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i am now able to validation textboxes when the textboxes is null a error message will appear.
Right now if the user enter the number 20 and he or she wants to add the number 20 again, an error will occour.
how do i achieve tt?
i tried google however have no clue on how to strt.
Needing help..
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Assuming you've split your code into MVC (Model, View and Controller) - and of course you did so 
You will store the data somewhere in a object. For this you're using a set-methode.
This is a typical moment for checking integrity of the value:
public void setIValue(final int iValue){
if(null != iValue && 0 < iValue && 100 > iValue){
this.iValue = iValue;
}
else{
}
}
or you do delegate this validation to another class(when pushing some "OK"-button) or even your textbox itself (write an extension and trigger on lost of focus or keystroke(can become strange if validation takes to long)).
regards,
Torsten
I never finish anyth...
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pancakeleh wrote: i tried google however have no clue on how to strt.
I already gave you a link to the Java tutorials. I suggest you spend some more time going through them, especially the areas that you are having difficulty with.
Just say 'NO' to evaluated arguments for diadic functions! Ash
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Hi, i am trying to connect to MySQL database mysql using JAVA .. using code given below,
import java.sql.*;
public class dbExample{
public static void main(String[] args) {
System.out.println("Listing all table name in Database!");
Connection con = null;
String url = "jdbc:mysql://localhost:3306/";
String db = "mydb";
String driver = "com.mysql.jdbc.Driver";
String user = "root";
String pass = "root";
try{
Class.forName(driver);
con = DriverManager.getConnection(url+db, user, pass);
}
catch (Exception e){
e.printStackTrace();
}
}
}
I've picked this example from internet .. and there lot more example i tried using this same driver String driver = "com.mysql.jdbc.Driver"; But this code all other i tried gives me error Driver Class not found ... at this statment Class.forName(driver); ..... and similarly on trying this driver sun.jdbc.odbc.JdbcOdbcDriver the above mentioned statment Class.fonName ... executes but then it gives error on statment con = DriverManager.getConnection(url+db, user, pass); error is No suitable drive found for jdbc:mysql://localhost:3306/mydb
I'm very much confused and tried it toooooo many time in diffrents ways that i could but still unable to create successfull database connection.
I've tried this using notepad / Netbeans both and both on WINDOWS7 and XP ... and both give same error to me .... 
Please Please PLease give me any solution .... I shell be very very Thanksfull to you.
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Ok Thanks you ver much ....... Problem solved by adding MySQL.jar to Library.
THanks a lot ...
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i have added a delete button on the table that i have created to allow user to delete values straight from the table and the database will then be updated. however when i try to run the program an error incurred.
Error: java.lang.IllegalArgumentException: unrecognized virtual form name: addIncidentStatus
my code as follows:
public String Del_btn_action() {
form1.discardSubmittedValues("addIncidentStatus");
try {
RowKey rk = tableRowGroup1.getRowKey();
if (rk != null) {
incidentStatusDataProvider.removeRow(rk);
incidentStatusDataProvider.commitChanges();
incidentStatusDataProvider.refresh();}
} catch (Exception ex) {
log("ErrorDescription", ex);
error(ex.getMessage());
}
return null;
}
By the way the "addIncidentStatus" is a function in the sessionbean.
May i know what went wrong?
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Hello i have no idea if i should post it at the java forum pr the database forum, pardon me if i post it at the wrong forum. i am currently using netbeans, javadb and glassfish for my project and right now i created a table that allow user to insert values into the database.
The table contains of 2 attributes a ID and Name.
Problem : http://img827.imageshack.us/img827/673/helpnb.png[^][^]
when the user try to add a 24 again as the ID an error page will popup. how do i create a message instead of the error popup?
error popup page : http://img824.imageshack.us/img824/1426/errorye.png[^]
Needing help.
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pancakeleh wrote: how do i create a message instead of the error popup?
Catch the exception[^] and deal with it.
Just say 'NO' to evaluated arguments for diadic functions! Ash
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You need to handle the exception and then display your customize message box as your requirement.
take a look there[^] for getting more details about Exception.
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i have this particular line in my program however when i execute this line it gives me error.
Integer addIncidentID = (Integer) getIncidentidtxt().getValue();
how do i convert from string to integer?
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Of course you can't cast a String to an Integer, they are two completely unrelated types. You have to use the Integer.valueOff(String s) method:
Integer addIncidentID = Integer.valueOff(getIncidentidtxt().getValue());
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// to primitive int i from Integer Object ii
int i = ii.intValue();
// to Integer ii from primitive int i
Integer ii = new Integer( i );
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this is a static method of the type Integer:
int iValue = Integer.parseInt(givenString);
This one throws an exception when converting fails. So best is to wrap in a try/catch:
int iValue=0;
try{
iValue = Integer.parseInt(givenString);
}
catch(NumberFormatException oException){
}
regards,
Torsten
I never finish anyth...
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can i use interger.parseint?
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that's kind of the one I mentioned - if "interger" is just a typo and is supposed to be "Integer".
see post above your post.
regards
Torsten
I never finish anyth...
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Please, check the javadoc !
Yes you can use parseInt but it returns an int, not an Integer. So, depending on your needs, either use valueOf or parseInt.
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pancakeleh wrote:
how do i convert from string to integer?
you can convert string to integer by using various ways
you can use valueOf method of Integer class in this way
Integer obj = Integer.valueOf(str_value);
you can use Integer Constructor
Integer obj = new Integer(str_value);
you can use parseInt method
int objt = Integer.parseInt(str_value);
for more details move there[^]
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For Example:
String abc123 = "123";
Integer abcint = Integer.valueOf(abc123);
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int int_page_id=o;
String str_page_id="5";
try {
int_page_id = Integer.parseInt(str_page_id);
} catch(NumberFormatException ex) {
ex.printStackTrace();
}
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String a="2";
int value = Integer.parseInt(a);
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Hey!
I need to save some properties encrypted. So I have a key and a value, which I should separate in some way with some character or symbol. The most used "=" is used in Base64 encoding and will not work.
Which characters or symbols or totally strange hieroglyphs are not used in Base64 encoding?
How can guarantee access to the properties 
Anyone ever played that game?
regards
Torsten
I never finish anyth...
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TorstenH. wrote: So I have a key and a value, which I should separate in some way with some character or symbol. The most used "=" is used in Base64 encoding and will not work.
You should be able to convert the string "bla=1" to Base64 and back, regardless of the equal-sign within that string. Did it fail, and if so, what error did it generate?
I are Troll 
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 sometimes its simpler than expected. Have I thought of doing it this way?
You're right, I could convert the complete string. Right now I'm just converting the value - this looks like "label.text=qwertzwtf==". This has the opportunity of deleting certain entries when needed. The values are not predefined, admin users (our crew) are able to add additional entries by using a dialog. Simple users (customers) should not be able to manipulate out those values(safety reasons).
I figured out (try&error) that the "@"-symbol is pretty safe, so I changed my properties to "label.text@qwertzwtf==". works like a charm so far 
regards,
Torsten
I never finish anyth...
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