Something like this:

char * ArgPtr = (char *)&arg1 - sizeof(arg1);
if( ArgPtr == (char *)&arg2 )
{
    // Stack growing the other way...
    ArgPtr = (char *)&arg1 + sizeof(arg1);
}

list = (va_list)ArgPtr;

That oughta take into account whatever way the stack grows.

Bob Ciora

bbluey31-Aug-05 2:14

bbluey

31-Aug-05 2:14

Indeed something like that works. Thank you
Now something else troubles me regarding float. I make myself a list of the arguments. the list contains a char*, a float and something. I check them, they are ok. But when i'm tring to right them into a file using vfprintf(file,format,list), instead of my float value i always get a 0.00000

This is too much Big Grin | :-D

Rick York31-Aug-05 7:56

Rick York

31-Aug-05 7:56

You should always use the va_ family of functions to do this.

Anyway, floats are always pushed as doubles in var arg functions. You can check some assembly listings to verify this.

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bbluey31-Aug-05 22:03

bbluey

31-Aug-05 22:03

Thank you for your help.
Indeed when i use va_arg to extract my float the result is corect, so I'll just use a printf Big Grin | :-D

Thanks again

Nassa30-Aug-05 22:52

Nassa

30-Aug-05 22:52

Hi I am trying to connect to SQL server data base using NT authentication from my window service code.

_bstr_t bstrConn = _bstr_t("PROVIDER=SQLOLEDB;SERVER=SD1;DATABASE=MEDICAPT;TRUSTED_CONNECTION=YES;");

m_pConnGenGuiDB->ConnectionString = bstrConn;
m_pConnGenGuiDB->CommandTimeout = 600;
m_pConnGenGuiDB->Open("","","", adConnectUnspecified);

I am getting error Description = Login failed for user 'NT AUTHORITY\SYSTEM'

The same code works fine in any MFC application.
Any body have clue abt that

How to use the struct in the VC.Net?

greenwyx30-Aug-05 22:02

greenwyx

30-Aug-05 22:02

I define a struct like this:
typedef struct
{
float blc;
float sx;
float sy;
}ScreenStruct;

Then in the .h,I define a struct pointer :
ScreenStruct *m_Screen;

At last ,I use it in the .cpp as follows:
m_Screen[0].sx=0;

When I run ,it canont be complied.And the result is that
"miss ; (before *)" or "CView::ScreenStruct miss the storage class or class declaration".

How can I do?Thank u.

toxcct30-Aug-05 22:17

30-Aug-05 22:17

why do you declare m_Screen in the .h ? is it global or as it name tell (but you didn't), it is a class member ?
how is it initialized ?
why don't you declare ScreenStruct as a part of your CWiew class ?

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greenwyx30-Aug-05 22:49

greenwyx

30-Aug-05 22:49

yes.I declare the m_Screen in the Cview.h,which include the Cview class,and the m_Screen[0].cx=0 is in the Cview.cpp.

toxcct30-Aug-05 22:54

30-Aug-05 22:54

you didn't answer my question. how do you initialize m_Screen ?

moreover, i asked if you were declaring the struct ScreenStruct directly into the CWiew derived class...

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