ASP.NET

24-Sep-09 2:36

Not sure about the ASP.NET menu, but there are third party menus that do this http://demos.telerik.com/aspnet-ajax/menu/examples/functionality/righttoleft/defaultcs.aspx[^]

only two letters away from being an asset

Hi, I need help !!!

_ASPAle_24-Sep-09 2:03

Re: Hi, I need help to view image on a datalist control.

24-Sep-09 2:03

Hi, sorry for my bad english, but I'm italian xD!

However,

At this link there is an image that explain you what I want to do.(first look at it!!!)

Link The foto!!

I want when I click on a row of gridview, send me to another page that do see the detail of what I clicked.
For example if I click on the picture of "Alfa Romeo", I must see the detail of the car in another gridview in another page.
The path of the photos is stored in the database in the field 'FotoEsterno'.

Someone can help me?

Nisha Agrawal24-Sep-09 2:10

Nisha Agrawal

24-Sep-09 2:10

for that u have to handle RowDataBound and SelectedIndexChanged Events. Below is the code

protected void gvItems_SelectedIndexChanged(object sender, EventArgs e)
{
         Response.Redirect("ToPage.aspx?SelectedItemId=" + gvItems.SelectedDataKey.Value)
}

protected void gvItems_RowDataBound(object sender, GridViewRowEventArgs e)
{
            if(e.Row.RowType==DataControlRowType.DataRow)
            {
                e.Row.Attributes.Add("onclick", ClientScript.GetPostBackEventReference(this.gvItems, "Select$" + e.Row.RowIndex));
            }
}

Now at ToPage.aspx u have the Id of the Selected Item so you can display the data related to that item as you want to display.

Re: Hi, I need help to view image on a datalist control.

Not Active24-Sep-09 2:16

Re: Hi, I need help to view image on a datalist control.

24-Sep-09 2:16

Waste of time doing a Response.Redirect from a postback event, just use a Hyperlink column.

only two letters away from being an asset

sashidhar24-Sep-09 2:25

Re: Hi, I need help to view image on a datalist control.

24-Sep-09 2:25

Mark Nischalke wrote:
Waste of time

Yes He is right Try to use ItemTemplate as Mark suggests

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Nisha Agrawal24-Sep-09 2:28

Nisha Agrawal

24-Sep-09 2:28

But the original requirement was to able to click on datarow not any control in the gridview row. thats why i have prvovided that code. please read the requirement carefully.

Re: Hi, I need help to view image on a datalist control.

Not Active24-Sep-09 2:33

Re: Hi, I need help to view image on a datalist control.

24-Sep-09 2:33

Nisha Agrawal wrote:
please read the requirement carefully.

Please look at all of the requirements. The image clearly shows and says the OP want to click on a LINK

only two letters away from being an asset

Nisha Agrawal24-Sep-09 3:00

Nisha Agrawal

24-Sep-09 3:00

yes, it's my mistake. I just followed the words that were written in the main post and ignored the one in the image.

Re: Hi, I need help to view image on a datalist control.

_ASPAle_24-Sep-09 7:04

Re: Hi, I need help to view image on a datalist control.

24-Sep-09 7:04

Ok, it works, because when I click the link, it has this value
"http://localhost:3849/progetto/visualizza.aspx?IDModello=24," but now to see the data, including other photos in the DataList , how should I proceed?

sashidhar24-Sep-09 7:30

Re: Hi, I need help to view image on a datalist control.

24-Sep-09 7:30

_ASPAle_ wrote:
but now to see the data

Can You please explain in detail.I didnt get Your point.
Depending upon the IDModello You can present the data .If You want to access the previous data provide a link.
If You want to See all the other photos Provide a next button or image slider.If that is the case use the below links it may help.
http://www.asp.net/AJAX/AjaxControlToolkit/Samples/SlideShow/SlideShow.aspx[^]
http://aspnet.4guysfromrolla.com/articles/070704-1.aspx[^]
http://aspnet.4guysfromrolla.com/London/[^]

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_ASPAle_26-Sep-09 1:07

26-Sep-09 1:07

"IDModello" is a sql int variable.

When I click on the gridview (see the image I posted),I want to appear a DataList with only the data that I want to ... not all!

Not Active24-Sep-09 2:18

24-Sep-09 2:18

Use a Hyperlink column or a Template column to place the link in the grid

only two letters away from being an asset

sashidhar24-Sep-09 2:18

24-Sep-09 2:18

<ItemTemplate>
                           <asp:LinkButton ID ="LinkButtonemp" CausesValidation="false" Text='<%# Eval("EmployeeName") %>' runat="server" CommandArgument='<% #Eval("EmployeeID")%>' CommandName="View" CssClass="gridlnk"/>
                        </ItemTemplate>

Append the name/ID to the querystring and redirect it to another page say InfoPage.aspx.In info page Request the query String .With the Help of Query String Get the Data in the InfoPage.aspx.

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S.Dhanasekaran24-Sep-09 2:22

S.Dhanasekaran

24-Sep-09 2:22

Hi,

do changes in frist column(Viewdetails)

<asp:HyperLink ID="hypTitle" NavigateUrl='<%#"secondpage.aspx?pid="+DataBinder.Eval(Container.DataItem,"picid")%>' Text='<%#DataBinder.Eval(Container.DataItem,"picturename") %>' runat="server" ></asp:HyperLink>

when click the viewdetails column, i pass Querystring("pid") value of current picture.

On second page, get value from querystring("pid"), using to display the picture.

sashidhar24-Sep-09 2:26

24-Sep-09 2:26

Good Answer But Try to use pre tags i.e. code block so he can understand easily Cool | :cool:

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_ASPAle_24-Sep-09 2:41

Re: i found error 500 on ie

24-Sep-09 2:41

Thank you guys!!!

i found error 500 on ie

mauji24-Sep-09 1:25

mauji

24-Sep-09 1:25

hi all...

plz help me i found error 500 on my web application.
plz somebody help me.

thanx in advance
maujiram

sashidhar24-Sep-09 1:28

[Solved]Confirmation Box Problem [modified]

24-Sep-09 1:28

Try this Link It May Help..!
http://pcsupport.about.com/od/findbyerrormessage/a/500servererror.htm[^]
http://support.microsoft.com/kb/822319[^]

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nagendrathecoder24-Sep-09 0:33

nagendrathecoder

24-Sep-09 0:33

Hello All,
In my ASP.Net application, i am showing a confirmation box using javascript whenever user intends to delete something.
I have written this code in aspx file

function confirmation()
{
if(confirm("Are you sure?")==true)
return true;
else
return false;
}

Then on Page_Load of my codebehind, i am using this:

btnDelete.Attributes.Add("onclick", "return confirmation();")

It is working fine, if user click ok record is deleting and vice versa.

But when i am trying to write same thing for my GridView delete link its not working, i am writting this:

GridView1.Attributes.Add("OnRowDeleting", "return confirmation();");

Can anybody help me? why its not working for GridView_RowDeleting method?

Thanks,
Nagendra.

modified on Thursday, September 24, 2009 7:06 AM

Christian Graus24-Sep-09 0:36

Christian Graus

24-Sep-09 0:36

nagendrathecoder wrote:
function confirmation()
{
if(confirm("Are you sure?")==true)
return true;
else
return false;
}

This is messy as hell. Why not just return (confirm("Are you sure?")) ? Why not tell them what they are to be sure if, in case they don't realise what they pushed ?

nagendrathecoder wrote:
GridView1.Attributes.Add("OnRowDeleting", "return confirmation();");

I'd guess that it's because you're trying to hook up to a code behind event, not an actual client side event. You could start by reading on the difference between the client and server.

Christian Graus

Driven to the arms of OSX by Vista.

Read my blog to find out how I've worked around bugs in Microsoft tools and frameworks.

nagendrathecoder24-Sep-09 0:51

nagendrathecoder

24-Sep-09 0:51

Thanks, i implemented what u mentioned(used just confirm & displaying proper msg). Smile | :)

I also understand that RowDeleting is server side event and onclick is client side.
But i want this functionality to work for GridView too, what can i do?

sashidhar24-Sep-09 0:53

24-Sep-09 0:53

try to add itemtemplate in gridview and do it

<ItemTemplate>

                       <asp:LinkButton ID="Delete" CommandName="Delete"
                       OnClientClick="return confirm('Are you sure you wish to delete this item?')"
                       CausesValidation="false"
                        runat="server" Text="Delete" ></asp:LinkButton>
                   </ItemTemplate>

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