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The little triangle with an exclamation point (not an arrow), that the file is listed in the project, but it's not found on the disk where it is expected to be. All you have to do is remove the file from the project and re-add it, if you can find it, or copy the file to where the project expects it to be.
There may be missing files that you don't know about either. For instance, under 2005, a normal Windows Form has, usually, three files associated with it, A formName.Designer.vb file, formName.resx, and formName.vb. If any of these files are missing, you'll get the little yellow triangle.
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i do it but it steal exist
and all the three file are exist in the project folder
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You're missing a file somewhere. At the top of the solution explorer window, there is a button, I think it's the second form the left, that says "Show All Files" when you have the mouse over it. Click on that button and you should be able to see exactly which files are missing.
Now, you have to check to see where the files are. You may have them, but they are probably not in the correct folder. If you open the folder that .SLN file is in, you should see something like this:
ProjectName
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+--ProjectName.sln
+--ProjectName.suo
+--ProjectName (folder)
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+--ProjectName.vbproj
+--ProjectName.vbproj.user
+--Form1.Designer.vb
+--Form1.resx
+--Form1.vb
+--bin (folder)
+--My Project (folder)
+--obj (folder)
If, for instance, you have the project files in the wrong folder, or not in a subfolder like this, but the solution file expects it, you'll get this problem.
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thanks
but i found all the files with an exclamation point is their a way to know the path of the folder becase i copy it befor this time and but it in my disk top after that the exclamation point aper
but i am sure that all the files in the right folder
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asha_s wrote: but i am sure that all the files in the right folder
The solution explorer is telling you otherwise. I've already given you the folder structure of a normal VS2005 solution. If the structure doesn't match up, you've got the files int the wrong places, or you've renamed folders when you shouldn't have. The folder names are very specific and buried in the .SLN and .VBPROJ files. The paths listed in the .SLN file are relative to the folder that contains the .SLN file. Likewise, all the paths listed in the .VBPROJ file are relative to the folder that contains the .VBPROJ file.
You have a few choices at this point.
Create a blank Windows Forms project and save it, examining the .SLN and .VBPROJ files for how the path names look, comparing them to the folder structure you see on disk. Then, compare what you've seen to what you see in your projects .SLN and .VBPROJ files.
Use the existing project and remove all the files from the solution in the solution explorer, then re-add each of your code files on disk back into the solution explorer.
Scrap this entire folder and re-copy the entire solution folder from the original source.
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thanks it work 
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Hi,
I'm using vb 2005.
I'm making a test project to try some things out but having problem that I have a DataGridViewComboBoxColumn binded to a child table and then adding that column to a DataGridView. The column doesn't show the data from the child table until I tripple click the column. The data is the correct data though.
Details:
I have three tables that are related.
Parent table called Customers table with cust_id as PK
Orders table with order_id and foreign key being cust_id
Prices table with FK of order_id.
This is the code I used to bind the DataGridViewComboBoxColumn
Dim priceComboBoxColumn As New DataGridViewComboBoxColumn<br />
<br />
With priceComboBoxColumn<br />
<br />
.HeaderText = "price"<br />
.DataSource = priceBindingsource<br />
.DisplayMember = "price"<br />
.DataPropertyName = "price"<br />
.ValueMember = "price"<br />
.DisplayStyle = DataGridViewComboBoxDisplayStyle.Nothing<br />
.Visible = True<br />
' .DisplayStyle = DataGridViewComboBoxDisplayStyle.ComboBox<br />
<br />
<br />
End With<br />
<br />
dgOrders.Columns.Add(priceComboBoxColumn)
I have two pictures here to show what I mean
http://www.matcmp.ncc.edu/~steve/vb/
Any help would be greatly appreciated.
Thanks
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It's strange that you're using a Combo to show/pick the price of a product.
Normally, a combo is used to pick from a standard list of items where the ID of an item in the list corresponds to an ID column in another table. For example, a list of team IDs and Names in one table and a schedule table, listing two teams ID's, instead of names. The combo would show you the team names (DisplayMember), but the value (ValueMember) of each name in the list returns that teams ID. This ID would be populated into the schedule table (DataPropertyName).
For this to work you need two binding sources. One bound to the schedule data and one bound to the team data. For example, there are two BindingSources, one called MasterScheduleBindingSource, which the DataGridView is bound to is bound to a table containing the data for the schedule, and a second TeamsDataBindingSource, which will be used by the combo and is bound to a table with TeamId's and names.
Dim comboColumn As New DataGridViewComboBoxColumn
With comboColumn
' Column header that shows up in the DataGridView
.HeaderText = "Home Team"
' This is the column name in the MasterScheduleBindingSource where team ID's are going to get stored.
.DataPropertyName = "HomeTeamId"
' This is the binding for the combo to it's data
.DataSource = TeamsDataBindingSource
.ValueMember = "TeamID"
.DisplayMember = "TeamName"
End With
MyDGV.Columns.Add(comboColumn)
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I do have two binding sources.
One binding source for orders and one for prices.
I used a combobox so user can select a price from available prices but I'm open to suggestions for other controls to use.
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SteveNY wrote: I do have two binding sources.
One binding source for orders and one for prices.
Then you've got something else set somewhere or some other code you haven't shown us screwing this up for you.
SteveNY wrote: I used a combobox so user can select a price from available prices but I'm open to suggestions for other controls to use.
Normally, a textbox does this. You usually don't find a one-to-many relationship between products and prices.
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I think you're misunderstanding my problem.
It's not that the data isn't showing up. It's the fact that I have to click the column multiple times in order for the data to show up.
My code to initialize the column is the same as you've posted.
I made a separate demo app to show what I mean.
I put a datagridview on an empty form and in the form's load event I have this code:
<br />
<br />
Dim nameComboBoxColumn As New DataGridViewComboBoxColumn<br />
<br />
With nameComboBoxColumn<br />
<br />
.HeaderText = "names"<br />
.Items.Add("john doe")<br />
.Items.Add("jane doe")<br />
.DisplayStyle = DataGridViewComboBoxDisplayStyle.Nothing<br />
<br />
<br />
End With<br />
<br />
DataGridView1.Columns.Add(nameComboBoxColumn)<br />
<br />
When the app loads the data is not shown in the column until I click the column.
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SteveNY wrote: It's not that the data isn't showing up. It's the fact that I have to click the column multiple times in order for the data to show up.
I understand that. Since there isn't enough information to figure out what you did wrong, I supplied the template of how to do it right.
SteveNY wrote: I made a separate demo app to show what I mean.
I put a datagridview on an empty form and in the form's load event I have this code:
... When the app loads the data is not shown in the column until I click the column.
I can't duplicate the problem. There's something else you're doing that you haven't mentioned.
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Your example shows the expected behavior. Since the cell doesn't have a value yet (DbNull,) one isn't selected in the ComboBox.
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OK,
So how do I have the first item selected by default?
I have searched on the workaround since the dgvcmb doesn't have a selectedindex property but haven't found anything I have been able to use or haven't tried.
Thanks
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The cell has to have a value that matches a Value in the data bound to the Combo.
In your example, the default cell value is DbNull, which the data in the Combo doesn't contain. Set the value of the cell to one of the values in the Combo and the combo will show the correct item.
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try to solve the issue with the microsoft benchwork
regards,
Javed Ahmed Khan
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HELLO
I HAVE PROGRAMMED A WINDOWS FORMS APPLICATION IN VB.NET AND TAPI
THE MAIN FORM OF THE APPLICATION IS HIDE AND EVERY TIME THE TELEPHONY RINGS THE FORM APEARS FOR 10 SECS
THE PROBLEMM IS THAT THE FORM ALWAYS ACTIVE OPENS
MAINFORM.SHOW() AND THE USER HAS TO REACTIVATE THE OTHER PROGRAMM OR FORM TO CONTINIUE HIS WORK
CAN SOMEBODY TELL ME HOW TO SHOW THE FORM WITHOUT TO MAKE IT ACTIVE
THANKS A LOT
KOSMAS
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First, read the posting guidelines here[^], paying particular attention to point number 6. TYPING EVERYTHING IN UPPER CASE MEANS YOU'RE SCREAMING AT PEOPLE.
In order to show the form without activation, you'd have to call the Win32 API function ShowWindow. There's an example here[^].
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I could not test it because i had no time but thanks a lot
kosmas
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Was the Image that you're showing in the picturebox loaded from the very same file?? If so, you've run into a known issue where an Image object created using FromFile holds the original file open for the life of the Image object created from it. Read this[^] for a workaround.
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The image was loaded into the picture box after reading it as binary file from the DataBase...
The link you had given is talking about when we open a file..
Which is different from what i am doing..
Here is what all i am doing...
- Connect to DB read the file
- Display it as image in picture box
- On click of a button open save file dialog and get the new destination file name and path
- save it as image on that path
Regards
Nishkarsh
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OK, you didn't specify that in your original post.
There's a work around for this too. Basically, create your Image object from the data comming from the database, then create a NEW Image object using the first image as a source. Then you can use this copy anyway you like in your application and retain the ability to save to file.
Dim origBitmap As Bitmap ' This is the original image you created from the database
Dim copyBitmap As New Bitmap(origBitmap.Width, origBitmap.Height)
Dim g As Graphics = Graphics.FromImage(copyBitmap)
g.DrawImage(origBitmap, New Rectangle(0, 0, copyBitmap.Width, copyBitmap.Height), _
0, 0, origBitmap.Width, origBitmap.Height, GraphicsUnit.Pixel)
origBitmap.Dispose()
g.Dispose()
' The copy of the bitmap is in copyBitmap. This is the one you use in the rest of your code.
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Thanks for the input
This is how exactly i am loading the file to the picture box
Dim ar(dataLength) As Byte<br />
<br />
myReader.GetBytes(0, 0, ar, 0, dataLength)<br />
myReader.Close()<br />
<br />
Dim b As New MemoryStream(ar)<br />
<br />
picView.Image = Image.FromStream(b)
How exactly can i implement ur suggestion
Another question
Can you please explain why can i NOT directly save the image when it is already ain the picture box in this case
Regards
Nishkarsh
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