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Yeah....you're just trying to drag me into this, huh? 
"Posting a VB.NET question in the C++ forum will end in tears." Chris Maunder
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Was it a joke or anything. No doubt my total VC experience and total experience is 1.5 years , and Basically I am Mechanical Engineer, but right now I am developing
FingurePrint Identification Server For ATM Parallel to Main Switch for Identification
Aplab India,
Near CheckNaka,
Thane(W),
Maharshtra
India -400604.
I am putting in joke to bypass from main discussion.
|| ART OF LIVING ||
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I am not that master of VC ,but I have to work on very higher end.
I need to show somehow how many atms ,which all atms are currently running.
Doubt is lack of Life force , Answers cannot satify doubt Only Art Of Living Can Solve www.artofliving.org
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shivditya wrote: It crashes at ::GetWindowRect Of groupbox in which I was planning to show the running threads.
"show the running threads" what does that mean? Show them how?
If you just want to display some text put a static control in side the GroupBox control and then SetWindowText on the static control.
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No not like that.
Just like bar graph
I said Group Box Because ,I Just kept groupbox to have some border around
Graph. And I was taking its rect because I was willing to have some
Base coordinates.Which ATM is running ,graph line will be shown for it on y axis.
And ATMs will be on X axis.
|| ART OF LIVING ||
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shivditya wrote: Just like bar graph
Ok then you definitely don't want to draw that on a dialog that has other controls on it. You want to make your own window and draw the graph in there then that window is placed on the dialog as a child like other controls are. If you are using MFC you just derive from CWnd then in the dialog you setup the window as a child using whats called "subclass"ing.
Have you looked at the C++ articles here on CodeProject. I would imagine there are some that walk you through all of this. There is probably even a article with code that will draw the bar graph for you.
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Thanks I will Search for it.
Conclusion
1) Drawing on dialog is not so easy.
2) Subclassing will help // I dont
3) Can diretly add classes which are already developed.
Will you please redirect me to what exactly you mean by placing child window on dialog.
class CDerived : public CMyMainDialog
{
--------
};
CMyMainDialog cm = new CDerived()
cm.Domodal();
|| ART OF LIVING ||
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shivditya wrote: Will you please redirect me to what exactly you mean by placing child window on dialog.
It's called subclassing and you should find tons of articles here on CodeProject in the C++ and/or MFC categories that will help in this subject.
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shivditya wrote: Conclusion
1) Drawing on dialog is not so easy.
2) Subclassing will help // I dont
3) Can diretly add classes which are already developed.
1) Drawing on a dialog is just as easy as drawing on any window. It's just not a good solution
beyond maybe drawing a custom background.
2) You're using MFC - the subclassing is done for you if you use CWnd as a base class.
shivditya wrote: what exactly you mean by placing child window on dialog.
Every control on your dialog is already a child window of the dialog. It seems logical, then, if
you need an area of the dialog to draw in then you should use a child window to do so.
You can place your child window on the dialog just like you'd use a child window anywhere -
1) Implement the window class, or use an existing window class, perhaps 3rd-party code
2) Create a child window object of that class
3) Create the Windows object (HWND) for the window object, using the dialog window as the parent
"Posting a VB.NET question in the C++ forum will end in tears." Chris Maunder
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I got now by looking in article the subclassing means customising.
And I have done it many times,without knowing that term.
Ok I will try out ,based on time in hand.
|| ART OF LIVING ||
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Hi everybody. I'm developing an IC card handset device application with standard C language.I'm a new comer to C language.I have a question
Look at the funtion definition :
<br />
unsigned short dt_recv(unsigned char *data, int *datalen)<br />
Input parameters: <br />
Data : to receive data buffer<br />
Output parameters: Datalen:receive data buffer size<br />
Return values: none.<br />
<br />
Communication Protocol :<br />
data[0]=command head; <br />
...<br />
data[3]=high of length; <br />
data[4]=low of length;<br />
...<br />
Data[3] and Data[4] store a Int16 value.I have problem when I try to get the value.Here is my code:
<br />
short i;<br />
memcpy(&Data[3],&i,2);<br />
But it seems that I did not get the right value.I guess I'm in the wrong way.I'm not familiar with memory operation.
Can any one give me the right way?Any idea will be appropriate.
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are you a chinese boy?
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My suggestion (not tested):
short i;
i = (short) ((data[3] << 8) | data[4]);
Alcohol. The cause of, and the solution to, all of life's problems - Homer Simpson
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Xiaoming Qian wrote: short i;
memcpy(&Data[3],&i,2);
But it seems that I did not get the right value.I guess I'm in the wrong way.I'm
Are you wanting the value of Data[3] or i? The signature for memcpy() is:
void *memcpy( void *dest, const void *src, size_t count ); So what you have is writing from i to Data[3].
"A good athlete is the result of a good and worthy opponent." - David Crow
"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne
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Xiaoming Qian wrote: short i;
memcpy(&Data[3],&i,2);
On Intel machines, i is stored with the least-significant byte first. If you use memcpy like
this then
Data[3] == least-significant byte of i
Data[4] == most-significant byte of i
To get the value back. something like:
short i = (short)((unsigned short)Data[4] << 8) | (unsigned short)Data[3];
or
short i;
memcpy(&i,&Data[3],2);
"Posting a VB.NET question in the C++ forum will end in tears." Chris Maunder
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Here "data[]" is an array. so "data" itself an a address.
And instead of using "&Data[3]" use "Data[3]" in "memcpy" function
That is:
short i;
memcpy(Data[3],&i,2);
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Wrong. The first argument to memcpy() needs to be an address, of which Data[3] is not.
"A good athlete is the result of a good and worthy opponent." - David Crow
"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne
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I believe you should use a lower-case "D" in "Data". C is a case-sensitive language.
For example, use
memcpy(&i,&data[3],2);
instead of
memcpy(&i,&Data[3],2);
As others have noted, there could be other problems because you're reading from an array of unsigned chars into a short.
-- modified at 14:06 Wednesday 20th June, 2007
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Erik Midtskogen wrote: I believe you should use a lower-case "D" in "Data".
Umm, the compiler would have told him this (i.e., syntax error). 
"A good athlete is the result of a good and worthy opponent." - David Crow
"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne
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I was assuming that he may have been getting a compiler error and not known why. Probably we should ask him what sort compiler message or other symptom of a problem he is seeing.
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Hi all
In servise can I create new process?
( can I use CreateProcess(.....) function? )
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As long as you don't tell anyone I'm sure you can get away with it. I promise I don't work the Process police, honest.
Why don't you try it and let me know?
Nothing is exactly what it seems but everything with seems can be unpicked.
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Ok.
I have console an I whont to make service, sow I copy code from console to service. I test it and ewriting work ony problenm is wen I service try to create process.
<br />
char CmdLine[512];<br />
sprintf(CmdLine,"C:\\My program\\Program.exe"); <br />
<br />
if(CreateProcessA(NULL, CmdLine, NULL, NULL, FALSE, dwCreationFlags, NULL, NULL, &si, &pi) == 0)<br />
{<br />
MyLog("ERROR CANT START PROCESS"); <br />
}<br />
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Ok I test and my service can't create process.
If you can help me.
how to Create Process from Service?
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Hi,
Under which user account does your Service run. Services normally run under a system account which could be conflicting with the CreateProcess function.
Try to run the Service under a user account.
Or create new UserCredentials to start the process with.
codito ergo sum
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