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in SQL Server 2000 is not possible.,
you may try as navaneeth suggesting.
Regards
KP
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Gents,
I have a string "abcd1;abcd2;abcd3;abcd4"
in my database on an MS SQL there are stored "abcd3" in a column. In the reverse situation I would be able to do a select statement like this
Select * from MyTable where MyColumn LIKE '%abcd3%'
Is there any easy solution to it in the reverse way so i fx could do something like
Select * from MyTable where 'abcd1;abcd2;abcd3;abcd4' LIKE MyColumn
Tried this by the way, didnt return any result or error so guess there are some solution to it.
Cheers,
-- modified at 6:28 Tuesday 14th August, 2007
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this not correct because '%adbcd3%' not equal to '%abcd3%'
Select * from MyTable where MyColumn LIKE '%adbcd3%'
if you need show resault you must write select statment
Select * from MyTable where MyColumn LIKE '%abcd3%'
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Hi Rami,
This was an typo in this topic on the example for the normal way to use like statement.
Thanks for the notification of the spelling error.
/Ronni
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hi ronii
you solve the problem
if you not solving problem i need more explane about your problem
with regards
Rami Abd alhalim
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nope didnt solve the problem. please read the whole text.
I have string "abcd1;abcd2;abcd3;abcd4" for example posted from a website or an application
In my database i have a string "abcd1".
I now need to find out if any part of the string ("abcd1;abcd2;abcd3;abcd4") is present in the column who hold fx "abcd1". This have to be done in a single select statement.
If done reverse "Find abcd1 in database with abcd1;abcd2;abcd3;abcd4 then a standard Select * from TableName where ColumnName LIKE '%abcd1%'" but is there an fast and easy to do that in a simliar way? just reverse in finding part of a string in the database?
/Ronni
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add this function after that you can split string to compare between your string
=======================
SET QUOTED_IDENTIFIER OFF
GO
SET ANSI_NULLS OFF
GO
ALTER FUNCTION [dbo].[fn_Split]
(@text varchar(8000), @delimiter varchar(20) = ' ')
RETURNS @Strings TABLE
(
position int IDENTITY PRIMARY KEY,
value varchar(8000)
--Name2 Varchar(8000)
)
AS
BEGIN
/*Declare @Strings TABLE
(
position int IDENTITY PRIMARY KEY,
value varchar(8000)
)
*/
DECLARE @index int
SET @index = -1
Declare @Text2 varchar(8000)
SET @Text2=@text
Declare @index2 int
WHILE (LEN(@text) > 0)
BEGIN
SET @index = CHARINDEX(@delimiter , @text)
IF (@index = 0) AND (LEN(@text) > 0)
BEGIN
INSERT INTO @Strings VALUES (@text)
BREAK
END
IF (@index >1)
BEGIN
SET @index2=len(Right(@text, @index - 1))
SET @text2=SUBSTRING(@text,LEN(LEFT(@text, @index+1 )),CHARINDEX(@delimiter , @text)-1 )
INSERT INTO @Strings VALUES (LEFT(@text, @index - 1))
SET @text = RIGHT(@text , (LEN(@text) - @index))
END
ELSE
SET @text = RIGHT(@text, (LEN(@text) - @index))
END
RETURN
END
GO
SET QUOTED_IDENTIFIER OFF
GO
SET ANSI_NULLS ON
GO
=======================
after add this function
select * from tablename where 'abcd1'in select value from fn_Split('abcd1;abcd2;abcd3;abcd4',';')
Rami Abd alhalim
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How about:
select * from MyTable
where ';abcd1;abcd2;abcd3;abcd4;' like '%;' + MyColumn + ';%' Regards
Andy
If you want to thank me for my help, please vote my message by clicking one of numbers beside "Rate this message".
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Great thanks Andy. Worked like a charm.
Cheers,
Ronni
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I am inserting a row into database from asp.net. Below is the command i had given:
insert_cmd = string.Format("Insert into CreateTask(AssignedTo,AssignedDate,EstimatedEfforts,Priority) values ('ABCD',14/08/2007,30,'Medium')");
The date i had given in the command is 14/08/2007, but when I check the table data in SQL server the date is displayed as ---- 1/1/1900 12:00:00 AM
Please help me out... 
Sailaja
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this problem maybe cause format date
if you need sure that set in command this date
solve:
insert_cmd = string.Format("Insert into CreateTask(AssignedTo,AssignedDate,EstimatedEfforts,Priority) values ('ABCD',08/14/2007,30,'Medium')");
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Said could you plz tell me how to do that as i dnt know.
i'm new to sql
Sailaja
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Insert into CreateTask(AssignedTo,AssignedDate,EstimatedEfforts,Priority) values ('ABCD','2007-8-11',30,'Medium'
In VB u have format function. U can use this function to format the date.
i.e. YYYY-MM-DD format.
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thx pande... the code worked correctly if I give the date in single quotes but am not getting the current system time in it..
its displayed as:
8/14/2007 12:00:00 AM
Sailaja
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If you want to insert the current date and time, use the Getdate() function. It's a Sql Server function that returns the current date and time. For instance:
insert into myTable(CurrentDate) values (GetDate());
Deja View - the feeling that you've seen this post before.
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my problem has been solved.
thank u so much... ![Rose | [Rose]](https://codeproject.freetls.fastly.net/script/Forums/Images/rose.gif)
Sailaja
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i have a table, i want to display the values in rows into columns in sql server 2005..
Ex:-
<br />
<br />
a 1 x ----> a b c<br />
b 2 y ----> 1 2 3<br />
c 3 z ----> x y z<br />
Can anyone help me on this??
Dream it to achieve it
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Hi
I have about 2k records in a table which contains a numeric field. I would like to know if there is any way I can select a set of records where the sum of this numeric field is limited to a particular value.
The table in question is part of an SQL 7 database.
Thanks in advance
Chandra
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Hi Chandra
Do you mean:
select * from Orders where cust_id in (
select cust_id from Orders
group by cust_id
having sum(order_total) > 500)
order by cust_id This would receive the orders for customers who have placed more than $500 worth of orders.
Regards
Andy
If you want to thank me for my help, please vote my message by clicking one of numbers beside "Rate this message".
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Hi Andy
Thanks for your answer... but what if my table contains all distinct cust_id?
Regards
Chandra
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Hi Chandra
Sorry - I got a little confused because your original question stated "... where the sum of ...".
Does
select * from Orders where OrderValue > 500 do what you want?
Regards
Andy
If you want to thank me for my help, please vote my message by clicking one of numbers beside "Rate this message".
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Hi Andy,
I'm afraid this will not help either... let me explain with some data:
Field1 Field2<br />
3 34<br />
4 58<br />
5 97<br />
6 234<br />
7 345<br />
8 540<br />
9 679<br />
10 768<br />
11 2312<br />
12 4324
Now, I want to be able to pick up a set of records where the sum of Field2 is less than 5000.
I hope I have explained my requirement clearly 
Thanks
Chandra
Modified to include /code tags since the tabs were swallowed up.
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Hi Chandra
Thats a bit clearer - looks like some-sort of stock allocation problem. The simplest query would be:
select * from MyTable
where Field1 in (
select a.Field1
from MyTable a
inner join MyTable b
on b.Field1 <= a.Field1
group by a.Field1
having sum(Field2) < 5000)
order by Field1The key is the link between a.Field1 and b.Field1. However, this checks rows sequentially. If you have a record with Field1=100 and Field2=1 then earlier rows take precedence.
If you want a more optimised allocation query then you would need to resort to a UDF.
Regards
Andy
If you want to thank me for my help, please vote my message by clicking one of numbers beside "Rate this message".
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Thanks Andy
No... its not a stock-allocation problem, just something I am trying to implement without having to write a messy SP.
I ran your query and got this result... not quite what I was looking for, but thanks anyway.
field1 field2<br />
10 768<br />
11 2312<br />
4 58<br />
5 97<br />
7 345
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Got it ....
create table #MyTable (
Field1 int,
Field2 int
)
go
insert into #MyTable values (3, 34)
insert into #MyTable values (4, 58)
insert into #MyTable values (5, 97)
insert into #MyTable values (6, 234)
insert into #MyTable values (7, 345)
insert into #MyTable values (8, 540)
insert into #MyTable values (9, 679)
insert into #MyTable values (10, 768)
insert into #MyTable values (11, 2312)
insert into #MyTable values (12, 4324)
go
select * from #MyTable
where Field1 in (
select a.Field1
from #MyTable a
inner join #MyTable b
on b.Field1 <= a.Field1
group by a.Field1
having sum(b.Field2) < 5000)
order by Field1
goMy previous solution had an ambiguous column.
Regards
Andy
If you want to thank me for my help, please vote my message by clicking one of numbers beside "Rate this message".
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