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I just spent another 5 minutes looking for it, and just caught it.
nice job dusty!
[edit]
Oh, I copied the mistake into my code sample, even worse!, oh well
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I’m trying to get my website to show images one after the other using java script I got from www.javascriptkit.com/howto/show2.shtml and have followed there example as closely as I can but with no luck.
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<title>Acrele - Home</title>
<meta name="keywords" content="" />
<meta name="description" content="" />
<link href="CSS1.css" rel="stylesheet" type="text/css" />
<script type="text/javascript">
var image1=new Image()
image1.src="16.jpg"
var image2=new Image()
image2.src="employee-training.jpg"
var image3=new Image()
image3.src="Real_Estate_Investment_Education.jpg"
var image4=new Image()
image4.src="Unti2tled.jpg"
var image5=new Image()
image5.src="Untitled.jpg"
var image6=new Image()
image6.src="zclassroom.jpg"
</script>
</head>
2. Added the html code were I want the image to show:
<div id="left-feature-colum">
<div id="slider-bg">
<div id="slider">
<img src="16.jpg" id="slide" width="600px" height="300px">
</div>
</div>
</div>
3. Edited there javascript accordingly to the number of images I’m using:
<div id="left-feature-colum">
<div id="slider-bg">
<div id="slider">
<img src="16.jpg" id="slide" width="600px" height="300px">
<script>
var step=1;
var img = document.getElementById('slide');
img.src = "image" + step + ".src";
console.log(img.src);
if (step < 6) step++;
else step = 1;
setTimeout(slideit, 3500);
</script>
</div>
</div>
</div>
This isn’t working, it only load the first image “16.jpg” only…Help
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You have removed the code from inside the "slideit" function, so now there is no way for it to repeat and the setTimeout(slideit, 3500) is trying to call a function that doesn't exist.
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There are a lot of bad slideshow scripts out there, I rewrote one that was a CMS plugin for word press which had many errors in it, and made no sense to me. It might be too advanced for you, and requires JQuery, but is simplistic in design.
[Display Advertising Filmstrip^]
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you must use setinterval...
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Your profile is not active so I'm can not know your name. I have a question ..
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I have my account back now.
Also changed my profile to allow email replies.
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan
That's what machines are for.
Got a problem?
Sleep on it.
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<html>
<head>
<script type="text/javascript">
var rec = ["19","20","21","40","41","45","12","23","34","36","37","46"]
document.write("Weekly records for 2 week : ");
for(var i=0; i<12; i++) {
document.write(rec[i] + ",");
}
document.write("<BR>");
for(var z=0; z<6; z++) {
var q = Math.round(12 * Math.random());
document.write(rec[q], + "," + z);
}
</script>
</head>
<body>
</body>
</html>
I wrote a simple random permutations, but May Have NaN Error Can help me with this?
modified 25-Mar-13 3:23am.
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Off by one error - range of random 0-12, valid range for Array 0 - 11
Removed an unwanted comma (,) after rec[q] in your document write.
<html>
<head>
<script type="text/javascript">
var rec = ["19","20","21","40","41","45","12","23","34","36","37","46"];
document.write("Weekly records for 2 week : ");
for(var i=0; i<12; i++) {
document.write(rec[i] + ",");
}
document.write("<BR>");
for(var z=0; z<6; z++) {
var q = Math.round(11 * Math.random());
document.write(rec[q] +", "+ z +" ");
}
</script>
</head>
<body>
</body>
</html>
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan
That's what machines are for.
Got a problem?
Sleep on it.
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Well.. now how do i prevent adding the numbers of array elements value, array elements only among themselves, I just wanted to combine random..
Output is:
19, 0 23, 1 20, 2 19, 3 34, 4 45, 5
it must be:
19, 23, 20, 19, 34, 45
Why does it wrote the numbers of random array and how do i prevent the same number selection..¿
Quickly remove the shameless
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I have to special thanks for all ur helps.
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Well you aren't putting the (value of) the z variable into the array. Only showing its value.
remove the
+ z +" " from document.write
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan
That's what machines are for.
Got a problem?
Sleep on it.
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I tried the following lines at least.. have you got an idea about this statement?
document.write("<BR><BR>" + "Combination is :" + "<BR>");
do(q) { z += 1;
var q = Math.round(Math.random()* 11);
if(q==q) {return q;}
document.write(rec[q] +", "+ z);
} while(z==6);
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Is there something to way some simple code to do this?
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replace with this.
<script>
var taken = new Array(49);
for (var i=49; i>0; i--) taken[i]=false;
var lucky = [];
var rec = ["19","20","21","40","41","45","12","23","34","36","37","46"];
document.write("Weekly records for 2 week : ");
for(var i=0; i<12; i++) {
document.write(rec[i] + ",");
}
document.write("<br><hr>");
var z=0;
do {
var q = Math.round(11 * Math.random());
if(!taken[ rec[q] ]) {
lucky[z] = rec[q];
taken[ rec[q] ] = true;
document.write(lucky[z] + "<br>");
z++;
}
} while (z < 6);
</script>
this line:
if(!taken[ rec[q] ]) checks if NOT taken (! = not)
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan
That's what machines are for.
Got a problem?
Sleep on it.
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Excellent code thanks a lot.
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Just letting you know what your errors here are. See my other post for new code.
do(q)
can't use expressions at the top of do loop *(q)*, just use
do {
z is not declared with var *and* initialised with a value. var z = 0;
z +=1;
you don't need the { } braces for a single statement..
if(q==q) return q;
but, q==q just evaluates to true so you might as well have just written this
return q;
I am not able to reply very quickly. On a training course for another 10 days. Be patient.
Please keep trying to write new code as it is easier for me to guess what you are doing. 
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan
That's what machines are for.
Got a problem?
Sleep on it.
modified 25-Mar-13 18:05pm.
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Finally, ask you for anything more in a array of 12 elemented to 49 membered Argument want to match, you can also help me in this topic? JavaScript writing is so hard really. Thank you for your help.
I tried the following lines:
var arrNumbers = [49];
var arrOutside = [];
var arrInside = ["19","20","21","40","41","45","12","23","34","36","37","46"];
var z=0;
for(var i=0; i<12; i++) { arrInside[i]=false; }
for(var j=49; j>0; --j)
{
arrNumbers[j]=j;
if(arrNumbers[j] != arrInside[i]) {
document.write(arrNumbers[j]=arrOutside[z], + ", ");
arrInside[i] = true;
z++;
}
}
if this is what special things I did not want to deal with it..
I do not want to discuss whom it is could not be shy
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Please explain what inside & outside mean.
inside what?
outside what?
arrNumbers = [49]; // array length = 1 ???
I'm guessing this is what you intended
arrNumbers = new Array(49);
Also, you can't assign (=) inside of document.write()
arrOutside[j]=j
arrNumbers[j] = arrOutside[z]
did you mean to show arrNumbers and arrOutside, or copy from one to another?
this does not make sense.
arrNumbers[j] && arrInside[i] = true;
What other programming language do you know?
Because, it might be easier if you write your code in a computer language that you are familiar with.
I will be able to figure it out.
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan
That's what machines are for.
Got a problem?
Sleep on it.
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It flags to the 49 numbers of numeric lotto arrInside is the numbers two week of and arrOutside is other numbers of 49 that is The number 49 is the number of remaining ..previously worked on the platform of Visual C++ 6.0.. I am thinking you are right JavaScript language is not completely literal a language because of it's called name as script ...
arrInside arrOutside are instead of lucky or unlucky they may also like the your previous thread is to be
modified 28-Mar-13 3:23am.
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Hi All,
I am not able to read xml from HTTPS(Secure) server to HTTP server using JavaScript. it is working perfectly if XML is available on same server but not from other server. Frown | 
It seems Crossdomain issue.
Could anyone please help me out what technology need to use.
I heard with the help of JSONP but don't have much idea about it.
Please help me on it.
Thanks in Advanced.
Regards,
Satyam
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[sniff, sniff] It smells like double-posting sock puppets in here... 
Soren Madsen
"When you don't know what you're doing it's best to do it quickly" - Jase #DuckDynasty
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They were difficult to catch, weren't they  ?
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Oooohh... I smell more sock puppets...
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Hi All,
I am not able to read xml from HTTPS(Secure) server to HTTP server using JavaScript. it is working perfectly if XML is available on same server but not from other server. 
It seems Crossdomain issue.
Could anyone please help me out what technology need to use.
I heard with the help of JSONP but don't have much idea about it.
Please help me on it.
Thanks in Advanced.
Regards,
Satyam
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