Flickering - C / C++ / MFC Discussion Boards

Re: Enabling a button after previous button click.

chandu00410-Oct-07 2:48

chandu004

10-Oct-07 2:48

congradulations! Blush | :O

Re: Enabling a button after previous button click.

CodingLover10-Oct-07 19:04

CodingLover

10-Oct-07 19:04

Thanks. Seems to me lots of things can be done there, like global initializations and stuff. I want to try them later. Smile | :)

I appreciate your help all the time...

Re: Enabling a button after previous button click.

Nelek10-Oct-07 0:47

Nelek

10-Oct-07 0:47

mmm, ok, let see...

You stablish your form or your dialog in the resource editor, then you drag a button from the toolbar and drop it on your form. If you select the button and press enter, you get a properties window where as default comes IDC_BUTTON1 this is the ID of the button (you may always change it to you names, i.e. IDC_BUTTON_OPEN), you have the caption and so on...

once you have the buttons with the correct names, you can press CTRL + W and comes the class wizard assistant. When it opens you have the "Message order table" property sheet opened, the second is "Member variables", the third "Automation" and so on...

In the second one "Member variables" you will have a list with all the IDs of the form, in this case the two buttons, click on add variable and complete the "m_ " field with a name to reference the button in your code.

Create the second button and uncheck the property "Enabled" in the properties window of the button (at the bottom)

If you do it in that way, you can always use this name directly to access or modify the button.

You will have something like that in your CDialog.cpp

void CMyView::DoDataExchange(CDataExchange* pDX)
{
	CFormView::DoDataExchange(pDX);
	//{{AFX_DATA_MAP(CSPSMonitorView)
	DDX_Control(pDX, IDC_BUTTON_OPEN, m_cbOpen);
	DDX_Control(pDX, IDC_BUTTON_CLOSE, m_cbClose);
	//}}AFX_DATA_MAP
}

one that is done...

you can use another time the class assistant (this time in the first sheet "Messages Table") to look for the name of your button in the left listbox and include a function of the right listbox. In this case your OnButtonOpenClick

void CMyView::OnButtonOpenClick()
{
//do your things to open the file

m_cbClose.EnableWindow (TRUE);
}

and to reset the enable

void CMyView::OnButtonCloseClick()
{
//do your things to close the file

m_cbClose.EnableWindow (FALSE);
}

The other way to make it is without using member variables, taking a pointer to the control using the ID and the GetDlgControl () function as the other answer already explains.

Greetings.

--------
M.D.V.

If something has a solution... Why do we have to worry about?. If it has no solution... For what reason do we have to worry about?

Help me to understand what I'm saying, and I'll explain it better to you

Wink | ;)

Re: Enabling a button after previous button click.

CodingLover10-Oct-07 0:56

CodingLover

10-Oct-07 0:56

Thank you for the long explanation. I learn a lot from there. Meantime I found one way to do it. As I asked earlier, I'm looking to find where the form load or any smiler operation is going on.

OnInitDialog() behave like that. I placed the code

GetDlgItem(IDC_CLOSE)->EnableWindow(FALSE) ;

for Close button it works. What's your comments.

Thanks Smile | :)

I appreciate your help all the time...

Re: Enabling a button after previous button click.

Nelek10-Oct-07 1:07

Nelek

10-Oct-07 1:07

if it works... it works. Wink | ;)

Re: Enabling a button after previous button click.

CodingLover10-Oct-07 1:10

CodingLover

10-Oct-07 1:10

Ya, seems to me it is correct. But haven't found that it is used on the web, not on the MSDN as well. Anyway it works as form load in Visual Studio .Net 2003 Big Grin | :-D

I appreciate your help all the time...

Re: Enabling a button after previous button click.

Hamid_RT9-Oct-07 23:38

Hamid_RT

9-Oct-07 23:38

use of m_Open.EnableWindow(1);or 0 for disable

Flickering

saisp9-Oct-07 22:58

saisp

9-Oct-07 22:58

I created an MFC ActiveX Control with VC++ Wizard. Compiled it without changing anything. Created a webpage, put it in (it draws an ellipse).Now drag the horz scrollbar, the image inside the activeX control is teared and dragged terribly. It even draws the border on the surface of activeX control. how to avoid this flickering.

Re: Flickering

chandu00410-Oct-07 0:29

chandu004

10-Oct-07 0:29

can you explain more,
because, i used my own active X controls, which display images in web pages(html). but i never faced such problem.

Non-rectangular client area

Nishad S9-Oct-07 22:53

Nishad S

9-Oct-07 22:53

Hi,

Is it possible to make the client area of a window as non-rectangular? If yes how?

Thanks in advance.

- NS -

Re: Non-rectangular client area

Nelek9-Oct-07 23:14

Nelek

9-Oct-07 23:14

Yes, i have a word document where it is explained how to make a round window, the most important problem... It is on spanish. But if you want I can send you it, and take a look in the code that is being explained (altough you can not understand the explanations)

if rounded is possible, I guess polygonal will be possible too.

Re: Non-rectangular client area

Nishad S9-Oct-07 23:29

Nishad S

9-Oct-07 23:29

Thank you for the replay. But are you sure that it says about creating the client area as round? Or simply the window?

Anyway I dont know Spanish Frown | :(

But if you kindly send it I may try by using any translators Smile | :)

- NS -

Re: Non-rectangular client area

Nelek10-Oct-07 0:30

Nelek

10-Oct-07 0:30

Now that you say it... it is a round window (I read it too quick). So it problably won't be usefull at all. Sniff | :^)

But... it is a bit difficult to see the concept, if the window is not round... why to stablish a round client area?

and an innocent try...

have you thought about masking the squared client area with a user defined region and avoiding all what is outside the limits of the region?

Re: Non-rectangular client area

Nishad S10-Oct-07 2:27

Nishad S

10-Oct-07 2:27

Let me say an example. Suppose my window has a round shape. And it has child controls. And my requirement is that, the border should be of a few pixels. So the childs should be clipped by the round client border if it is placed beyond the client. If only rectangular shape is possible for client, you can imagine what will be the problem. There will be non uniform border thickness, right?

- NS -

Re: Non-rectangular client area

Nelek10-Oct-07 20:39

Nelek

10-Oct-07 20:39

Send me a pm to have your email and I will send you the document anyways, there may be some code that gives you an idea.

Re: Non-rectangular client area

eli1502197910-Oct-07 0:02

eli15021979

10-Oct-07 0:02

You can create a region using a bitmap.
Here is one example :http://www.codeproject.com/dialog/cdialogsk.asp[^]

Eli

Re: Non-rectangular client area

Nishad S10-Oct-07 0:10

Nishad S

10-Oct-07 0:10

Sorry. This is not what I am looking for.

- NS -

Re: Non-rectangular client area

Mark Salsbery10-Oct-07 6:14

Mark Salsbery

10-Oct-07 6:14

The client area of a window is kind of an abstract concept.

The WM_NCHITTEST message is used by the system to determine points
in or outside of the client area.

You can handle this message and adjust the return value appropriately.

For drawing, you'll need to use clipping regions if necessary.

Mark

Mark Salsbery
Microsoft MVP - Visual C++
Java | [Coffee]

Re: Non-rectangular client area

Nishad S10-Oct-07 17:45

Nishad S

10-Oct-07 17:45

But what about the clipping of child controls by the client area?

- NS -

Re: Non-rectangular client area

David Crow11-Oct-07 2:58

David Crow

11-Oct-07 2:58

See here.

"A good athlete is the result of a good and worthy opponent." - David Crow

"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne

Re: Non-rectangular client area

Nishad S11-Oct-07 18:48

Nishad S

11-Oct-07 18:48

Thank you. But I could not found the solution for my doubt. I am not talking about the NcHitTest. But the actual client area, by which the child's visibility is clipped. AFAIK client are cannot be non-rectangular. Frown | :(

- NS -

Re: Non-rectangular client area [modified]

rnendel1-Feb-10 6:06

rnendel

1-Feb-10 6:06

Yes, I just did it.&nbsp;&nbsp; The concept is fairly easy to implement if you are managing your own custom container control ( which I'm fairly certain is what you are doing based on the thread ).

To implement this; however, you need to use only custom child controls or child controls that have OnPaint() overridden so that you can interject a clipping region prior to the child control being rendered.

1. In your custom container control, in the OnPaint() event, calculate the desired client area GraphicsPath.&nbsp;&nbsp; Save that path as a public member for later use by chlid controls, let's name it 'ClientAreaPath' for fun.

2. For any control that can be added to your custom container, define the control as a custom control, or at least inherit and override the OnPaint() event.

3. In your child controls, in the OnPaint() override, determine if the control is a child of your custom container and, if so, then transform and apply the ClientAreaPath that was calculated and saved in step #1 above.&nbsp;&nbsp; Viola - non-rectangular clipping Smile | :)

Here's a rough c# outline of the child control OnPaint() operations.

public override void OnPaint( PaintEventArgs e )
{
   // determine if this control is parented and if the parent can supply a ClientAreaPath
   try
   {
         // attempt to cast, will cause exception if nothing else
         MyCustomContainer parentContainer = ( MyCustomContainer )Parent;

         // get a copy of the custom client path
         GraphicsPath p = new GraphicsPath(parentContainer.ChildPath.PathPoints, parentContainer.ChildPath.PathTypes);

         // transfrom the path to be relative to the client (critical step here)
         // all paths are "zero-relative" so the client needs to see this path expressed
         // not as zero-relative, but client-location relative instead
         Matrix translateMatrix = new Matrix();
         translateMatrix.Translate(-(Location.X), -(Location.Y));
         p.Transform(translateMatrix);

         // now apply a nice clipping region to the control's graphics object so that
         // all subsequent render related operations will clip appropritely
         e.Graphics.SetClip( p );
   }
   catch( &lt;bleh&gt; )
   {
   }

   // ******* now render your control using whatever means you want, just make sure that
   // you do not reset the clipping path - if you need to clip additional client-relative
   // areas, use a clipping combine mode of compliment ( or whatever that option is )
}

Hope this helps Smile | :)

Of course, based on the date of the post ( 3 years ago ), probably not LOL.

modified on Monday, February 1, 2010 12:32 PM

Re: Non-rectangular client area

Nishad S1-Feb-10 13:36

Nishad S

1-Feb-10 13:36

rnendel wrote:
Hope this helps Of course, based on the date of the post ( 3 years ago ), probably not LOL.

This solution was not applicable (at that time) I think... Smile | :)

- ns ami -

request time out

neha.agarwal279-Oct-07 22:20

neha.agarwal27

9-Oct-07 22:20

Hello all,

I have written a code for getting html code of any given link using api's .
Now what i want is when a particular page is taking more then 10 sec to get its html code a message box stating time out should be displayed. How can i do this?

Thanks in advance

Re: request time out

Nelek9-Oct-07 22:24

Nelek

9-Oct-07 22:24

You can use SetTimer (...) when the function to get the code starts, and KillTimer (...) when the function ends succesfully with the download of the code.

If the timer reachs the end of the interval, then you can code you dialogbox with the error in the message WM_TIMER.

hope it helps

Use Ctrl+Left/Right to switch messages, Ctrl+Up/Down to switch threads, Ctrl+Shift+Left/Right to switch pages.