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stop this spam immediately... 
you started a thread some minutes ago. why don't you just follow it instead of starting new ones ? 
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Same question!?
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i have declered a constants in a Header file in following way
const COLORREF RED = RGB(255,0,0);<br />
const COLORREF GREEN = RGB(0,254,0);<br />
const COLORREF BLUE = RGB(0,0,254);
after that i created a message handler like below for each colour
void CNEWWINDOWView::OnGreen()
View.<br />
{<br />
m_colour=GREEN;<br />
Invalidate();<br />
}<br />
now i have wriien in the ondraw as
CString str2.Format("%d",m_colour);<br />
pDC->TextOut(400,10,"COLOUR:"+str2);
i am geting in the window the value of clour of red as 255,for green 65024,
for blue it is 16646144; why it is displaying like this?
-- modified at 8:22 Wednesday 23rd August, 2006
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Because it is a combination of R,G, and B components.
R + (256*G) + (65536*B)
Steve S
Developer for hire
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i want to display the name of the colours than that of the values on window
can u give me the sugetions to how to do it?
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ramanand_bulusu wrote: i want to display the name of the colours than that of the values on window
 
You must be kidding
This is crazy: take two seconds to think about what you said. COLOURREF is just a number that holds a the intensity of each color (R, G and B). There is no colour name associated in any way (and this would be completely absurd, imagine the number of names you need to have).
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what about the method GetRValue();
so ur telling that it is impossible to get the name of the colour on the window with respective to selecting colour?
-- modified at 8:37 Wednesday 23rd August, 2006
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ramanand_bulusu wrote: so ur telling that it is impossible to get the name of the colour on the window
There is no name, COLOURREF is a number. Imagine, there is more than 1 million color combination (make the calculation yourself: 256^256^256). And you want to have a specific name for EACH of those colors ??
What you need to display is the intensity of the three channels, there is no other way to do it if you want color info.
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Cedric Moonen wrote: Imagine, there is more than 1 million color combination (make the calculation yourself: 256^256^256)
256^256^256 is rather bigger than a million - I think you mean 256 * 256 * 256 which is 16.7 million colours 
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Mmh, yes you are right, I mixed the two  (I must be tired)
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name of each color,its
<br />
R=Red<br />
B=Blue<br />
G=Green<br />
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 What kind of answer is that ? 
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WhiteSky wrote: name of each color,its
R=Red
B=Blue
G=Green
i have already declared the names .just see my question before.
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I dont understand your purpose do you want for example cyna/orange/red/purple and....?
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The colourref is code this way: the last significant byte is for red, the middle byte is for green, and so on.
So it is logical that you get these values:
Red:0x0000FFif you translate that in decimal it makes 255.
Green: 0x00FE00 equal to 65024 in decimal
Blue: 0xFE0000 equal to 16646144 in decimal
What did you expect as a result ??
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i expected each value should be 255 onley.ok thanks for ur explanation.
now i want to display the name of that colour than that of values.what i have to do?
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ramanand_bulusu wrote: i expected each value should be 255 onley...now i want to display the name of that colour than that of values.what i have to do?
If the red, green, and blue values are all 255, then the name of that color is white.
"Money talks. When my money starts to talk, I get a bill to shut it up." - Frank
"Judge not by the eye but by the heart." - Native American Proverb
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DavidCrow wrote: If the red, green, and blue values are all 255, then the name of that color is white.
so, how could i solve my problem in order to display the name of the colour
on window
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You have to do it yourself. As I said, there is no name associated with COLOURREF (it is just a number). If you have only Red (0x0000FF), Green (0x00FF00) and Blue (0xFF0000) you can check the color and display the name if it matches:
if (m_Colour&0x0000FF)
{
}
if (m_Colour&0x00FF00)
{
}
if (m_Colour&0xFF0000)
{
}
It's not very elegant but you requirement is... quite 'strange' 
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if( m_colour == GREEN )
{
str2 = "GREEN";
}
.. fill in the rest ..
pDC->TextOut(400,10,"COLOUR:"+str2);
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use %ld in format function , COLORREF is long int .
regards
krishnan
If u can Dream... U can do it
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How to initialize a variable array in a class? it should be static defined?
class{
...
char array[] = "asdhajsdjasgdj";
...
}
9ine
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9ine wrote: How to initialize a variable array in a class?
Use member initialization list.
But in above case varaible is array, so cant use member initialization list. In constructor body you can initialize(re) it.
class A
{
int i;
char array[1];
public:
A():i(0)
{
array[0]=0;
}
};
9ine wrote: it should be static defined?
Not necessary.
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in C++ (by opposition to C# or java), almost all the members should be initialized in the constructor. the only exception are static members, which init should be done outside of the class definition.
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