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You can get the color as an integer value using the ToArgb method, and turn the integer back to a color using the FromArgb method.
---
single minded; short sighted; long gone;
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Hi.
1. Is there any code which will list the installed frameworks on server (asp.net)?
and
2. How can I list all installed browsers on system?
Thanks.
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write code to
1.Listout the directories existing in C:\WINDOWS\Microsoft.NET\Framework
2.Check the folder name starts with small v
3.Parse the folder name and take the version.
I know this is a shortcut way of taking the versions. But I dont know how to take it in other way.
Regards,
Sylvester G
Senior Software Engineer
Xoriant Solutions
sylvester_g_m@yahoo.com
Score it if you like my post
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Thanks for reply.
Do you think this will work on server since I don't know which letter represents system partition and since I am surely restricted to read Windows folder on server?
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I saw that article, but uses registry.
I don't think that will work either.
I know that I can see fw version by making an error and then fw version will be displayed, but that isn't very good approach.
Thanks for reply.
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Hi.
How can I use a dataview(or any other object that can I edit template it) with paging ?
Gridview has paging but I can't edit template it!
Best wishes
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You can use datagridview for paging and editing purpose also.
Sathesh Pandian
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I am having problems passing a value of a boundfield in a gridview to a javascript function. My code is below please help. The hyperlink is linking to a javascript function.
<asp:gridview id="gd_seop" runat="server" width="100%" borderwidth="0px"
="" cellpadding="0">
<alternatingrowstyle backcolor="LightCyan">
<columns>
<asp:hyperlinkfield datatextfield="Name" headertext="Offender Name" navigateurl="javascript:showSexDetail(key)"
="" text="Name">
<asp:boundfield datafield="type" headertext="Type" sortexpression="type">
<asp:boundfield datafield="key" insertvisible="False" visible="False">
This is the javascript
function showSexDetail(sKey){
var winSexDetail
winSexDetail = window.open("http://gisims2.miamidade.gov/MyNeighborhood/sex_detail.asp?case="+sKey, "SexDetail", "width=250,height=300,scrollbars=1,resizable=1,toolbar=0,menubar=1");
winSexDetail.focus();
}
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Can you give more details to your problem?
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I've dropped a GridView onto a page and I'm assigning table to the DataSource property during the Page_Load. I've tweaked the properties to add the Edit and Delete buttons, and I've added the event handlers that ASP.NET screams about if they are missing. However, the end result is, the underyling DataTable is not being updated. What should RowUpdating do? Is there something I need to do beyond what I've done?
Marc
Thyme In The CountryInteracxPeople are just notoriously impossible. --DavidCrow
There's NO excuse for not commenting your code. -- John Simmons / outlaw programmer
People who say that they will refactor their code later to make it "good" don't understand refactoring, nor the art and craft of programming. -- Josh Smith
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Marc,
I have had the best luck with the Gridview when I have used a sqldatasource or an objectdatasource. In those cases you set up what the update / delete / insert methods are and then the gridview calls those methods.
It sounds like you are expecting the gridview to act more like the windows datagrid control. I don't believe it can work that way. I haven't actually tried with a grid view to set the datasource directly, but since the state of the datasource has to be re newed each page_load that could be the problem. If you are always reloading your datatable it might be overwriting any changes you may have made.
Back when I was still using .net 1.1 and a Datagrid I had an ItemCommand event that I used to figure out if I was Insert / update or deleting a row. There was a lot of manual code that was based off the button.CommandName. Anyway, I would suggest using the sqldatasource or objectdatasource if that is an option for you. I wrote and article using the objectdatasource that may be of some help to you.
http://www.codeproject.com/useritems/GridViewObjectDataSource.asp[^]
Anyway, hope that helps.
Ben
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Hi Ben,
Thanks for the feedback. I was putting the data source into a session so I'm constantly reloading it, but yes, because I'm not assigning the data source at design time, I think it's making life more difficult. The designer lets you templatize the columns, which appears to be necessary to get at the underlying data when editing a cell. I found this[^] article to be very helpful with regards to dynamic template generation. Finally the thing is working.
Thanks again for you response and your article link. 
Marc
Thyme In The CountryInteracxPeople are just notoriously impossible. --DavidCrow
There's NO excuse for not commenting your code. -- John Simmons / outlaw programmer
People who say that they will refactor their code later to make it "good" don't understand refactoring, nor the art and craft of programming. -- Josh Smith
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Dear Sirs,
I need to generate a unique random 12 digit number. the number should be unique even if the app gets restarted. could any one help me out...
Thanking you
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If you are using .net 2.0 you have some good options. If not then it will be harder to find something that is solid. Here is the .net 2.0 code right out of microsoft help:
The following example creates a random sequence 100 bytes long and stores it in random.
Visual Basic Copy Code
Dim random() As Byte = New Byte(100) {}
'RNGCryptoServiceProvider is an implementation of an RNG
Dim rng As New RNGCryptoServiceProvider()
rng.GetBytes(random) ' bytes in random are now random
C# Copy Code
byte[] random = new Byte[100];
//RNGCryptoServiceProvider is an implementation of a random number generator.
RNGCryptoServiceProvider rng = new RNGCryptoServiceProvider();
rng.GetBytes(random); // The array is now filled with cryptographically strong random bytes.
Here is the link to this help page:
ms-help://MS.VSCC.v80/MS.MSDN.v80/MS.NETDEVFX.v20.en/cpref11/html/M_System_Security_Cryptography_RandomNumberGenerator_GetBytes_1_f0697ec3.htm
Hope that helps.
Ben
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thanks for your reply.
do i've to add any reference for above code.
Ram
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Here is the namespace you need to reference:
System.Security.Cryptography
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thanks a lot kubben....
its al for my college project. I'm learning and implementing...
Bye...
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You can't produce both a unique and random number. By definition a random number cannot be unique.
Guids are nice but are not really random but they are usually unique.
The random class provides nice randoms numbers.
The most unique solution would be to persist the number and increment it when you need a new one.
File Not Found
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great. This is good solution. I agreed. Giving score for you
Regards,
Sylvester G
Senior Software Engineer
Xoriant Solutions
sylvester_g_m@yahoo.com
Score it if you like my post
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use "Guid" class to generate unique number
Thomas
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Thanks all for ur replies...
Could you help me how to use GUID
Ram
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System.GUID.NewGuid().ToString()
Thomas
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thank you very much thomas...
actually i'm doing my college project(learning and implementing). i'll msg you after implementing. Bye...
Ram
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If you have any doubt you can mail me. I am glad to help you. Have a nice day!!!
Thomas
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