C#

Control[] controlName = new Control[85];

private void Shuffle()
{
    ArrayList list = new ArrayList(this.controlName);
    Random rand = new Random();
    int j = 0;
    for (int i = 0; i < this.controlName.Length; i++)
    {
        j = rand.Next(list.Count);
        this.controlName[i] = (Control) list[j];
        list.RemoveAt(j);
    }
}

public int GetRandomInt(int[] array, int length)
{
  return array[new Random.Next(0, length)];
}

Belfast Child wrote:

Does return array not return a list of arrays or does the Next method refine it to one number?

public int GetRandomInt(int[] array, int length) <br />
        {<br />
            Random ranNum = new Random();<br />
            return array[ranNum.Next(0, length)]; <br />
        }<br />
<br />
private void button1_Click(object sender, EventArgs e)<br />
        {<br />
            int [] intArray;<br />
            intArray = new int[3] {123, 321, 666};<br />
            int randumNum = GetRandomInt(intArray, 3);<br />
            randomLabel.Text = (randumNum.ToString());<br />
        }

int randumNum = GetRandomInt(intArray, intArray.Length);

Belfast Child wrote:

Error 2 'System.Random.Next()' is a 'method' but is used like a 'type'

Random r = new Random();
r.Next(...)