Java

try{
//code that causes the exception
}catch(SocketException e){
   Sytem.err.println(e);
}

Indian Coder1989 wrote:

I want to create a server socket(TCP) in which I want that server shouldn't be
closed if
client is closed.

import java.io.PrintWriter;
import java.net.ServerSocket;
import java.net.Socket;

public class Test {
    public static void main(String[] args) throws Exception {
        ServerSocket server = new ServerSocket(888);
        while(true) {
            Socket s = server.accept();
            Processer p = new Processer(s);
            Thread t = new Thread(p);
            t.start();
        }
    }
}

class Processer implements Runnable {
    private Socket socket;
    
    public Processer(Socket s) {
        // TODO Auto-generated constructor stub
        this.socket = s;
    }
    @Override
    public void run() {
        try {
            PrintWriter out=new PrintWriter(socket.getOutputStream(),true);
            out.println("HTTP/1.0 200 OK");
            out.println("Content-Type:text/html;charset=utf-8");
            out.println();
            out.println("<h1> web service test sucess！</h1>");
            out.close();
        } catch(Exception ex) {
            ex.printStackTrace();
        } finally {
            try {
                socket.close();
            } catch (Exception e) {
                e.printStackTrace();
            }
        }
        
    }
}

HopePerson wrote:

I am stuck