ASP.NET

26-Jun-07 2:19

Client Query String[^]

Regards,

Satips. Rose | [Rose]

Datagrid

bhanu1234526-Jun-07 2:09

bhanu12345

26-Jun-07 2:09

I am using a datagrid to show a set of records.
I am also using edit,update,cancel and delete button columns to perfom required action.

I wanted to is it possible for me to call a javascript function on clicking update button in datagrid.

Thanks & Regards
Bhanu

Re: Datagrid

RepliCrux26-Jun-07 2:15

RepliCrux

26-Jun-07 2:15

You will have to use Ajax if you want to use Javascript for this functionality of Datagrid.

Writing client side code for these kind of functinality is not always the best practice.

Re: Datagrid

Sathesh Sakthivel26-Jun-07 2:18

Error during Deletion of file in Server

26-Jun-07 2:18

bhanu12345 wrote:
I wanted to is it possible for me to call a javascript function on clicking update button in datagrid.

It is not a good practice.

Go with Ajax. that will be better for this.

Regards,

Satips. Rose | [Rose]

dhulipudi26-Jun-07 1:37

dhulipudi

26-Jun-07 1:37

Hi,

I am getting an error while uploading and deleting a file in the server. Using the following code.

ERROR MESSAGE: The process cannot access the file 'index_01.jpg' because it is being used by another process.

protected void Button4_Click(object sender, EventArgs e)
{
DirectoryInfo d = new DirectoryInfo(Server.MapPath("~\\Upload\\"));

if (FileUpload1.HasFile)
{
FileUpload1.SaveAs(@"D:\\Dotnet_Projects\\kyc_start\\Upload\\" + FileUpload1.FileName);
}
else
{
Label1.Text = "No File Uploaded.";
}
foreach (FileInfo f in d.GetFiles("*.jpg"))
{
byte[] buffer = new byte[f.OpenRead().Length];
f.OpenRead().Read(buffer, 0, (int)f.OpenRead().Length);
PhotoManager.AddPhoto(buffer);
f.Delete(); //ERROR HERE!!!

}
this.PhID();
}

Plz let me know where i am making mistakes. ITS working fine in local server. Smile | :)

Regards,
dhulipudi

kubben26-Jun-07 2:18

kubben

26-Jun-07 2:18

My guess is that your site is still running or perhaps your app pool is still running. Normally when you delete files that belong to a web site you will need to stop the web site and the app pool to make sure that none of the files are cached in memory. So if you shut down the app pool that your web app is using I think you should be able to delete the file.

Hope that helps.
Ben

dhulipudi26-Jun-07 2:35

dhulipudi

26-Jun-07 2:35

Hi Ben,

I would like to explain my task more clearly...

Task: Upload Client photos to server and display it. (registration form)

Strategy followed:
1. Upload images to \upload\ folder in server.
2. Read all images in \upload\ folder and put it in sql database.
3. delete the image from \upload\ folder.
4. display it in the webform.

All this tasks should perform in a single button click "upload image"

I succeeded In SETPS: 1, 2 and 4.

I could not delete the file (step 3) soon after I upload the file into the database.

IN this situation i could not stop the site for deletion I need some suggestions that can delete the file soon after Step 2.

Plz let me know your thoughts.

Regards,
JJ

kubben26-Jun-07 2:38

kubben

26-Jun-07 2:38

I am not sure what code you are using to read the images, but I would guess there is a chance that code is not properly closing its connection to the image it just read. The only other thing I have seen with images is the need to call garbage collection. So after you read the images and close the connections to the image then you may need to call gc.Collect

Hope that helps.
Ben

kubben26-Jun-07 2:40

kubben

26-Jun-07 2:40

Here is an example of openread with a fileinfo

using (FileStream fs = fi.OpenRead())
{
byte[] b = new byte[1024];
UTF8Encoding temp = new UTF8Encoding(true);

while (fs.Read(b,0,b.Length) > 0)
{
Console.WriteLine(temp.GetString(b));
}
}

When the using is used the openread is closed when you reach the end of the using. So you are not closing your openread.

Ben

dhulipudi26-Jun-07 2:54

dhulipudi

26-Jun-07 2:54

Thank you for the info. I will check once again all my connections and stream readers used to read the images to DB.

Regards,
Jagadeesh

Vasudevan Deepak Kumar26-Jun-07 2:29

Vasudevan Deepak Kumar

26-Jun-07 2:29

dhulipudi wrote:
foreach (FileInfo f in d.GetFiles("*.jpg"))
{
byte[] buffer = new byte[f.OpenRead().Length];
f.OpenRead().Read(buffer, 0, (int)f.OpenRead().Length);
PhotoManager.AddPhoto(buffer);
f.Delete(); //ERROR HERE!!!

}

A quick brainstorming query: Did you observe whether this FileInfo keeps an handle also?

Vasudevan Deepak Kumar
Personal Homepage
Tech Gossips

validation

A kamath26-Jun-07 0:54

26-Jun-07 0:54

I want to know how should we give validation for phone numbers.
my phone number format is 0000-000-000

SHatchard26-Jun-07 1:04

SHatchard

26-Jun-07 1:04

There are a couple of easy ways

1. Client-side
There is a nice ASP.net AJAX control in the toolkit which offers this if you want to use it. Link - http://ajax.asp.net/ajaxtoolkit/MaskedEdit/MaskedEdit.aspx[^]

2. Regular expression validator
You could write a simple regular expression to match the input against and use a validator on the page. The regular expression would be something like

^d{4}-\d{3}-\d{3}$ (Not 100% sure of the exact syntax)

Try www.regexlib.com as a great source for help and examples of regular expressions.

A kamath26-Jun-07 1:24

26-Jun-07 1:24

thanks

RepliCrux26-Jun-07 1:04

RepliCrux

26-Jun-07 1:04

Heared of Regular expression ?

Sathesh Sakthivel26-Jun-07 1:53

26-Jun-07 1:53

Here is your code for Validation of Phone Number, with asp:regularexpressionvalidator

<%@ Page Language=VB Debug=true %>

<title>Validating a Phone Number with a RegularExpressionValidator Control

Please enter your phone number:

<asp:textbox
="" id="txtPhoneNumber" runat="server">
<asp:regularexpressionvalidator
="" id="regZipCode" controltovalidate="txtPhoneNumber" validationexpression="\\d{4}\-\d{3}\-\d{3}" display="Dynamic" font-name="Arial" font-size="11" runat="server
">
You must enter a phone number in the form of 9999-999-999.

<asp:button
="" id="butOK" text="OK" type="Submit" runat="server">

Regards,

Satips. Rose | [Rose]

A kamath26-Jun-07 1:39

26-Jun-07 1:39

yes

A kamath26-Jun-07 1:58

26-Jun-07 1:58

Thanks, but if the first number should be either 3 or 4 so how should we give?
like 0000-000-000 or 000-000-000

Sathesh Sakthivel26-Jun-07 2:04

26-Jun-07 2:04

The first digit is only three.
Like wise you have to mention.
(999) 999-9999.

Regards,

Satips. Rose | [Rose]

Sathesh Sakthivel26-Jun-07 2:05

26-Jun-07 2:05

But i have given the code as you have asked for four digit in the first as you stated.

If you want you can change the code for three.

Regards,

Satips. Rose | [Rose]

A kamath26-Jun-07 3:48

26-Jun-07 3:48

Thanks .Can we keep both either 3 or 4 in single expression.because some phone no is having 4 digit first and some having 3 digit first.

Sathesh Sakthivel26-Jun-07 4:21