C / C++ / MFC

Roger Stoltz wrote:

Of course the hidden COM window processes COM related messages in order to received the response from the server and the HRESULT of the call.

George_George wrote:

Since it is the STA owner thread which process the message pump, so, it should not be blocked -- if blocked, how could it retrieve message pump?

George_George wrote:

And it is why the STA reentry issue exists -- STA owner thread is not blocked when making an outward call.
Please refer to section "STA Reentrancy" of the following article.

Roger Stoltz wrote:

It makes the calling thread open for COM calls which makes it reentrant from a COM perspective, but it would make a window that belongs to the calling thread non-responsive. Believe me, I have it in front of me as we "speak".

Roger Stoltz wrote:

Doesn't the article you linked to answer your questions?

int a[10];
for(x=0;x<10;x++)
{
  *str[x] = a[x];
}

#include "stdafx.h"
#include "iostream"
#include "cstring"
using namespace std;




	
int main()
{
	int x, y;
    char ppl[5][80];
	
	for(y = 0; y < 5; y++){
	    gets_s(ppl[y]);
	}

	for(x = 0; x < y; x++){
			cout << ppl[x] << "\n";
	}
	
	int a[5];
	for(x = 0;x < y; x++){  
		*ppl[x] = a[x];
	}
	
	for(x = 0;x < y; x++){
			cout << a[x] << "\n";
	}

	



		    


		return 0;
}

toprogramminguy wrote:

for example if you want to display the strings showing what their values are.

toprogramminguy wrote:

cout << ppl[x] << "\n";

toprogramminguy wrote:

int a[5];

sprintf(str[i],"%d",a[i]);//#include "stdio.h"
//sprintf(str[i],"%c",a[i]);

#include <string>//not <string.h>
     using namespace std;
     string str1,str2;
     str1 = "this is my first string.";
     str2 = "this is my second string."
     cout<<str1<<endl;
     cout<<str2<<endl;