Visual Basic

Run-time error 6:<br />
<br />
overflow

Private Sub Form_Load()<br />
mStart = Timer<br />
<br />
'Set up the listview<br />
    ListView1.View = lvwReport<br />
    ListView1.ColumnHeaders.Add , , "Artist"<br />
    ListView1.ColumnHeaders.Add , , "Name"<br />
    ListView1.ColumnHeaders.Add , , "Image"<br />
    ListView1.ColumnHeaders.Add , , "Rating"<br />
    'ListView1.ColumnHeaders.Add , , "Song ID"<br />
    ListView1.ColumnHeaders.Add , , "Total Votes"<br />
    ListView1.ColumnHeaders.Add , , "Page"<br />
    ListView1.ColumnHeaders.Add , , "Referrer"<br />
    ListView1.ColumnHeaders.Add , , "pageWindowName"<br />
    <br />
    <br />
    Timer1.Interval = 1000 ' <-- 10 seconds<br />
    Timer1.Enabled = True<br />
    <br />
<br />
End Sub<br />
<br />
Private Sub Timer1_Timer()<br />
<br />
ListView1.ListItems(1).ListSubItems(4).Text = Format(TimeSerial(0, 0, CLng(Timer - mStart)), "hh:nn:ss")<br />
<br />
End Sub

Dim x As New TimeSpan(0, 0, 0, 0, milliseconds)
Console.WriteLine("Minutes: " & x.Minutes)
Console.WriteLine("Seconds: " & x.Seconds)

CPallini wrote:

Of course we don't care about rounding...

Dave Kreskowiak wrote:

So what's the point of all this? Are you trying to round down to the next lower integer, be it a positive or negative value? -9 is lower than -8.12 for example.

CleaKO wrote:

It would appear that it always rounds to the number lower not closer to zero so -8.12 goes to -9 whereas 20.8 goes to 20. That seems like a bug to me.

CInt(Csng("-8.62") + 0.5)

Int(Csng("-8.62") + 0.5)

Dave Kreskowiak wrote:

Why? The answer is in the documentation:
Int, Fix Functions[^]
Both Int and Fix remove the fractional part of a number and return the resulting integer value.

The difference between Int and Fix is that if the number is negative, Int returns the first negative integer less than or equal to that number, whereas Fix returns the first negative integer greater than or equal to that number. For example, Int converts -8.4 to -9, and Fix converts -8.4 to -8.


Cint()[^]
CInt differs from the Fix and Int functions, which truncate, rather than round, the fractional part of a number. When the fractional part is exactly 0.5, the CInt function always rounds it to the nearest even number. For example, 0.5 rounds to 0, and 1.5 rounds to 2.

Under VB.NET, the CInt and Convert.ToInt32() methods follow the old VB6 CInt function. You can still use the original VB6 code VB.NET, the Int function IS still there.

Int() -> Math.Floor()<br />
Fix() -> Math.Ceiling()<br />
Round() -> Math.Round()<br />
CSng() -> Convert.ToSingle()<br />
CLng() -> Convert.ToInt32()

Irshadt wrote:

I used the following code to crack Caesar Cipher code where the key is unknown. I have written the following code and is it not working. I want it done in access. Plz Plz help me.

Irshadt wrote:

Please be kind enough to write me a code.