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we faced the same problem long ago and we solved it by taking a circular queue.
btw, are you doing all theze in user mode or in kernel mode.
the thread which reads the data from a pci card puts it into a queue and another thread takes the data from the queue and writes it to a file.
since RAID supports upto 300mbps, when the system is busy, the data will get accumulated inthe queue and when the system has come out of the busy mode, the data will get vacated from the queue.
but be careful.
you should use proper synchronization mechanisms between threads.
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thanks.
chandu.
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It's not WriteFile. It's the fact that you do not have 100% of the system to yourself all the time.
BTW - what's the real write speed of your disks? Your write speed will fill the buffer in 1.3 seconds - how long does it take to flush the buffer to disk?
Othe ravenues to investigate - scatter/gather IO[^], asynchronous IO[^]. Also - what happens if you let the system buffer your IO? It's possible that Windows could help you achieve your requirement of averaging of 150MB/s.
Java, Basic, who cares - it's all a bunch of tree-hugging hippy cr*p
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Q:what's the real write speed of your disks?
A:The speed is no less than 150MB/S.
Q:how long does it take to flush the buffer to disk?
A:When I receive data,I will write them to file at once.The buffer is visited by two threads:one reads and one writes.
Asynchronous IO may lose data.
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denghp wrote: Q:what's the real write speed of your disks?
A:The speed is no less than 150MB/S.
That may be true on average, when it's able to write sequentially. However, when some other process needs to read or write with the disk, you are going to get a lot slower performance. The other read/write will likely require the head to seek to somewhere else on the disk, which will take ~10ms, then seek back to your file (another 10ms) before starting to write again.
Is the RAIDed partition used purely for writing your data? If not, I'd alter your system so it does work that way (i.e. get a separate disk for Windows, your programs, data etc).
denghp wrote: Q:how long does it take to flush the buffer to disk?
I meant the buffer(s) in hte RAID controller/hard drive controllers. Never mind.
denghp wrote: Asynchronous IO may lose data
Really. Got proof for that assertion?
Java, Basic, who cares - it's all a bunch of tree-hugging hippy cr*p
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Try to alter the buffer size, bigger is not always better! It depends on various factors like the controller, hard drive, etc.
Also, for copying large files the flag FILE_FLAG_SEQUENTIAL_SCAN can make quite a difference.
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HI,,, i got a garmin 18x usb device and using the sdk I am able to get the gps data lat/lon. now i want to plot this gps data on to my own gps map i dont have any gps map, so is it possible to create so that i can plot the data in it.from some tutorials i got the codes for plotting it in google map which i did already. i just want to make it work on my own map of my town..plz help.
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sure you can do that.
but answer these.
1.is your town visible on googleearth?
2.are you using visual c++?.
3.if yes, are you aware of device context and drawing routines? like moveto and line to.
if you can answer these, then i can help you out how to achieve your task.
FYI: i have worked on the same.
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thanks.
chandu.
modified on Friday, June 19, 2009 2:58 AM
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thankyou for your response... the answers
1. yes my town is visible in googleearth
2.yes i am suing vc++
3. yes i am aware of these stuff but didnt worked on it, but i am sure i can work on it with your help..
thank you once again...
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cool,
now take a sample of longitude and latitude.
for example, 78d32m24.88s 17d33m24.21s
now convert these into intregers like
78*60*60*100+32*60*100+24*100+21
--------------------
on the other side,
now your aim is to draw your town map on your screen right?
now you should try to get the digital data related to your town.
this can be obtained in several ways. we will decide which would be easier for you at your circumstances.
first go to google earth and note the longitude and latitudes of the bounding rectangle of your town.
ootherwise you assume them approximately.
let me know them and we shall proceed further
if any doubt in what i tried to explain, please be comfortable.
ans also let me know how much time you have with you. i mean dead line?
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thanks.
chandu.
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ok hope u had a great lunch...
here is my latitude and longitude from google earth.
25d16min16.10secN and 55d18mi26.95secE
so when i convert it into integers
25*60*60*100+16*60+100+16*100+10= 9097610
55*60*60*100+18*60*100+26*100+95= 19910695
my deadline is on july second week.
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fine then.
could u not find the bounding rectangle of your town.
to find it, just draw a virtual rectangle around ur town in GE (ggl erth)
take the longi and lati of the top left corner of the rect and bottom right corner of the rect.
parallelly, experiment drawing a rectangle(0,0,700,700) on your screen and lines 0,0 to 100,100 to 100,150 to 150,200. if you are stuck up, let me know i shall help u.
gpsmercato wrote: my deadline is on july second week.
far more than sufficient.
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 well ...ya it took long time..actually i went for friday prayer in between......
ok so rectangle with the lines done.
in GE the values are 25d17m28.90sc & 55d18m31.07sec
25d11m32.57sec & 55d24m17.68sec
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can you convert these into integers for me please.
make it quick.
25d17m28.90sc & 55d18m31.07sec
25d11m32.57sec & 55d24m17.68sec
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thanks.
chandu.
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9104890 and 19911100.7
9069257 and 19945768
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plz verify them that .7 is not supposed to come.
and also write a function which will convert ge format to int(pix) format.
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thanks.
chandu.
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sorry the value is 19911107.
function to convert ge format? u mean radian to degree format?
if so then ok. done
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no man,
some function like
int ConvertGratitoPix(int d,int m,int s,int sf)
{
return d*60*60*100+m*60*100+s*100+sf;
}
here graticule in general means latitude and/or longitude.
pix refers to an integer.
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thanks.
chandu.
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so, your towns bounds are as follows.
top-9104890 and left-19911107
bottom-9069257 and right-19945768
now, the width of your town is
19945768-19911107=34661
and height is
9069257-9104890 =-35633
temporarily we will ignore the - sign for height. theresult would be reversed display of the map. we will correct at the end.
finally,
width=34661
and
height=35633
did you understand till here.
if so i shall proceed further otherwise ask ur doubt.
be quick.
--------------------------------------------
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thanks.
chandu.
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good.
now
width=34661
and
height=35633
it is evident that, if we draw the abovepattern, it will be a rectangle, not a square.for our convinience we want to make it a square.
so out of width and height, which is more?
obviously height.
so we will subtract
height-width=35633-34661
=972.
means width is 972 units less than height.
so if we adjust 972/2 units to the left and 972/2 units to the right of our original rectangle, then it would become a square.
now, i want you to explain those caluculations for me.
do it fast.
--------------------------------------------
Suggestion to the members:
Please prefix your main thread subject with [SOLVED] if it is solved.
thanks.
chandu.
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