Java

LawlessBaron8-Aug-13 22:15

8-Aug-13 22:15

toString because un and pw are EditText

Richard MacCutchan8-Aug-13 23:09

8-Aug-13 23:09

Java

String response = null;
try {
    response = CustomHttpClient.executeHttpPost("http://www.domain.com/Launcherloginaccount.php?username="+ userName +"&password="+ passWord +"", postParameters);
    String res = response.toString();

response is already a String.

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LawlessBaron11-Aug-13 2:28

11-Aug-13 2:28

Been fixed i just need help with logging into an XML array and having it display the data

Richard MacCutchan11-Aug-13 2:42

11-Aug-13 2:42

Member 10160291 wrote:
logging into an XML array

What does that mean?

Use the best guess

LawlessBaron11-Aug-13 3:27

11-Aug-13 3:27

<account>
<user>
<Username>Error</Username>
<Cash>Error</Cash>
<Bank>Error</Bank>
<Job>Error</Job>
<Inventory/>
<Weapons/>
<Role>Error</Role>
<Holster>Error</Holster>
<Bag>Error</Bag>
<Jail>Error</Jail>
<Playtime>01:36:01</Playtime>
<DOB>1/1/2000</DOB>
<licences/>
<skills>
<Strength>0</Strength>
<Mining>0</Mining>
<Vehicle>0</Vehicle>
<Gathering>0</Gathering>
<Air>0</Air>
<Unit>0</Unit>
</skills>
</user>
<vehicles>
<vehicle>
<key>Error</key>
<storage>True</storage>
<cost>Error</cost>
<sell>Error</sell>
<tuneup>Error</tuneup>
<turbo>Error</turbo>
<lowjacksell>Error</lowjacksell>
<alarm>Error</alarm>
<plate>Error</plate>
</vehicle>
</vehicles>
<shops>
<shop>
<name>Error</name>
<stock>[["Stock",0]]</stock>
<takings>Error</takings>
<value>Error</value>
</shop>
</shops>
<crimedatabase>
<log>
<citizen>Error</citizen>
<reporttype>PR</reporttype>
<crimes>
<crime>
<ticket>Error</ticket>
<suspect>Error</suspect>
<records/>
</crime>
</crimes>
</log>
</crimedatabase>
<dmv>
<vehicleonmap>
<log>
<vehicle>
<id>0</id>
<owner>Error</owner>
<key>Error</key>
<plate>Error</plate>
</vehicle>
</log>
</vehicleonmap>
<vehiclestorage>
<log>
<vehicle>
<id>0</id>
<owner>Error</owner>
<key>Error</key>
<plate>Error</plate>
</vehicle>
</log>
</vehiclestorage>
<licencelist>
<log>
<Player>Error</Player>
<DriverLic>0</DriverLic>
<BoatLic>0</BoatLic>
<PilotLic>0</PilotLic>
<PistolLic>0</PistolLic>
<RifleLic>0</RifleLic>
<MotorLic>0</MotorLic>
<Passport>0</Passport>
<TruckLic>0</TruckLic>
</log>
</licencelist>
</dmv>
</account>

Richard MacCutchan11-Aug-13 3:39

11-Aug-13 3:39

You really need to spend some more time writing down a detailed explanation of your problem. The listing of some XML on its own means absolutely nothing.

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LawlessBaron11-Aug-13 3:47

converting problem from cmyk to rgb image

11-Aug-13 3:47

The issue is i have a login system all worked out i just need it so once a user has logged in they can they be taken to the formatted XML Array with all the users data to display for interest

The issue that im having is being able to have the XML generate on login

Shankar nehrumaharajan7-Aug-13 3:21

Shankar nehrumaharajan

7-Aug-13 3:21

Hi,

i want to convert a cmyk type image into RGB Image.
if i use the below code the conversion happens but the image is not displaying properly.i can see block strike-through codes in my output image. any other way to convert CMYK to RGB.

Java

java.util.Iterator<ImageReader> readers = ImageIO.getImageReadersByFormatName("JPEG");
               ImageReader reader = null;
               while(readers.hasNext()) {
                   reader = (ImageReader)readers.next();
                   if(reader.canReadRaster()) {
                       break;
                   }
               }

               //Stream the image file (the original CMYK image)
               ImageInputStream input =   ImageIO.createImageInputStream(fromFile);
               reader.setInput(input);

               //Read the image raster
               Raster raster = reader.readRaster(0, null);

               //Create a new RGB image
               BufferedImage bi = new BufferedImage(raster.getWidth(), raster.getHeight(),BufferedImage.TYPE_INT_RGB);

               //Fill the new image with the old raster
               bi.getRaster().setRect(raster);
           System.out.println("\n\n\n   bi.getColorModel().getColorSpace().getType()\n\n "+bi.getColorModel().getColorSpace().getType());



           //  BufferedImage bi = ImageIO.read(toFile);
               int colorSpaceType = bi.getColorModel().getColorSpace().getType();

                if( colorSpaceType == ColorSpace.TYPE_CMYK)
                {
                    System.out.println("\n\n\n is CMYK image \n\n\n");
                }
                else if(colorSpaceType == ColorSpace.TYPE_RGB)
                {
                System.out.println("\n\n\n is RGB image \n\n\n");
                ImageIO.write(bi, "JPEG", new File("d:\\hi.jpg"));

                }

how to draw smooth curve with java?

xiaobai13795-Aug-13 17:32

xiaobai1379

5-Aug-13 17:32

how to draw smooth curve with java?

Re: how to draw smooth curve with java?

Richard MacCutchan5-Aug-13 20:48

i can't pause the song in this code

5-Aug-13 20:48

Write some code, making use of the 2D drawing library features[^].

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Member 101909835-Aug-13 8:52

Member 10190983

5-Aug-13 8:52

import java.awt.*;
import javax.swing.*;
import java.awt.event.*;
import java.io.*;
import java.awt.event.*;
import java.net.*;
import javazoom.jl.player.*;
class Myjpanel extends JPanel implements ActionListener,Runnable
{
boolean count=true;
Thread th;
JSlider js1;
JLabel jl;
private JButton jb1,jb2;
JTextField jt1;
public SoundJLayer soundToPlay;
public Myjpanel()
{
jl=new JLabel(" ");
jb1=new JButton("Open");
jb2=new JButton("Stop");
jt1=new JTextField(20);
js1=new JSlider(1,100);
add(jt1);
this.add(jb1);
this.add(jb2);
add(js1);
js1.setValue(0);
js1.setPaintLabels(false);
jb1.addActionListener(this);
jb2.addActionListener(this);
this.add(jl);
}
public void actionPerformed(ActionEvent e)
{
if(e.getSource()==jb2)
{
count=true;
soundToPlay.stop1();
jl.setText(" 0 : 0 ");
}
else
{
th=new Thread(this);
if(count==true)
{

JFileChooser jfc=new JFileChooser();
File f=null;
jfc.setFileSelectionMode(JFileChooser.FILES_ONLY);

int choice=jfc.showOpenDialog(null);

if(choice!=JFileChooser.CANCEL_OPTION)
{
f=jfc.getSelectedFile();
}
if(f==null)
JOptionPane.showMessageDialog(null,"You didn't select a file");
else
{
int option=JOptionPane.showConfirmDialog(null,"You selected "+f.getName()+"\nDo you want to open it?");

if(option==JOptionPane.YES_OPTION)
{
String str=f.getName();
jt1.setText(str);
soundToPlay= new SoundJLayer(f);
soundToPlay.play();
th.start();
count=false;
}
}
}
}
}
public void run()
{
int i=0;
for(;count==false;)
{
try
{
Thread.sleep(1000);
}
catch(InterruptedException ex)
{
}
double db1=soundToPlay.player.getPosition();
int db=(int)db1/1000;
js1.setValue(db);
db=db%60;
if(db==59)
i++;
String str1=String.valueOf(i);
String str=String.valueOf(db);
jl.setText(str1+" : "+str);

}
}
}
class Myjframe extends JFrame
{
private Myjpanel jp;
public Myjframe(String title)
{
super(title);
jp=new Myjpanel();
Container ct=getContentPane();
ct.add(jp);
setVisible(true);
setBounds(50,50,200,200);
setDefaultCloseOperation
(JFrame.EXIT_ON_CLOSE);
}
}
public class mymp3player2
{
public static void main(String[] args)

{

Myjframe obj=new Myjframe("Sumit's");
}
}
class SoundJLayer implements Runnable
{

public Player player;
public Thread playerThread;

private URL url;
public SoundJLayer(File file)
{
try
{

url=file.toURL();
}
catch (Exception ex)
{
ex.printStackTrace();
}
}

public void play()
{
try
{

InputStream ip=url.openStream();

this.player = new Player(ip);

this.playerThread = new Thread(this, "AudioPlayerThread");

this.playerThread.start();
}
catch (Exception ex)
{
ex.printStackTrace();
}

}

public void run()
{
try
{

this.player.play();

}
catch (javazoom.jl.decoder.JavaLayerException ex)
{
ex.printStackTrace();
}

}
public void stop1()
{
this.player.close();
}
}

Re: i can't pause the song in this code

Richard MacCutchan5-Aug-13 20:46

Re: i can't pause the song in this code

5-Aug-13 20:46

1. Pleas indent your code and put it between <pre> tags for readability, thus

Java

public void stop1()
{
    this.player.close();
}

2. Give proper details of your problem.

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Member 101909836-Aug-13 4:42

Member 10190983

6-Aug-13 4:42

when i play an mp3 file then if i want to pause that song for some time then i can't i can only play and stop the song in this code

Re: i can't pause the song in this code

Richard MacCutchan6-Aug-13 4:56

how can i solve method RequestProcessor with using thread

6-Aug-13 4:56

Rather than just repeating your original post, it would be helpful if you followed my previous suggestions. It is extremely difficult to read your code from that unformatted listing, and I cannot find a method anywhere that handles a Pause command.

Use the best guess

Two salt Values?

chdboy3-Aug-13 5:14

chdboy

3-Aug-13 5:14

I'm getting two values for my salt

This is my code

Java

private static String getSalt() throws NoSuchAlgorithmException, NoSuchProviderException
{
    SecureRandom sr = SecureRandom.getInstance("SHA1PRNG");
	//SecureRandom sr = new SecureRandom();
    byte[] salt = new byte[8192];
    sr.nextBytes(salt);    
    return salt.toString();
   
}

and when I save it in my database
my code

Java

PS.setString(1, User);		
		PS.setString(2, getSalt());
		PS.executeUpdate();		
		System.out.println(" Salt :"+getSalt());

I get different value..why?

I'm salting String asdf

 Database value [B@2fc396df 
Printed value [B@5199c9ac

Re: Two salt Values?

jschell3-Aug-13 5:18

jschell

3-Aug-13 5:18

salt.toString();

That doesn't do what you think it does. It prints the object reference not the contents.

Re: Two salt Values?

Bernhard Hiller4-Aug-13 22:32

Bernhard Hiller

4-Aug-13 22:32

By the way, your function createSalt() creates a new salt every time you call it!
When you want to compare the original value and the database value, you hat to write the salt into a variable, then set it to your object, write to database, then retrieve from the database.

Zeff Portal31-Jul-13 15:39

Zeff Portal

31-Jul-13 15:39

public void run(){
for(int i=0;i<totalThread;++i){

Thread x=new Thread(new RequestProcessor(documentRootDirectory,indexfileName));
x.start();

}

System.out.println("coonection accepted"+server.getLocalPort());
System.out.println("Dokumen root"+documentRootDirectory);

while(true){
try{
Socket request=server.accept();
RequestProcessor.startProcessing();

}
catch(IOException ex){

}
}

}

error message from this program : method RequestProcessor can't not implemented with given types,
althaugh i have create class RequestProcessor from one package, can you help me to integrated the totalThread with RequestProcessor? the error start when i try to instance new Thread.

thx.

Re: how can i solve method RequestProcessor with using thread

Richard MacCutchan31-Jul-13 21:02