C / C++ / MFC

li zhiyuan wrote:

printArray(a);

double DblRand()
{
	unsigned __int64 ui64Seed;
	__asm
	{
		rdtsc;
		mov dword ptr ui64Seed, eax;
		mov dword ptr ui64Seed + 4, edx;
	}
	srand((unsigned int)ui64Seed + clock());
	return (double)rand() / 32767;
}

Randor wrote:

You should seed the random number generator before each retrieval of a random number.

Randor wrote:

double DblRand()
{
unsigned __int64 ui64Seed;
__asm
{
rdtsc;
mov dword ptr ui64Seed, eax;
mov dword ptr ui64Seed + 4, edx;
}
srand((unsigned int)ui64Seed + clock());
return (double)rand() / 32767;
}

CPallini wrote:

Actually this is not true.

Randor wrote:

I think you are misunderstanding my suggestion.

Randor wrote:

I am giving the author of the question a best-practice tip on secure number generation.

cuesdean florin wrote:

That's why I SAID that I need the help of someone who DID THIS BEFORE !!!

char tempBuff[1024];
unsigned int iReq;
// REMEMBER TO INITIALISE VARS
char newBuff[1024 + sizeof(iReq)];
memcpy(newBuff, &iReq, sizeof(iReq));
memcpy(newBuff + sizeof(iReq), tempBuff, 1024);

<br />
char tempBuff[1024];<br />
unsigned int iReq;// REMEMBER TO INITIALISE VARS<br />
char newBuff[1024 + sizeof(iReq)];<br />
memcpy(newBuff, &iReq, sizeof(iReq));<br />
memcpy(newBuff + sizeof(iReq), tempBuff, 1024);

<br />
int *iptr = &newBuff[0];<br />
int iTReq = *iptr;

fantasy1215 wrote:

Can this achieve?
int *iptr = &newBuff[0];
int iTReq = *iptr;

int *iptr = (int*) (&newBuff[0]);
int iTReq = *iptr;

int iTReq = *((int*)(&newBuff[0]);

int iTReq = *((int*)newBuff);