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Hi,
we can sort the data grid on column. i saw this few days back in one article.
you have tp set the AllowSorting property of the DataGrid to True. This property changes all of the column header text to hyperlinks. A click on the header text hyperlink causes a post-back and a call to the OnSortCommand event handler.
In datagrid control creation u have to set these properties:
AllowSorting as "True" and OnsortCommand as "SortCommand_OnClick"
In the OnSortCommand event handler you simply need to specify how the data should be sorted, recreate the data source and bind the data to the DataGrid. Currently creating the data source and the data binding are done in the BindData() method, so really all you need to do is specify how the data should be sorted before calling the BindData() method. In other words, redefine the SQL statement. Since the SQL statement is a page-level variable you have access to it in the OnSortCommand event handler.
u can write the OnSortCommand event handler.
\\ Sub SortCommand_OnClick(Source As Object, E As DataGridSortCommandEventArgs)
_sqlStmt = _sqlStmt & " ORDER BY " & E.SortExpression
BindData()
End Sub \\
hope this will give you some idea.
Thanks,
Rahithi Sharma
If you look at what you do not have in life, you don't have anything,
If you look at what you have in life, you have everything... "
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1.Hi pls place u r connection string in place of my con string.
2.<asp:datagrid id="DataGrid1" runat="server" allowsorting="True" pagesize="5">
<pagerstyle mode="NumericPages">
3.paste this code in codebehind..
imports system.data.sqlclient
Dim conObj As New SqlConnection
Dim adpObj As New SqlDataAdapter
Dim dsObj As New DataSet
Dim sort As String
Private Sub Page_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
If Not Page.IsPostBack Then
bindGrid()
If sort = "" Then
sort = "name"
End If
End If
End Sub
Sub bindGrid()
Try
conObj = New SqlConnection("Data Source=B4B-2F-323-CK26;user id=sa;password=sa;Database=TEST")
conObj.Open()
adpObj = New SqlDataAdapter("SELECT * FROM Login", conObj)
adpObj.Fill(dsObj, "Login")
Dim dt As DataTable = dsObj.Tables("Login")
Dim dv As DataView = New DataView(dt)
dv.Sort = sort
DataGrid1.DataSource = dv
DataGrid1.DataBind()
Catch ex As Exception
Response.Write(ex.ToString())
End Try
End Sub
Private Sub DataGrid1_SortCommand(ByVal source As Object, ByVal e As System.Web.UI.WebControls.DataGridSortCommandEventArgs) Handles DataGrid1.SortCommand
sort = e.SortExpression
bindGrid()
End Sub
End Class
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Hi there
I have developed a web application. But I don't know how to deploy it on server.
If i try publishing it or copy the files and pasting it in the wwwroot It' is giving an error.
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V
XML Parsing Error: not well-formed
Location: http://localhost/test/Default.aspx
Line Number 1, Column 2:<%@ page language="C#" autoeventwireup="true" inherits="_Default, App_Web_qvmriy24" %>
-^
Please help me out .
And thanx for the help in advance..
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Does the server have .NET installed ?
Christian Graus - Microsoft MVP - C++
Metal Musings - Rex and my new metal blog
"I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum )
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Yeah!
I have Visual Studio 2005 Installed on my system.
So that means i have the .Net runtime too.
-- modified at 13:58 Saturday 24th March, 2007
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The application is running fine in the asp server.
i.e when i debug it from the VS environment.
Please help;
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It looks to me like it is trying to interpret the .ASPX file extension as an XML file type.
If I were you, I would check the IIS configuration to make sure that it has the .ASPX file extension assigned so that it is handled by ASP.NET.
Do you know how to check the document types assigned to file extensions on IIS?
----Greg Stevens
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Hi thanks for the help,
But I have no idea, How we check the configuration of IIS.
I would really appreciate you help.
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Hi,
I have hosted two application sites on two different servers. both the sites are based on windows authentication.
Is there any method by which i can send the credentials used by one site to the other site? so that it will not prompt for the windows useid and password while accessing thr second site from the same window.
( both the sites are using same domain for authenticating users)
need help from an expert...
Regards
Vaibhav Vartak
-- modified at 5:38 Sunday 25th March, 2007
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I have a page which has some frames. After processing one
of the pages I want to redirect to another frameset.
However, when I use Response.Redirect I end up with a
frameset with the frameset rather than just the new
frameset.
I have had to resort to using Javascript to do this but
I'd prefer to use the server.
Any ideas ho to do this?
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Hi,
I have a datagrid which displays few records on page load itself!
Now, there is an add record option where the user could add a new record!
The fucntionality is written in the btn event where the new data should be updated in the database!
This task is succesffully completed, however the datagrid doesnt show the new record, it shows the new records only after the next page load!
Is there a way that on btn click itself the datagrid shows the new inserted records
Gautham
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You actually should be adding records to the datatable, so after you have acceptedchanges you need to rebind the datagrid to the datatable or dataview.
Hope that helps.
Ben
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Thanks!
Apart from that is there any other way ?
Like re-loading only the datagrid with the latest records!!!
Gautham
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There isn't any way I know of doing that. This issue is that the pageload event happens before your button click event. So you don't need to do the same code as you do in the page load you just need a datagrid.databind()
Ben
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Is the issue simply that you don't want to have the ugliness of re-loading the entire page? If so, I can think of two options:
1. Put just the datagrid, all by itself, as a document that gets loaded into a little IFRAME with no scrollbars. Then, have whatever event adds the recordset also reload the page inside the IFRAME, and it will re-read the data from the database and therefore refresh with the new record.
2. You could use AJAX to accomplish basically the same thing as above, with no IFRAME. If you know the basics of the AJAX approach: use the XMLHTTP object to call a document that both adds a record to your database table and returns the HTML for a new datagrid object, then when the responsetext is returned, replace the existing datagrid HTML with the responseText.
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This is Only Problem with Binding your Data with DataGrid..
After adding a new Record Simply call DataGrid binding method..
Then u will not get this problem again..
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hello am using ASP.NET 2.0
and I have following problem :-
I added to page TreeView add i added nodes to it..
and I added link to page <a href>
I want when User click or select node , href=get the value of selected node and redirect to link here is the sample of my problem
:---
<form id="form1" runat="server">
<a href="<% Response.Write( TreeView1.SelectedNode.Value); %>">
<asp:TreeView ID="TreeView1" runat="server" Style="left: 157px; position: relative;
top: 84px" OnSelectedNodeChanged="TreeView1_SelectedNodeChanged" >
<Nodes>
<asp:TreeNode Selected="True" Text="Yahoo" Value="http://www.yahoo.com"></asp:TreeNode>
<asp:TreeNode Text="Google" Value="http://www.Google.com"></asp:TreeNode>
</Nodes>
</asp:TreeView>
</a>
</form>
.......
why its not work or is that possible
or is there any other way to do that without server code like :-
<i>Response.Write(TreeView1.SelectedNode.value)</i>
thanks
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Hi there..
I created one web application and i want to give version for that for future uses. Because it's also having some enhancements. Please help and mention the formats. 1.0.0.0 means wat's the meaning for 1, 0, 0 and 0.
Regards n Thks
Sam.M
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I would guess that you are using the assemblyInfo page to set up the version.
The version is set up as Major, Minor, build, revision.
Hope that helps.
Ben
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MAJOR:MINOR:BUILD:RIVISON
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Can U please tell, how to compare the different versions.
Regards n Thks
Sam.M
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I have an adRotator control on my webpage.
Now, I want my ads get changed after every 3seconds without clicking refresh button.
Hoping a soon reply
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You can use the refresh attribute!
In your html code for the page you can include the following1
Gautham
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I tried this before, but it didnt work.
<meta http-equiv="refresh" content="3" />
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