C / C++ / MFC

clock_t start, end, tt;
tt = clock();
while ((start = clock()) == tt);
...begin timing test
end = clock();

#include<stdio.h>
//#include<signal.h>
//#include<conio.h>
#include<time.h>
const int MAX=1000;

int partition(int a[],int low,int high)
{
    int i,j,temp,key;
    key=a[low];
    i=low;
    j=high+1;
    while(i<=j&&key<=a[i])
    {
    i++;
    }
     while(key>a[j])
    {
    j--;
    }
     if(i<j)
    {
    temp=a[i],a[i]=a[j],a[j]=temp;
    }
      else
    {
    temp=a[low],a[low]=a[j],a[j]=a[low];
    return j ;
    }
}

void quick_sort(int a[],int low,int high)
{
    int mid;
    if(low<high)
    {
    mid=partition(a,low,high);
    quick_sort(a,low,mid-1);
    quick_sort(a,mid+1,high);
    }
}

void main()
    {
    int a[MAX],n,i,start,end;
    //clock_t end,start;
        double CLK_TCK;
    printf("enter the no of elements:");
    scanf("%d",&n);
    printf("\n enter the elements to sort\n");
    for(i=0;i<=n;i++)
    scanf("%d",&a[i]);
    start=clock();
    quick_sort(a,0,n-1);
    end=clock();
    printf("n the sorted elemetns are:\n\n");
    for(i=0;i<=n;i++)
    printf("%d\t",a[i]);
    printf("\n\n time consumed the array is: %5.2f sec: ",(end-start)/(double)CLK_TCK);
    //getch();
}

Jochen Arndt wrote:

TCP connections are based on the client-server concept. So two clients can not communicate even when in the same network segment.

Jochen Arndt wrote:

both systems are probably behind routers using NAT

Erudite_Eric wrote:

That is what we need to establish. If so, then he is into a more complex design. But it is possible that all he needs to do is open a few ports on the firewall.

 

Erudite_Eric wrote:

OK, I admit, I reacted to the terminology you used, understanding it to mean something else so I will apologise for saying 'crap'.