Re: Tab Order - C / C++ / MFC Discussion Boards

Re: Reading microphone input

Russell^'14-Sep-07 22:25

Russell^'

14-Sep-07 22:25

Thanks

About Linux:
I don't know anything about it to help you, sorry.

You can start a new thread,...but think also to post it in another forum: here more than 90% of members are expert on Windows. I don't want to mean that here noone can help you, but that it is not so impossible.

good luck
Rose | [Rose]

Russell

Reg. Structure variable [modified]

rajaratk13-Sep-07 19:22

rajaratk

13-Sep-07 19:22

Hello,

Good Day!

Step 1:

struct user
{

unsigned short us_nbs;
unsigned short us_debit;
unsigned short us_flowctrl;
};

Step 2:

In another header file contains this:

"class C_User : public CObject, public user"

Step 3:

class C_Subscriber : public C_User

Step 4:
C_Subscriber subdeviceSubs = *lpSubscr;

Step 5:
I got that us_flowctrl value is "0" by executing this statement : subdeviceSubs.us_flowctrl. How?

Thanks in advance
Raja Ratheesh

-- modified at 1:56 Friday 14th September, 2007

Re: Reg. Structure variable

Nishad S13-Sep-07 20:23

Nishad S

13-Sep-07 20:23

rajaratk wrote:
C_Subscriber subdeviceSubs = *lpSubscr;

What is this lpSubscr?

- NS -

Re: Reg. Structure variable

rajaratk13-Sep-07 22:47

rajaratk

13-Sep-07 22:47

Instance of

typedef struct user far *LPUSER;

Re: Reg. Structure variable

Nishad S14-Sep-07 1:44

Nishad S

14-Sep-07 1:44

So you are getting values changed...

class C_User : public CObject, public user
class C_Subscriber : public C_User
typedef struct user far *LPUSER

C_Subscriber subdeviceSubs = *lpSubscr;

So the C_Subscriber has CObject in the first memory area. I doubt that it could be the problem.

Dont you get any compilation error by "C_Subscriber subdeviceSubs = *lpSubscr;" ?

- NS -

Tab Order

msr_codeproject13-Sep-07 17:10

msr_codeproject

13-Sep-07 17:10

Hi friends........

I have a question on tab oreder.......?

How the tab order will effect the visibility of controls placed on a dialog?

Thank u in advance.....

Sairam Madem

Re: Tab Order

Mark Salsbery13-Sep-07 18:07

Mark Salsbery

13-Sep-07 18:07

The WS_VISIBLE style effects the visibility of controls on a dialog.

If you meant the Z-order, the controls are created in the order they
appear in the DIALOG resource, so initially, the first control will be at the
bottom of the z-order, the last control at the top.

Setting the tab order sets the order of the control definitions in the resource.

Mark

Mark Salsbery
Microsoft MVP - Visual C++
Java | [Coffee]

Re: Tab Order

chandu00413-Sep-07 19:39

chandu004

13-Sep-07 19:39

it is a simple logic.
the control that has the least taborder will be placed first on the dialog.
then any other control with a higher taborder will be placed next.
this means that,
the later control, if it is located at the same place as the former control will obviously overlap the former.
in the past, once i faced the same problem. i had to struggle for two days to find out that taborder is the reason for the controls that are invisible.
is int it very funny?
gud luck.

Re: Tab Order

Nishad S13-Sep-07 20:17

Nishad S

13-Sep-07 20:17

chandu004 wrote:
i had to struggle for two days to find out that taborder is the reason for the controls that are invisible.

- NS -

Upgrading old MFC look to .NET look

Mojoturner13-Sep-07 16:42

Mojoturner

13-Sep-07 16:42

Hopefully this makes sense, here goes:
I've upgraded my MSVS C++ 6.0 MFC application to MSVS C++ 2005. All went well - no big issues - but here's what I can't figure out: In my resource browser my MFC dialog app appears to have that updated .NET style, i.e. rounded glossy buttons & list controls. That's how I would like it to appear when built; however, it still has that "old-school" MFC look with the square edge buttons and "3D" look.

I've created a new MFC dummy app just to compare headers and resource files in Araxis Merge to see if I could find some "switch" somewhere that needs to be set. The dummy app has that contemporary .NET look. I can't seem to figure out what I need to set to accomplish this task.

Any help or advice would be GREATLY appreciated.

Thanks,
CMD

Re: Upgrading old MFC look to .NET look

sps-itsec4613-Sep-07 22:21

sps-itsec46

13-Sep-07 22:21

Hi,

checkout the following links:
http://www.codeproject.com/w2k/xptheme.asp[^]
http://www.codeproject.com/cpp/xpstylemfc.asp[^]

(regard the comments for VS2005 in the discussion section below the articles)

cheers,
mykel

OMM: "Let us be thankful we have an occupation to fill. Work hard, increase production, prevent accidents and be happy."

need to give the number of middle

youbo13-Sep-07 15:53

youbo

13-Sep-07 15:53

when somebody input some number,you need give out the number of middle.my code is follow:#include <iostream>
using namespace std;
void swap(int &a,int &b);
void main()
{
int n=0,k,m,j;
int*p=new int[n];

cin>>n;
k=n;
j=n;
m=n;
for(;n>0;n--)
{
cin>>p[n-1];
}
int x=1;
while(x)
{
x=0;
for(;k>0;k--)
{
if(p[k-1]

Re: need to give the number of middle

David Crow13-Sep-07 17:22

David Crow

13-Sep-07 17:22

youbo wrote:
the number of middle.

AKA the median.

youbo wrote:
my code is follow

Congratulations. Roll eyes | :rolleyes:

"A good athlete is the result of a good and worthy opponent." - David Crow

"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne

Re: need to give the number of middle

youbo13-Sep-07 17:24

youbo

13-Sep-07 17:24

- -!!

Re: need to give the number of middle

David Crow14-Sep-07 2:28

David Crow

14-Sep-07 2:28

Is dash space dash exclamation exclamation an abbreviation for something?

"A good athlete is the result of a good and worthy opponent." - David Crow

"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne

Re: need to give the number of middle [modified]

carrivick13-Sep-07 19:23

carrivick

13-Sep-07 19:23

Here you go

void swap(int &a,int &b);<br />
void main()<br />
{<br />
   int array_size=0,k,m,j;<br />
<br />
<br />
   cin>>array_size;<br />
   if(array_size < 1)<br />
      return;<br />
   int*p=new int[array_size];<br />
   for(int i=0;i<array_size;i++)<br />
   {<br />
      cin>>p[i];<br />
   }<br />
   // Lets do a bubble sort<br />
   bool changed = true;<br />
   int bubble_end = array_size - 1;<br />
   while(changed)<br />
   {<br />
      changed = false;<br />
      for(int i=0;i<bubble_end;i++)<br />
      {<br />
         if(p[i] > p[i+1])<br />
         {<br />
            swap(p[i],p[i+1]);<br />
            changed = true;<br />
         }<br />
      }<br />
   }<br />
   if(array_size > 1)<br />
   {<br />
      if(array_size%2==1)<br />
         cout<<p[array_size/2+1];<br />
      else cout<<p[array_size/2]<<p[array_size/2+1];<br />
   }<br />
   else<br />
      cout<<p[0];<br />
<br />
}<br />
void swap(int &a,int &b)<br />
{<br />
   int c;<br />
   c=a;<br />
   a=b;<br />
   b=c;<br />
}

-- modified at 8:50 Saturday 15th September, 2007

Re: need to give the number of middle

youbo13-Sep-07 20:38

youbo

13-Sep-07 20:38

thank you first,but i couldn't find out the differences from your code to mine.i
have run it ,it appeared the same wrong that is not i need. my code in the same with yours is looked right....

Re: need to give the number of middle

carrivick15-Sep-07 2:48

carrivick

15-Sep-07 2:48

Look more closely

void main()<br />
{<br />
int n=0,k,m,j;<br />
//n is Zero so you declare an array of zero size !<br />
int*p=new int[n];<br />
// To late you update the value of n<br />
cin>>n;<br />
k=n;<br />
j=n;<br />
m=n;<br />
for(;n>0;n--)<br />
{<br />
cin>>p[n-1];<br />
}<br />
int x=1;<br />
while(x)<br />
{<br />
x=0;<br />
for(;k>0;k--)<br />
{<br />
// This syntax is just wrong try to understand rather than just getting it to compile<br />
if(p[k-1] {<br />
swap(p[k-1],p[k]);<br />
x=1;<br />
<br />
}<br />
<br />
}<br />
}<br />
// What if only one element is enter opps were off the end of the array<br />
if(m%2==1){cout<<p[j/2+1];}<br />
else cout<<p[j/2]<<p[j/2+1];<br />
//cout<<p[m/2+j%2]<<endl;<br />
<br />
}<br />
void swap(int &a,int &b)<br />
{int c;<br />
c=a;<br />
a=b;<br />
b=c;}

get this,it is also wrong.please have

Convert DWORD_PTR back to my object

paresh_joe13-Sep-07 9:48

paresh_joe

13-Sep-07 9:48

I have problem with Casting ...

i've create class named Instrument { ... }

and in Dialog based MFC application
i have TreeView Control and in that at some point i am settin ItemData as "Instument" classs' Object

treeCtrl->SetItemData(instObject)//Instrument* to DWORD_PTR casting is done here Wink | ;)

now at some point i need this data(object) back
so to take data

Instrument *instObject = treeCtrl->GetItemData(hItem); // error: Sniff | :^)

Please help me to cast DWORD_PTR back to Instrument Type ... Frown | :(

Re: Convert DWORD_PTR back to my object

Michael Dunn13-Sep-07 10:03

Michael Dunn

13-Sep-07 10:03

To reverse the effect of the first cast, cast the value back to the original type:

Instrument *instObject = (Instrument*) treeCtrl->GetItemData(hItem);

--Mike--
Visual C++ MVP Cool | :cool:

LINKS~! Ericahist | PimpFish | CP SearchBar v3.0 | C++ Forum FAQ

"That's what's great about doing user interface work. No matter what you do, people will say that what you did was idiotic." -- Raymond Chen

Re: Convert DWORD_PTR back to my object

paresh_joe13-Sep-07 17:22

paresh_joe

13-Sep-07 17:22

hey its not working ...

otherwise i would have done that ...

Re: Convert DWORD_PTR back to my object

David Crow13-Sep-07 17:24

David Crow

13-Sep-07 17:24

Then you've obviously done something else wrong, as Michael's suggestion is correct. How are you verifying that it does not work?

"A good athlete is the result of a good and worthy opponent." - David Crow

"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne

Re: Convert DWORD_PTR back to my object

carrivick13-Sep-07 19:29

carrivick

13-Sep-07 19:29

I'm guessing you are getting cannot convert DWORD_PTR to Instrument *.

Oh and allways try and use eplicit casting i.e. static_cast rather than C-Style casts.

Try this

Instrument *instObject = static_cast<Instrument *>((static_cast<void *>(treeCtrl->GetItemData(hItem))));

or if not

Instrument *instObject = dynamic_cast<Instrument *>((dynamic_cast<void *>(treeCtrl->GetItemData(hItem))));

Could you copy the exact compiler error into the thread.

Re: Convert DWORD_PTR back to my object

Michael Dunn13-Sep-07 22:13

Michael Dunn

13-Sep-07 22:13

reinterpret_cast is the right one for this situation, since you're converting between a pointer and a non-pointer type.

--Mike--
Visual C++ MVP Cool | :cool:

LINKS~! Ericahist | PimpFish | CP SearchBar v3.0 | C++ Forum FAQ

I work for Keyser Söze

Re: Convert DWORD_PTR back to my object

paresh_joe13-Sep-07 19:41

paresh_joe

13-Sep-07 19:41

oh sorry its working now ... it was my mistake ...

Thanks a lot ... Big Grin | :-D

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