|
hi i have java script code for uploading images or files for a joomla component and i am not able to store this images or files in data base tell me the procedure for storing the images in a data base and i don't no data base in depth please let me know its urgent..........
|
|
|
|
|
Sorry, but there is no Access forum.
In a sub-form for detail lines, I'm trying to respond to the entry of a bar-code, using the After Update event of the bar-code combobox, where I set the Product name textbox in the same detail line to the ProductName value in the combobox. I'm sure I've done this before, and it only affects the current record, but now when I update the bar-code, the text the product name textbox in ALL lines gets updated.
Private Sub ddlProduct_AfterUpdate()
txtProductName = ddlProduct.Column(2)
End Sub
I do not believe they are right who say that the defects of famous men should be ignored. I think it is better that we should know them. Then, though we are conscious of having faults as glaring as theirs, we can believe that that is no hindrance to our achieving also something of their virtues. - W. Somerset Maugham
My New Blog
|
|
|
|
|
I couldn't add new registration in SQL Server2000 using SQL Server Authentication mode even I've already entered correct server name, username sa and correct password.
I've tried to ping this server from command line and it's ok.
But if I run Windows Explorer (\\servername) and put Windows'username and password then add new registration again, it's successful.
Please explain me why? I want to add new registraion from some server which I only have SQL Server username and password but don't have Windows username and password. Is it possible?
adfafafa
|
|
|
|
|
hdtrung wrote: Please explain me why?
Does the server process accept remote connections? Is there a firewall blocking the TCP port it is using?
Have you installed a named instance? If so, then you need to specify the name as well as the machine.
-- Always write code as if the maintenance programmer were an axe murderer who knows where you live.
Upcoming FREE developer events:
* Glasgow: Agile in the Enterprise Vs. ISVs, Mock Objects, SQL Server CLR Integration, Reporting Services, db4o ...
* Reading: SQL Bits
My website
|
|
|
|
|
Hi Colin Angus Mackay,
I used default instance (MSSQLSERVER) when installing the server. I think there's no problem with TCP port or remote connections(no firewall,my computer and server are in the Wide area network).
The server is also running in SQL authentication mode. That's why I gave username sa and password when adding new registration.
Following are all the complicated steps I must do to add new registration:
Ping SERVERNAME to check connection
Add new registration, using SA and SApassword
The previous step failed, then run windows explorer (\\SERVERNAME)
Put windows logon info: SERVERNAME\trunghd & mypassword
Add new registration again and it's successful
If I add registration from some server that I've already entered windows logon info once, it's successful too.
The question is why I have to give Windows logon information to the server when it's running in SQL authentication mode. I found no relation between my Windows username in this server with the installed SQL server in it.
Thank you very much for your answer.
adfafafa
|
|
|
|
|
HI All,
I have a frustrating problem with continual login failures with SQLExpress 2005.
I have an application that behaved until yesterday when I started adding some extra Crystal reports.
I get either of two errors:
1. "Cannot open user default database. login failed for TECRA\Nigel"
Or
2. some big long system error (32) saying the file is in use.
When first entering VS, I can either create a dataset or open server explorer, but after that trying to do either throw the error(s).
To clear the error i have to close down VS, restart SQL server manager and reset IIS, but it is back next time I try to do anything with the DB.
Folder permissions are OK for both ASP.NET and NETWORK SERVICE. I have even resorted to deleting the new reports and datasets but now I get the errors regardless.
I am sure I must have done something to the DB, or maybe there is a dud connection somewhere, but I have limited knowledge of SQL Server Manager Express so don't know where to look to stop the errors.
Connection string is:
<add name="cs_BigShakti" connectionString="Data Source=.\SQLEXPRESS;AttachDbFilename=|DataDirectory|\SHAKTI.MDF;Integrated Security=True;User Instance=True; Connect Timeout=30;Initial Catalog=SHAKTI" providerName="System.Data.SqlClient"/>
Many thanks in advance,
Nigel
|
|
|
|
|
big_nige wrote: Initial Catalog=SHAKTI" provider
Why do I see an extra quote after SHAKTI?
SG
Cause is effect concealed. Effect is cause revealed.
|
|
|
|
|
Hi,
How can I create a DTS Package using Sql-DMO in a Stored Procedure. I am
using Sql Server 2000.
Saswat.
|
|
|
|
|
1-To connect to the distribution database and provide published data to the DTS package (source connection), a special OLE DB provider, the Microsoft SQL Server Replication OLE DB Provider for DTS is used. When you create a transformable subscription, this provider is installed automatically on the
DTS package, and cannot be changed. This provider can be used only with transformable subscriptions.
The connection from the DTS package to the Subscriber (destination connection) does not use the Microsoft SQL Server Replication OLE DB Provider for DTS; it uses whatever OLE DB provider is required to connect to the Subscriber. For example, you would use the Microsoft OLE DB Provider for SQL Server to send transformed data to a Microsoft® SQL Server™ 2000 Subscriber.
2-Only SQL Server (the Microsoft OLE DB Provider for SQL Server) Subscribers and other OLE DB Subscribers can use transformable subscriptions; ODBC Subscribers will not work with transformable subscriptions.
Rami Abdalhalim
|
|
|
|
|
I'm writing an ASP .NET 2.0 application, and I have the following code:
Public Function GetRow(ByVal Id As Guid) As DataRow
Return Me.mDataSet.Table(0).Rows.Find(Id)
End Function
But an exception is thrown at the line: Return Me.mDataSet.Table(0).Rows.Find(Id). I copy the exception details bellow:
Error de servidor en la aplicación '/Proyecto03'.
--------------------------------------------------------------------------------
Se esperaban los valores 2 para la clave indizada, pero se han recibido valores 1.
Descripción: Excepción no controlada al ejecutar la solicitud Web actual. Revise el seguimiento de la pila para obtener más información acerca del error y dónde se originó en el código.
Detalles de la excepción: System.ArgumentException: Values 2 expected, but instead values 1 were received
This is anoying, because the Find method has two overloaded versions: one accepts an Object as parameter and the other accepts an array of Object, so a Guid object should pass without problems. The only thing that comes to my mind is this: There is a special way to make it with the Guid type, but I can't find anything neither the MSDN Library, nor the internet.
Please, help!!!
Bye
|
|
|
|
|
reinaldo.aru wrote: Se esperaban los valores 2 para la clave indizada, pero se han recibido valores 1.
Descripción: Excepción no controlada al ejecutar la solicitud Web actual. Revise el seguimiento de la pila para obtener más información acerca del error y dónde se originó en el código.
Detalles de la excepción:
To tell you the truth I dont understand any of that!
but as far as ur error is concerned I think what ur doin is that you're passing a single object of GUID type to Find and if you see its discription it says that the method takes the primary key value. I think your primary key must be something else and its datatype is not GUID hence the error... (I can be wrong too coz its an assumption)
Rocky
You can't climb up a ladder with your hands in your pockets.
|
|
|
|
|
I developed a web application usin c# and mysql as my database. Deploying it to my web server is giving me the following error message:
Configuration Error
Description: An error occurred during the processing of a configuration file required to service this request. Please review the specific error details below and modify your configuration file appropriately.
Parser Error Message: Could not load file or assembly 'MySql.Data, Version=5.0.3.0, Culture=neutral, PublicKeyToken=c5687fc88969c44d' or one of its dependencies. The system cannot find the file specified.
Source Error:
Line 20: <compilation debug="true">
Line 21: <assemblies>
Line 22: <add assembly="MySql.Data, Version=5.0.3.0, Culture=neutral, PublicKeyToken=C5687FC88969C44D">
Line 23:
|
|
|
|
|
Have you installed the MySQL provider libraries on the server? .NET does not support MySQL out-of-the-box, as far as I know.
|
|
|
|
|
I'm having to store the Year-End associated with accounts. While there is a static list of 12 dates that have been provided for me, the final day of each month, I wondering about what year value to use when I store these values into a database with a datetime type. I will be using the value to initialise other datetime types for specifying date ranges for subsequent query operations. For example, consider an account that is define to have a year-end of May 31. If I have to provide quarterly information on this account, then going forward I will be generating date ranges such as June 1 2007 to August 31 2007, September 1 2007 to November 30 2007 and December 1 2007 to February 29 2008. I now how I'm going to be generating these date ranges, but just wondering if there is a best practice for stroing year end dates where you ignore or don't care about the year value? Thanks.
Chris Meech
I am Canadian. [heard in a local bar]
|
|
|
|
|
You may want to look at AdventureWorksDW DimTime table. Its a OLAP concept where you use a DayTimeKey to refer to a lookup table DimTime for actual date and other pre-aggregated data.
You might be able to insert just one date for every day with FiscalYear and then use
SELECT [FiscalYear]
FROM [dbo].[DimTime]dt
INNER JOIN MyTable t1 ON CONVERT(varchar(23), t1.DateColumn, 101) = dt.[FullDateAlternateKey]
CREATE TABLE [dbo].[DimTime]
(
[DayTimeKey] [bigint] IDENTITY(1,1) PRIMARY KEY NOT NULL,
[FullDateAlternateKey] [datetime] NULL,
[DayNumberOfWeek] AS (datepart(weekday,[FullDateAlternateKey])),
[DayNameOfWeek] AS (datename(weekday,[FullDateAlternateKey])),
[DayNumberOfMonth] AS (datepart(day,[FullDateAlternateKey])),
[CalendarYear] AS (datepart(year,[FullDateAlternateKey])),
[MonthName] AS (datename(month,[FullDateAlternateKey])),
[MonthNumberOfYear] AS (DATEPART(mm, [FullDateAlternateKey])),
[CalendarQuarter] [tinyint] NULL,
[CalendarYear] [char](4) NULL,
[CalendarSemester] [tinyint] NULL,
[FiscalQuarter] [tinyint] NULL,
[FiscalYear] [char](4) NULL,
[FiscalSemester] [tinyint] NULL
)
Dave Evans
|
|
|
|
|
Thanks for the comment, Dave. That looks to be a little more than what I'm after, but it has given me an idea of using a separate table to contain all of the date ranges I may every use and then have an identifer map to the date range.
Chris Meech
I am Canadian. [heard in a local bar]
|
|
|
|
|
Hi.
How can I select some (5 for example) random record from a table?
i.e I want to select 5 records in random from a table ?
Best wishes
|
|
|
|
|
Use the function NEWID() to calculate a GUID for each row and sort by that.
SELECT TOP 5 *
FROM [MyTable]
ORDER BY NEWID()
-- modified at 14:54 Thursday 23rd August, 2007
|
|
|
|
|
I do something similar; I have a table with two columns, one for IDs and one for random numbers.
The benefits are:
A) I don't have to add a column to the main (Employee) table
B) I can weight the selection process; that is, some records (employees) may have multiple entries
in the "hat", or none at all
The table is normally empty, but when it's time to select (Employee) records, I populate it, and make my selections (after an employee is selected I remove all the entries for that employee).
Then I clear the table again when selecting is complete.
One could also add a column to indicate that that ID has already been selected, and after selections delete the non-selected rows, leaving a table with the selected IDs which can then be used in a join.
|
|
|
|
|
My idea is to get the max and min ID's from that Table.
Then use the Math.Random Function and give the limits in that range taken in previous step.
Select 5 Random ID's this way
Then select those records using this kindof construct in your where clause
ID IN(rand1,rand2,rand3,rand4,rand5)
Hope that's helpful for u
Rocky
You can't climb up a ladder with your hands in your pockets.
|
|
|
|
|
That'll work; unless IDs have been removed or deactivated or something.
Maybe select ten random numbers in the range and use TOP 5.
Or loop until you have five.
Rocky# wrote: You can't climb up a ladder with your hands in your pockets.
Sure I can, done it many times, but not on a steep ladder.
|
|
|
|
|
Hi,
I have a table with column named EmpID, EmpName, Salary,
I want to find out second highest salary.
Thanks![Rose | [Rose]](https://codeproject.freetls.fastly.net/script/Forums/Images/rose.gif)
|
|
|
|
|
SELECT MAX(Salary)
FROM [EmployeeTable]
WHERE Salary < (SELECT MAX(Salary) FROM [EmployeeTable])
|
|
|
|
|
thanks for your help.
Now I have a query that if I want find 3rd highest or 4th highest salary then how to write query?
thanks!
|
|
|
|
|
select TOP 5 salary,empID
FROM EMP
Order by Salary DESC
Use this to find whatever number of top salaried personeel u want. Use a Cursor to fetch the records one by one. In this way u can ignore the records you dont want. Like for finding the 4th highest salary you can ignore the 1st 3 records and get the fourth one.
Rocky
You can't climb up a ladder with your hands in your pockets.
|
|
|
|
|
General 
News 
Suggestion 
Question 
Bug 
Answer 
Joke 
Praise 
Rant 
Admin 
Submit an article or tip
